Metamath Proof Explorer


Theorem bnj900

Description: Technical lemma for bnj69 . This lemma may no longer be used or have become an indirect lemma of the theorem in question (i.e. a lemma of a lemma... of the theorem). (Contributed by Jonathan Ben-Naim, 3-Jun-2011) (New usage is discouraged.)

Ref Expression
Hypotheses bnj900.3 ⊢ 𝐷 = ( ω ∖ { ∅ } )
bnj900.4 ⊢ 𝐵 = { 𝑓 ∣ ∃ 𝑛 ∈ 𝐷 ( 𝑓 Fn 𝑛 ∧ 𝜑 ∧ 𝜓 ) }
Assertion bnj900 ( 𝑓 ∈ 𝐵 → ∅ ∈ dom 𝑓 )

Proof

Step Hyp Ref Expression
1 bnj900.3 ⊢ 𝐷 = ( ω ∖ { ∅ } )
2 bnj900.4 ⊢ 𝐵 = { 𝑓 ∣ ∃ 𝑛 ∈ 𝐷 ( 𝑓 Fn 𝑛 ∧ 𝜑 ∧ 𝜓 ) }
3 2 bnj1436 ⊢ ( 𝑓 ∈ 𝐵 → ∃ 𝑛 ∈ 𝐷 ( 𝑓 Fn 𝑛 ∧ 𝜑 ∧ 𝜓 ) )
4 simp1 ⊢ ( ( 𝑓 Fn 𝑛 ∧ 𝜑 ∧ 𝜓 ) → 𝑓 Fn 𝑛 )
5 4 reximi ⊢ ( ∃ 𝑛 ∈ 𝐷 ( 𝑓 Fn 𝑛 ∧ 𝜑 ∧ 𝜓 ) → ∃ 𝑛 ∈ 𝐷 𝑓 Fn 𝑛 )
6 fndm ⊢ ( 𝑓 Fn 𝑛 → dom 𝑓 = 𝑛 )
7 6 reximi ⊢ ( ∃ 𝑛 ∈ 𝐷 𝑓 Fn 𝑛 → ∃ 𝑛 ∈ 𝐷 dom 𝑓 = 𝑛 )
8 3 5 7 3syl ⊢ ( 𝑓 ∈ 𝐵 → ∃ 𝑛 ∈ 𝐷 dom 𝑓 = 𝑛 )
9 8 bnj1196 ⊢ ( 𝑓 ∈ 𝐵 → ∃ 𝑛 ( 𝑛 ∈ 𝐷 ∧ dom 𝑓 = 𝑛 ) )
10 nfre1 ⊢ Ⅎ 𝑛 ∃ 𝑛 ∈ 𝐷 ( 𝑓 Fn 𝑛 ∧ 𝜑 ∧ 𝜓 )
11 10 nfab ⊢ Ⅎ 𝑛 { 𝑓 ∣ ∃ 𝑛 ∈ 𝐷 ( 𝑓 Fn 𝑛 ∧ 𝜑 ∧ 𝜓 ) }
12 2 11 nfcxfr ⊢ Ⅎ 𝑛 𝐵
13 12 nfcri ⊢ Ⅎ 𝑛 𝑓 ∈ 𝐵
14 13 19.37 ⊢ ( ∃ 𝑛 ( 𝑓 ∈ 𝐵 → ( 𝑛 ∈ 𝐷 ∧ dom 𝑓 = 𝑛 ) ) ↔ ( 𝑓 ∈ 𝐵 → ∃ 𝑛 ( 𝑛 ∈ 𝐷 ∧ dom 𝑓 = 𝑛 ) ) )
15 9 14 mpbir ⊢ ∃ 𝑛 ( 𝑓 ∈ 𝐵 → ( 𝑛 ∈ 𝐷 ∧ dom 𝑓 = 𝑛 ) )
16 nfv ⊢ Ⅎ 𝑛 ∅ ∈ dom 𝑓
17 13 16 nfim ⊢ Ⅎ 𝑛 ( 𝑓 ∈ 𝐵 → ∅ ∈ dom 𝑓 )
18 1 bnj529 ⊢ ( 𝑛 ∈ 𝐷 → ∅ ∈ 𝑛 )
19 eleq2 ⊢ ( dom 𝑓 = 𝑛 → ( ∅ ∈ dom 𝑓 ↔ ∅ ∈ 𝑛 ) )
20 19 biimparc ⊢ ( ( ∅ ∈ 𝑛 ∧ dom 𝑓 = 𝑛 ) → ∅ ∈ dom 𝑓 )
21 18 20 sylan ⊢ ( ( 𝑛 ∈ 𝐷 ∧ dom 𝑓 = 𝑛 ) → ∅ ∈ dom 𝑓 )
22 21 imim2i ⊢ ( ( 𝑓 ∈ 𝐵 → ( 𝑛 ∈ 𝐷 ∧ dom 𝑓 = 𝑛 ) ) → ( 𝑓 ∈ 𝐵 → ∅ ∈ dom 𝑓 ) )
23 17 22 exlimi ⊢ ( ∃ 𝑛 ( 𝑓 ∈ 𝐵 → ( 𝑛 ∈ 𝐷 ∧ dom 𝑓 = 𝑛 ) ) → ( 𝑓 ∈ 𝐵 → ∅ ∈ dom 𝑓 ) )
24 15 23 ax-mp ⊢ ( 𝑓 ∈ 𝐵 → ∅ ∈ dom 𝑓 )