Metamath Proof Explorer


Theorem sqrt0

Description: The square root of zero is zero. (Contributed by Mario Carneiro, 9-Jul-2013)

Ref Expression
Assertion sqrt0 ⊢ 0 = 0

Proof

Step Hyp Ref Expression
1 0cn ⊢ 0 ∈ ℂ
2 sqrtval ⊢ 0 ∈ ℂ → 0 = ι x ∈ ℂ | x 2 = 0 ∧ 0 ≤ ℜ ⁡ x ∧ i ⁢ x ∉ ℝ +
3 1 2 ax-mp ⊢ 0 = ι x ∈ ℂ | x 2 = 0 ∧ 0 ≤ ℜ ⁡ x ∧ i ⁢ x ∉ ℝ +
4 id ⊢ 0 ∈ ℂ → 0 ∈ ℂ
5 sqeq0 ⊢ x ∈ ℂ → x 2 = 0 ↔ x = 0
6 5 biimpa ⊢ x ∈ ℂ ∧ x 2 = 0 → x = 0
7 6 3ad2antr1 ⊢ x ∈ ℂ ∧ x 2 = 0 ∧ 0 ≤ ℜ ⁡ x ∧ i ⁢ x ∉ ℝ + → x = 0
8 7 ex ⊢ x ∈ ℂ → x 2 = 0 ∧ 0 ≤ ℜ ⁡ x ∧ i ⁢ x ∉ ℝ + → x = 0
9 sq0i ⊢ x = 0 → x 2 = 0
10 0le0 ⊢ 0 ≤ 0
11 fveq2 ⊢ x = 0 → ℜ ⁡ x = ℜ ⁡ 0
12 re0 ⊢ ℜ ⁡ 0 = 0
13 11 12 eqtrdi ⊢ x = 0 → ℜ ⁡ x = 0
14 10 13 breqtrrid ⊢ x = 0 → 0 ≤ ℜ ⁡ x
15 0re ⊢ 0 ∈ ℝ
16 eleq1 ⊢ x = 0 → x ∈ ℝ ↔ 0 ∈ ℝ
17 15 16 mpbiri ⊢ x = 0 → x ∈ ℝ
18 rennim ⊢ x ∈ ℝ → i ⁢ x ∉ ℝ +
19 17 18 syl ⊢ x = 0 → i ⁢ x ∉ ℝ +
20 9 14 19 3jca ⊢ x = 0 → x 2 = 0 ∧ 0 ≤ ℜ ⁡ x ∧ i ⁢ x ∉ ℝ +
21 8 20 impbid1 ⊢ x ∈ ℂ → x 2 = 0 ∧ 0 ≤ ℜ ⁡ x ∧ i ⁢ x ∉ ℝ + ↔ x = 0
22 21 adantl ⊢ 0 ∈ ℂ ∧ x ∈ ℂ → x 2 = 0 ∧ 0 ≤ ℜ ⁡ x ∧ i ⁢ x ∉ ℝ + ↔ x = 0
23 4 22 riota5 ⊢ 0 ∈ ℂ → ι x ∈ ℂ | x 2 = 0 ∧ 0 ≤ ℜ ⁡ x ∧ i ⁢ x ∉ ℝ + = 0
24 1 23 ax-mp ⊢ ι x ∈ ℂ | x 2 = 0 ∧ 0 ≤ ℜ ⁡ x ∧ i ⁢ x ∉ ℝ + = 0
25 3 24 eqtri ⊢ 0 = 0