Metamath Proof Explorer


Theorem sbthlem7

Description: Lemma for sbth . (Contributed by NM, 27-Mar-1998)

Ref Expression
Hypotheses sbthlem.1 ⊢ A ∈ V
sbthlem.2 ⊢ D = x | x ⊆ A ∧ g B ∖ f x ⊆ A ∖ x
sbthlem.3 ⊢ H = f ↾ ⋃ D ∪ g -1 ↾ A ∖ ⋃ D
Assertion sbthlem7 ⊢ Fun ⁡ f ∧ Fun ⁡ g -1 → Fun ⁡ H

Proof

Step Hyp Ref Expression
1 sbthlem.1 ⊢ A ∈ V
2 sbthlem.2 ⊢ D = x | x ⊆ A ∧ g B ∖ f x ⊆ A ∖ x
3 sbthlem.3 ⊢ H = f ↾ ⋃ D ∪ g -1 ↾ A ∖ ⋃ D
4 funres ⊢ Fun ⁡ f → Fun ⁡ f ↾ ⋃ D
5 funres ⊢ Fun ⁡ g -1 → Fun ⁡ g -1 ↾ A ∖ ⋃ D
6 dmres ⊢ dom ⁡ f ↾ ⋃ D = ⋃ D ∩ dom ⁡ f
7 inss1 ⊢ ⋃ D ∩ dom ⁡ f ⊆ ⋃ D
8 6 7 eqsstri ⊢ dom ⁡ f ↾ ⋃ D ⊆ ⋃ D
9 ssrin ⊢ dom ⁡ f ↾ ⋃ D ⊆ ⋃ D → dom ⁡ f ↾ ⋃ D ∩ dom ⁡ g -1 ↾ A ∖ ⋃ D ⊆ ⋃ D ∩ dom ⁡ g -1 ↾ A ∖ ⋃ D
10 8 9 ax-mp ⊢ dom ⁡ f ↾ ⋃ D ∩ dom ⁡ g -1 ↾ A ∖ ⋃ D ⊆ ⋃ D ∩ dom ⁡ g -1 ↾ A ∖ ⋃ D
11 dmres ⊢ dom ⁡ g -1 ↾ A ∖ ⋃ D = A ∖ ⋃ D ∩ dom ⁡ g -1
12 inss1 ⊢ A ∖ ⋃ D ∩ dom ⁡ g -1 ⊆ A ∖ ⋃ D
13 11 12 eqsstri ⊢ dom ⁡ g -1 ↾ A ∖ ⋃ D ⊆ A ∖ ⋃ D
14 sslin ⊢ dom ⁡ g -1 ↾ A ∖ ⋃ D ⊆ A ∖ ⋃ D → ⋃ D ∩ dom ⁡ g -1 ↾ A ∖ ⋃ D ⊆ ⋃ D ∩ A ∖ ⋃ D
15 13 14 ax-mp ⊢ ⋃ D ∩ dom ⁡ g -1 ↾ A ∖ ⋃ D ⊆ ⋃ D ∩ A ∖ ⋃ D
16 10 15 sstri ⊢ dom ⁡ f ↾ ⋃ D ∩ dom ⁡ g -1 ↾ A ∖ ⋃ D ⊆ ⋃ D ∩ A ∖ ⋃ D
17 disjdif ⊢ ⋃ D ∩ A ∖ ⋃ D = ∅
18 16 17 sseqtri ⊢ dom ⁡ f ↾ ⋃ D ∩ dom ⁡ g -1 ↾ A ∖ ⋃ D ⊆ ∅
19 ss0 ⊢ dom ⁡ f ↾ ⋃ D ∩ dom ⁡ g -1 ↾ A ∖ ⋃ D ⊆ ∅ → dom ⁡ f ↾ ⋃ D ∩ dom ⁡ g -1 ↾ A ∖ ⋃ D = ∅
20 18 19 ax-mp ⊢ dom ⁡ f ↾ ⋃ D ∩ dom ⁡ g -1 ↾ A ∖ ⋃ D = ∅
21 funun ⊢ Fun ⁡ f ↾ ⋃ D ∧ Fun ⁡ g -1 ↾ A ∖ ⋃ D ∧ dom ⁡ f ↾ ⋃ D ∩ dom ⁡ g -1 ↾ A ∖ ⋃ D = ∅ → Fun ⁡ f ↾ ⋃ D ∪ g -1 ↾ A ∖ ⋃ D
22 20 21 mpan2 ⊢ Fun ⁡ f ↾ ⋃ D ∧ Fun ⁡ g -1 ↾ A ∖ ⋃ D → Fun ⁡ f ↾ ⋃ D ∪ g -1 ↾ A ∖ ⋃ D
23 4 5 22 syl2an ⊢ Fun ⁡ f ∧ Fun ⁡ g -1 → Fun ⁡ f ↾ ⋃ D ∪ g -1 ↾ A ∖ ⋃ D
24 3 funeqi ⊢ Fun ⁡ H ↔ Fun ⁡ f ↾ ⋃ D ∪ g -1 ↾ A ∖ ⋃ D
25 23 24 sylibr ⊢ Fun ⁡ f ∧ Fun ⁡ g -1 → Fun ⁡ H