Metamath Proof Explorer


Theorem fdivmptf

Description: The quotient of two functions into the complex numbers is a function into the complex numbers. (Contributed by AV, 16-May-2020)

Ref Expression
Assertion fdivmptf ( ( 𝐹 : 𝐴 ⟶ ℂ ∧ 𝐺 : 𝐴 ⟶ ℂ ∧ 𝐴 ∈ 𝑉 ) → ( 𝐹 /f 𝐺 ) : ( 𝐺 supp 0 ) ⟶ ℂ )

Proof

Step Hyp Ref Expression
1 simpl1 ⊢ ( ( ( 𝐹 : 𝐴 ⟶ ℂ ∧ 𝐺 : 𝐴 ⟶ ℂ ∧ 𝐴 ∈ 𝑉 ) ∧ 𝑥 ∈ ( 𝐺 supp 0 ) ) → 𝐹 : 𝐴 ⟶ ℂ )
2 suppssdm ⊢ ( 𝐺 supp 0 ) ⊆ dom 𝐺
3 fdm ⊢ ( 𝐺 : 𝐴 ⟶ ℂ → dom 𝐺 = 𝐴 )
4 2 3 sseqtrid ⊢ ( 𝐺 : 𝐴 ⟶ ℂ → ( 𝐺 supp 0 ) ⊆ 𝐴 )
5 4 3ad2ant2 ⊢ ( ( 𝐹 : 𝐴 ⟶ ℂ ∧ 𝐺 : 𝐴 ⟶ ℂ ∧ 𝐴 ∈ 𝑉 ) → ( 𝐺 supp 0 ) ⊆ 𝐴 )
6 5 sselda ⊢ ( ( ( 𝐹 : 𝐴 ⟶ ℂ ∧ 𝐺 : 𝐴 ⟶ ℂ ∧ 𝐴 ∈ 𝑉 ) ∧ 𝑥 ∈ ( 𝐺 supp 0 ) ) → 𝑥 ∈ 𝐴 )
7 1 6 ffvelcdmd ⊢ ( ( ( 𝐹 : 𝐴 ⟶ ℂ ∧ 𝐺 : 𝐴 ⟶ ℂ ∧ 𝐴 ∈ 𝑉 ) ∧ 𝑥 ∈ ( 𝐺 supp 0 ) ) → ( 𝐹 ‘ 𝑥 ) ∈ ℂ )
8 simpl2 ⊢ ( ( ( 𝐹 : 𝐴 ⟶ ℂ ∧ 𝐺 : 𝐴 ⟶ ℂ ∧ 𝐴 ∈ 𝑉 ) ∧ 𝑥 ∈ ( 𝐺 supp 0 ) ) → 𝐺 : 𝐴 ⟶ ℂ )
9 8 6 ffvelcdmd ⊢ ( ( ( 𝐹 : 𝐴 ⟶ ℂ ∧ 𝐺 : 𝐴 ⟶ ℂ ∧ 𝐴 ∈ 𝑉 ) ∧ 𝑥 ∈ ( 𝐺 supp 0 ) ) → ( 𝐺 ‘ 𝑥 ) ∈ ℂ )
10 ffn ⊢ ( 𝐺 : 𝐴 ⟶ ℂ → 𝐺 Fn 𝐴 )
11 10 3ad2ant2 ⊢ ( ( 𝐹 : 𝐴 ⟶ ℂ ∧ 𝐺 : 𝐴 ⟶ ℂ ∧ 𝐴 ∈ 𝑉 ) → 𝐺 Fn 𝐴 )
12 simp3 ⊢ ( ( 𝐹 : 𝐴 ⟶ ℂ ∧ 𝐺 : 𝐴 ⟶ ℂ ∧ 𝐴 ∈ 𝑉 ) → 𝐴 ∈ 𝑉 )
13 0cnd ⊢ ( ( 𝐹 : 𝐴 ⟶ ℂ ∧ 𝐺 : 𝐴 ⟶ ℂ ∧ 𝐴 ∈ 𝑉 ) → 0 ∈ ℂ )
14 elsuppfn ⊢ ( ( 𝐺 Fn 𝐴 ∧ 𝐴 ∈ 𝑉 ∧ 0 ∈ ℂ ) → ( 𝑥 ∈ ( 𝐺 supp 0 ) ↔ ( 𝑥 ∈ 𝐴 ∧ ( 𝐺 ‘ 𝑥 ) ≠ 0 ) ) )
15 11 12 13 14 syl3anc ⊢ ( ( 𝐹 : 𝐴 ⟶ ℂ ∧ 𝐺 : 𝐴 ⟶ ℂ ∧ 𝐴 ∈ 𝑉 ) → ( 𝑥 ∈ ( 𝐺 supp 0 ) ↔ ( 𝑥 ∈ 𝐴 ∧ ( 𝐺 ‘ 𝑥 ) ≠ 0 ) ) )
16 15 simplbda ⊢ ( ( ( 𝐹 : 𝐴 ⟶ ℂ ∧ 𝐺 : 𝐴 ⟶ ℂ ∧ 𝐴 ∈ 𝑉 ) ∧ 𝑥 ∈ ( 𝐺 supp 0 ) ) → ( 𝐺 ‘ 𝑥 ) ≠ 0 )
17 7 9 16 divcld ⊢ ( ( ( 𝐹 : 𝐴 ⟶ ℂ ∧ 𝐺 : 𝐴 ⟶ ℂ ∧ 𝐴 ∈ 𝑉 ) ∧ 𝑥 ∈ ( 𝐺 supp 0 ) ) → ( ( 𝐹 ‘ 𝑥 ) / ( 𝐺 ‘ 𝑥 ) ) ∈ ℂ )
18 17 fmpttd ⊢ ( ( 𝐹 : 𝐴 ⟶ ℂ ∧ 𝐺 : 𝐴 ⟶ ℂ ∧ 𝐴 ∈ 𝑉 ) → ( 𝑥 ∈ ( 𝐺 supp 0 ) ↦ ( ( 𝐹 ‘ 𝑥 ) / ( 𝐺 ‘ 𝑥 ) ) ) : ( 𝐺 supp 0 ) ⟶ ℂ )
19 fdivmpt ⊢ ( ( 𝐹 : 𝐴 ⟶ ℂ ∧ 𝐺 : 𝐴 ⟶ ℂ ∧ 𝐴 ∈ 𝑉 ) → ( 𝐹 /f 𝐺 ) = ( 𝑥 ∈ ( 𝐺 supp 0 ) ↦ ( ( 𝐹 ‘ 𝑥 ) / ( 𝐺 ‘ 𝑥 ) ) ) )
20 19 feq1d ⊢ ( ( 𝐹 : 𝐴 ⟶ ℂ ∧ 𝐺 : 𝐴 ⟶ ℂ ∧ 𝐴 ∈ 𝑉 ) → ( ( 𝐹 /f 𝐺 ) : ( 𝐺 supp 0 ) ⟶ ℂ ↔ ( 𝑥 ∈ ( 𝐺 supp 0 ) ↦ ( ( 𝐹 ‘ 𝑥 ) / ( 𝐺 ‘ 𝑥 ) ) ) : ( 𝐺 supp 0 ) ⟶ ℂ ) )
21 18 20 mpbird ⊢ ( ( 𝐹 : 𝐴 ⟶ ℂ ∧ 𝐺 : 𝐴 ⟶ ℂ ∧ 𝐴 ∈ 𝑉 ) → ( 𝐹 /f 𝐺 ) : ( 𝐺 supp 0 ) ⟶ ℂ )