Step |
Hyp |
Ref |
Expression |
1 |
|
eqid |
⊢ ( 1st ‘ 𝑅 ) = ( 1st ‘ 𝑅 ) |
2 |
|
eqid |
⊢ ran ( 1st ‘ 𝑅 ) = ran ( 1st ‘ 𝑅 ) |
3 |
1 2
|
idlss |
⊢ ( ( 𝑅 ∈ RingOps ∧ 𝐼 ∈ ( Idl ‘ 𝑅 ) ) → 𝐼 ⊆ ran ( 1st ‘ 𝑅 ) ) |
4 |
|
sstr |
⊢ ( ( 𝑆 ⊆ 𝐼 ∧ 𝐼 ⊆ ran ( 1st ‘ 𝑅 ) ) → 𝑆 ⊆ ran ( 1st ‘ 𝑅 ) ) |
5 |
4
|
ancoms |
⊢ ( ( 𝐼 ⊆ ran ( 1st ‘ 𝑅 ) ∧ 𝑆 ⊆ 𝐼 ) → 𝑆 ⊆ ran ( 1st ‘ 𝑅 ) ) |
6 |
1 2
|
igenval |
⊢ ( ( 𝑅 ∈ RingOps ∧ 𝑆 ⊆ ran ( 1st ‘ 𝑅 ) ) → ( 𝑅 IdlGen 𝑆 ) = ∩ { 𝑗 ∈ ( Idl ‘ 𝑅 ) ∣ 𝑆 ⊆ 𝑗 } ) |
7 |
5 6
|
sylan2 |
⊢ ( ( 𝑅 ∈ RingOps ∧ ( 𝐼 ⊆ ran ( 1st ‘ 𝑅 ) ∧ 𝑆 ⊆ 𝐼 ) ) → ( 𝑅 IdlGen 𝑆 ) = ∩ { 𝑗 ∈ ( Idl ‘ 𝑅 ) ∣ 𝑆 ⊆ 𝑗 } ) |
8 |
7
|
anassrs |
⊢ ( ( ( 𝑅 ∈ RingOps ∧ 𝐼 ⊆ ran ( 1st ‘ 𝑅 ) ) ∧ 𝑆 ⊆ 𝐼 ) → ( 𝑅 IdlGen 𝑆 ) = ∩ { 𝑗 ∈ ( Idl ‘ 𝑅 ) ∣ 𝑆 ⊆ 𝑗 } ) |
9 |
3 8
|
syldanl |
⊢ ( ( ( 𝑅 ∈ RingOps ∧ 𝐼 ∈ ( Idl ‘ 𝑅 ) ) ∧ 𝑆 ⊆ 𝐼 ) → ( 𝑅 IdlGen 𝑆 ) = ∩ { 𝑗 ∈ ( Idl ‘ 𝑅 ) ∣ 𝑆 ⊆ 𝑗 } ) |
10 |
9
|
3impa |
⊢ ( ( 𝑅 ∈ RingOps ∧ 𝐼 ∈ ( Idl ‘ 𝑅 ) ∧ 𝑆 ⊆ 𝐼 ) → ( 𝑅 IdlGen 𝑆 ) = ∩ { 𝑗 ∈ ( Idl ‘ 𝑅 ) ∣ 𝑆 ⊆ 𝑗 } ) |
11 |
|
sseq2 |
⊢ ( 𝑗 = 𝐼 → ( 𝑆 ⊆ 𝑗 ↔ 𝑆 ⊆ 𝐼 ) ) |
12 |
11
|
intminss |
⊢ ( ( 𝐼 ∈ ( Idl ‘ 𝑅 ) ∧ 𝑆 ⊆ 𝐼 ) → ∩ { 𝑗 ∈ ( Idl ‘ 𝑅 ) ∣ 𝑆 ⊆ 𝑗 } ⊆ 𝐼 ) |
13 |
12
|
3adant1 |
⊢ ( ( 𝑅 ∈ RingOps ∧ 𝐼 ∈ ( Idl ‘ 𝑅 ) ∧ 𝑆 ⊆ 𝐼 ) → ∩ { 𝑗 ∈ ( Idl ‘ 𝑅 ) ∣ 𝑆 ⊆ 𝑗 } ⊆ 𝐼 ) |
14 |
10 13
|
eqsstrd |
⊢ ( ( 𝑅 ∈ RingOps ∧ 𝐼 ∈ ( Idl ‘ 𝑅 ) ∧ 𝑆 ⊆ 𝐼 ) → ( 𝑅 IdlGen 𝑆 ) ⊆ 𝐼 ) |