Metamath Proof Explorer


Theorem imasetpreimafvbijlemfv1

Description: Lemma for imasetpreimafvbij : for a preimage of a value of function F there is an element of the preimage so that the value of the mapping H at this preimage is the function value at this element. (Contributed by AV, 5-Mar-2024)

Ref Expression
Hypotheses fundcmpsurinj.p ⊢ 𝑃 = { 𝑧 ∣ ∃ 𝑥 ∈ 𝐴 𝑧 = ( ◡ 𝐹 “ { ( 𝐹 ‘ 𝑥 ) } ) }
fundcmpsurinj.h ⊢ 𝐻 = ( 𝑝 ∈ 𝑃 ↦ ∪ ( 𝐹 “ 𝑝 ) )
Assertion imasetpreimafvbijlemfv1 ( ( 𝐹 Fn 𝐴 ∧ 𝑋 ∈ 𝑃 ) → ∃ 𝑦 ∈ 𝑋 ( 𝐻 ‘ 𝑋 ) = ( 𝐹 ‘ 𝑦 ) )

Proof

Step Hyp Ref Expression
1 fundcmpsurinj.p ⊢ 𝑃 = { 𝑧 ∣ ∃ 𝑥 ∈ 𝐴 𝑧 = ( ◡ 𝐹 “ { ( 𝐹 ‘ 𝑥 ) } ) }
2 fundcmpsurinj.h ⊢ 𝐻 = ( 𝑝 ∈ 𝑃 ↦ ∪ ( 𝐹 “ 𝑝 ) )
3 1 0nelsetpreimafv ⊢ ( 𝐹 Fn 𝐴 → ∅ ∉ 𝑃 )
4 elnelne2 ⊢ ( ( 𝑋 ∈ 𝑃 ∧ ∅ ∉ 𝑃 ) → 𝑋 ≠ ∅ )
5 4 expcom ⊢ ( ∅ ∉ 𝑃 → ( 𝑋 ∈ 𝑃 → 𝑋 ≠ ∅ ) )
6 3 5 syl ⊢ ( 𝐹 Fn 𝐴 → ( 𝑋 ∈ 𝑃 → 𝑋 ≠ ∅ ) )
7 6 imp ⊢ ( ( 𝐹 Fn 𝐴 ∧ 𝑋 ∈ 𝑃 ) → 𝑋 ≠ ∅ )
8 simpr ⊢ ( ( ( 𝐹 Fn 𝐴 ∧ 𝑋 ∈ 𝑃 ) ∧ 𝑦 ∈ 𝑋 ) → 𝑦 ∈ 𝑋 )
9 1 2 imasetpreimafvbijlemfv ⊢ ( ( 𝐹 Fn 𝐴 ∧ 𝑋 ∈ 𝑃 ∧ 𝑦 ∈ 𝑋 ) → ( 𝐻 ‘ 𝑋 ) = ( 𝐹 ‘ 𝑦 ) )
10 9 3expa ⊢ ( ( ( 𝐹 Fn 𝐴 ∧ 𝑋 ∈ 𝑃 ) ∧ 𝑦 ∈ 𝑋 ) → ( 𝐻 ‘ 𝑋 ) = ( 𝐹 ‘ 𝑦 ) )
11 8 10 jca ⊢ ( ( ( 𝐹 Fn 𝐴 ∧ 𝑋 ∈ 𝑃 ) ∧ 𝑦 ∈ 𝑋 ) → ( 𝑦 ∈ 𝑋 ∧ ( 𝐻 ‘ 𝑋 ) = ( 𝐹 ‘ 𝑦 ) ) )
12 11 ex ⊢ ( ( 𝐹 Fn 𝐴 ∧ 𝑋 ∈ 𝑃 ) → ( 𝑦 ∈ 𝑋 → ( 𝑦 ∈ 𝑋 ∧ ( 𝐻 ‘ 𝑋 ) = ( 𝐹 ‘ 𝑦 ) ) ) )
13 12 eximdv ⊢ ( ( 𝐹 Fn 𝐴 ∧ 𝑋 ∈ 𝑃 ) → ( ∃ 𝑦 𝑦 ∈ 𝑋 → ∃ 𝑦 ( 𝑦 ∈ 𝑋 ∧ ( 𝐻 ‘ 𝑋 ) = ( 𝐹 ‘ 𝑦 ) ) ) )
14 n0 ⊢ ( 𝑋 ≠ ∅ ↔ ∃ 𝑦 𝑦 ∈ 𝑋 )
15 df-rex ⊢ ( ∃ 𝑦 ∈ 𝑋 ( 𝐻 ‘ 𝑋 ) = ( 𝐹 ‘ 𝑦 ) ↔ ∃ 𝑦 ( 𝑦 ∈ 𝑋 ∧ ( 𝐻 ‘ 𝑋 ) = ( 𝐹 ‘ 𝑦 ) ) )
16 13 14 15 3imtr4g ⊢ ( ( 𝐹 Fn 𝐴 ∧ 𝑋 ∈ 𝑃 ) → ( 𝑋 ≠ ∅ → ∃ 𝑦 ∈ 𝑋 ( 𝐻 ‘ 𝑋 ) = ( 𝐹 ‘ 𝑦 ) ) )
17 7 16 mpd ⊢ ( ( 𝐹 Fn 𝐴 ∧ 𝑋 ∈ 𝑃 ) → ∃ 𝑦 ∈ 𝑋 ( 𝐻 ‘ 𝑋 ) = ( 𝐹 ‘ 𝑦 ) )