Metamath Proof Explorer


Theorem onsucf1lem

Description: For ordinals, the successor operation is injective, so there is at most one ordinal that a given ordinal could be the successor of. Lemma 1.17 of Schloeder p. 2. (Contributed by RP, 18-Jan-2025)

Ref Expression
Assertion onsucf1lem ( 𝐴 ∈ On → ∃* 𝑏 ∈ On 𝐴 = suc 𝑏 )

Proof

Step Hyp Ref Expression
1 onuni ⊢ ( 𝐴 ∈ On → ∪ 𝐴 ∈ On )
2 onsucuni2 ⊢ ( ( 𝐴 ∈ On ∧ 𝐴 = suc 𝑏 ) → suc ∪ 𝐴 = 𝐴 )
3 2 adantlr ⊢ ( ( ( 𝐴 ∈ On ∧ 𝑏 ∈ On ) ∧ 𝐴 = suc 𝑏 ) → suc ∪ 𝐴 = 𝐴 )
4 simpr ⊢ ( ( ( 𝐴 ∈ On ∧ 𝑏 ∈ On ) ∧ 𝐴 = suc 𝑏 ) → 𝐴 = suc 𝑏 )
5 3 4 eqtr2d ⊢ ( ( ( 𝐴 ∈ On ∧ 𝑏 ∈ On ) ∧ 𝐴 = suc 𝑏 ) → suc 𝑏 = suc ∪ 𝐴 )
6 1 anim1i ⊢ ( ( 𝐴 ∈ On ∧ 𝑏 ∈ On ) → ( ∪ 𝐴 ∈ On ∧ 𝑏 ∈ On ) )
7 6 adantr ⊢ ( ( ( 𝐴 ∈ On ∧ 𝑏 ∈ On ) ∧ 𝐴 = suc 𝑏 ) → ( ∪ 𝐴 ∈ On ∧ 𝑏 ∈ On ) )
8 7 ancomd ⊢ ( ( ( 𝐴 ∈ On ∧ 𝑏 ∈ On ) ∧ 𝐴 = suc 𝑏 ) → ( 𝑏 ∈ On ∧ ∪ 𝐴 ∈ On ) )
9 suc11 ⊢ ( ( 𝑏 ∈ On ∧ ∪ 𝐴 ∈ On ) → ( suc 𝑏 = suc ∪ 𝐴 ↔ 𝑏 = ∪ 𝐴 ) )
10 8 9 syl ⊢ ( ( ( 𝐴 ∈ On ∧ 𝑏 ∈ On ) ∧ 𝐴 = suc 𝑏 ) → ( suc 𝑏 = suc ∪ 𝐴 ↔ 𝑏 = ∪ 𝐴 ) )
11 5 10 mpbid ⊢ ( ( ( 𝐴 ∈ On ∧ 𝑏 ∈ On ) ∧ 𝐴 = suc 𝑏 ) → 𝑏 = ∪ 𝐴 )
12 11 ex ⊢ ( ( 𝐴 ∈ On ∧ 𝑏 ∈ On ) → ( 𝐴 = suc 𝑏 → 𝑏 = ∪ 𝐴 ) )
13 12 ralrimiva ⊢ ( 𝐴 ∈ On → ∀ 𝑏 ∈ On ( 𝐴 = suc 𝑏 → 𝑏 = ∪ 𝐴 ) )
14 eqeq2 ⊢ ( 𝑐 = ∪ 𝐴 → ( 𝑏 = 𝑐 ↔ 𝑏 = ∪ 𝐴 ) )
15 14 imbi2d ⊢ ( 𝑐 = ∪ 𝐴 → ( ( 𝐴 = suc 𝑏 → 𝑏 = 𝑐 ) ↔ ( 𝐴 = suc 𝑏 → 𝑏 = ∪ 𝐴 ) ) )
16 15 ralbidv ⊢ ( 𝑐 = ∪ 𝐴 → ( ∀ 𝑏 ∈ On ( 𝐴 = suc 𝑏 → 𝑏 = 𝑐 ) ↔ ∀ 𝑏 ∈ On ( 𝐴 = suc 𝑏 → 𝑏 = ∪ 𝐴 ) ) )
17 1 13 16 spcedv ⊢ ( 𝐴 ∈ On → ∃ 𝑐 ∀ 𝑏 ∈ On ( 𝐴 = suc 𝑏 → 𝑏 = 𝑐 ) )
18 nfv ⊢ Ⅎ 𝑐 𝐴 = suc 𝑏
19 18 rmo2 ⊢ ( ∃* 𝑏 ∈ On 𝐴 = suc 𝑏 ↔ ∃ 𝑐 ∀ 𝑏 ∈ On ( 𝐴 = suc 𝑏 → 𝑏 = 𝑐 ) )
20 17 19 sylibr ⊢ ( 𝐴 ∈ On → ∃* 𝑏 ∈ On 𝐴 = suc 𝑏 )