Metamath Proof Explorer


Theorem rspvalint

Description: The ideal generated by a subset of a ring as intersection of ideals including the subset. (Contributed by Jeff Madsen, 10-Jun-2010) (Revised by AV, 30-Jun-2026)

Ref Expression
Hypotheses rspvalint.v ⊢ B = Base R
rspvalint.i ⊢ I = LIdeal ⁡ R
rspvalint.k ⊢ K = RSpan ⁡ R
Assertion rspvalint ⊢ R ∈ Ring ∧ S ⊆ B → K ⁡ S = ⋂ t ∈ I | S ⊆ t

Proof

Step Hyp Ref Expression
1 rspvalint.v ⊢ B = Base R
2 rspvalint.i ⊢ I = LIdeal ⁡ R
3 rspvalint.k ⊢ K = RSpan ⁡ R
4 rspval ⊢ RSpan ⁡ R = LSpan ⁡ ringLMod ⁡ R
5 3 4 eqtri ⊢ K = LSpan ⁡ ringLMod ⁡ R
6 5 fveq1i ⊢ K ⁡ S = LSpan ⁡ ringLMod ⁡ R ⁡ S
7 6 a1i ⊢ R ∈ Ring ∧ S ⊆ B → K ⁡ S = LSpan ⁡ ringLMod ⁡ R ⁡ S
8 rlmlmod ⊢ R ∈ Ring → ringLMod ⁡ R ∈ LMod
9 rlmbas ⊢ Base R = Base ringLMod ⁡ R
10 1 9 eqtri ⊢ B = Base ringLMod ⁡ R
11 10 sseq2i ⊢ S ⊆ B ↔ S ⊆ Base ringLMod ⁡ R
12 11 bilani ⊢ R ∈ Ring ∧ S ⊆ B → S ⊆ Base ringLMod ⁡ R
13 eqid ⊢ Base ringLMod ⁡ R = Base ringLMod ⁡ R
14 eqid ⊢ LSubSp ⁡ ringLMod ⁡ R = LSubSp ⁡ ringLMod ⁡ R
15 eqid ⊢ LSpan ⁡ ringLMod ⁡ R = LSpan ⁡ ringLMod ⁡ R
16 13 14 15 lspval ⊢ ringLMod ⁡ R ∈ LMod ∧ S ⊆ Base ringLMod ⁡ R → LSpan ⁡ ringLMod ⁡ R ⁡ S = ⋂ t ∈ LSubSp ⁡ ringLMod ⁡ R | S ⊆ t
17 8 12 16 syl2an2r ⊢ R ∈ Ring ∧ S ⊆ B → LSpan ⁡ ringLMod ⁡ R ⁡ S = ⋂ t ∈ LSubSp ⁡ ringLMod ⁡ R | S ⊆ t
18 lidlval ⊢ LIdeal ⁡ R = LSubSp ⁡ ringLMod ⁡ R
19 2 18 eqtr2i ⊢ LSubSp ⁡ ringLMod ⁡ R = I
20 19 a1i ⊢ R ∈ Ring ∧ S ⊆ B → LSubSp ⁡ ringLMod ⁡ R = I
21 20 rabeqdv ⊢ R ∈ Ring ∧ S ⊆ B → t ∈ LSubSp ⁡ ringLMod ⁡ R | S ⊆ t = t ∈ I | S ⊆ t
22 21 inteqd ⊢ R ∈ Ring ∧ S ⊆ B → ⋂ t ∈ LSubSp ⁡ ringLMod ⁡ R | S ⊆ t = ⋂ t ∈ I | S ⊆ t
23 7 17 22 3eqtrd ⊢ R ∈ Ring ∧ S ⊆ B → K ⁡ S = ⋂ t ∈ I | S ⊆ t