Metamath Proof Explorer


Theorem xrltnsym

Description: Ordering on the extended reals is not symmetric. (Contributed by NM, 15-Oct-2005)

Ref Expression
Assertion xrltnsym ⊢ A ∈ ℝ * ∧ B ∈ ℝ * → A < B → ¬ B < A

Proof

Step Hyp Ref Expression
1 elxr ⊢ A ∈ ℝ * ↔ A ∈ ℝ ∨ A = +∞ ∨ A = −∞
2 elxr ⊢ B ∈ ℝ * ↔ B ∈ ℝ ∨ B = +∞ ∨ B = −∞
3 ltnsym ⊢ A ∈ ℝ ∧ B ∈ ℝ → A < B → ¬ B < A
4 rexr ⊢ A ∈ ℝ → A ∈ ℝ *
5 pnfnlt ⊢ A ∈ ℝ * → ¬ +∞ < A
6 4 5 syl ⊢ A ∈ ℝ → ¬ +∞ < A
7 6 adantr ⊢ A ∈ ℝ ∧ B = +∞ → ¬ +∞ < A
8 breq1 ⊢ B = +∞ → B < A ↔ +∞ < A
9 8 adantl ⊢ A ∈ ℝ ∧ B = +∞ → B < A ↔ +∞ < A
10 7 9 mtbird ⊢ A ∈ ℝ ∧ B = +∞ → ¬ B < A
11 10 a1d ⊢ A ∈ ℝ ∧ B = +∞ → A < B → ¬ B < A
12 nltmnf ⊢ A ∈ ℝ * → ¬ A < −∞
13 4 12 syl ⊢ A ∈ ℝ → ¬ A < −∞
14 13 adantr ⊢ A ∈ ℝ ∧ B = −∞ → ¬ A < −∞
15 breq2 ⊢ B = −∞ → A < B ↔ A < −∞
16 15 adantl ⊢ A ∈ ℝ ∧ B = −∞ → A < B ↔ A < −∞
17 14 16 mtbird ⊢ A ∈ ℝ ∧ B = −∞ → ¬ A < B
18 17 pm2.21d ⊢ A ∈ ℝ ∧ B = −∞ → A < B → ¬ B < A
19 3 11 18 3jaodan ⊢ A ∈ ℝ ∧ B ∈ ℝ ∨ B = +∞ ∨ B = −∞ → A < B → ¬ B < A
20 pnfnlt ⊢ B ∈ ℝ * → ¬ +∞ < B
21 20 adantl ⊢ A = +∞ ∧ B ∈ ℝ * → ¬ +∞ < B
22 breq1 ⊢ A = +∞ → A < B ↔ +∞ < B
23 22 adantr ⊢ A = +∞ ∧ B ∈ ℝ * → A < B ↔ +∞ < B
24 21 23 mtbird ⊢ A = +∞ ∧ B ∈ ℝ * → ¬ A < B
25 24 pm2.21d ⊢ A = +∞ ∧ B ∈ ℝ * → A < B → ¬ B < A
26 2 25 sylan2br ⊢ A = +∞ ∧ B ∈ ℝ ∨ B = +∞ ∨ B = −∞ → A < B → ¬ B < A
27 rexr ⊢ B ∈ ℝ → B ∈ ℝ *
28 nltmnf ⊢ B ∈ ℝ * → ¬ B < −∞
29 27 28 syl ⊢ B ∈ ℝ → ¬ B < −∞
30 29 adantl ⊢ A = −∞ ∧ B ∈ ℝ → ¬ B < −∞
31 breq2 ⊢ A = −∞ → B < A ↔ B < −∞
32 31 adantr ⊢ A = −∞ ∧ B ∈ ℝ → B < A ↔ B < −∞
33 30 32 mtbird ⊢ A = −∞ ∧ B ∈ ℝ → ¬ B < A
34 33 a1d ⊢ A = −∞ ∧ B ∈ ℝ → A < B → ¬ B < A
35 mnfxr ⊢ −∞ ∈ ℝ *
36 pnfnlt ⊢ −∞ ∈ ℝ * → ¬ +∞ < −∞
37 35 36 ax-mp ⊢ ¬ +∞ < −∞
38 breq12 ⊢ B = +∞ ∧ A = −∞ → B < A ↔ +∞ < −∞
39 37 38 mtbiri ⊢ B = +∞ ∧ A = −∞ → ¬ B < A
40 39 ancoms ⊢ A = −∞ ∧ B = +∞ → ¬ B < A
41 40 a1d ⊢ A = −∞ ∧ B = +∞ → A < B → ¬ B < A
42 xrltnr ⊢ −∞ ∈ ℝ * → ¬ −∞ < −∞
43 35 42 ax-mp ⊢ ¬ −∞ < −∞
44 breq12 ⊢ A = −∞ ∧ B = −∞ → A < B ↔ −∞ < −∞
45 43 44 mtbiri ⊢ A = −∞ ∧ B = −∞ → ¬ A < B
46 45 pm2.21d ⊢ A = −∞ ∧ B = −∞ → A < B → ¬ B < A
47 34 41 46 3jaodan ⊢ A = −∞ ∧ B ∈ ℝ ∨ B = +∞ ∨ B = −∞ → A < B → ¬ B < A
48 19 26 47 3jaoian ⊢ A ∈ ℝ ∨ A = +∞ ∨ A = −∞ ∧ B ∈ ℝ ∨ B = +∞ ∨ B = −∞ → A < B → ¬ B < A
49 1 2 48 syl2anb ⊢ A ∈ ℝ * ∧ B ∈ ℝ * → A < B → ¬ B < A