Metamath Proof Explorer


Theorem smfmulc1

Description: A sigma-measurable function multiplied by a constant is sigma-measurable. Proposition 121E (c) of Fremlin1 p. 37 . (Contributed by Glauco Siliprandi, 26-Jun-2021)

Ref Expression
Hypotheses smfmulc1.x ⊢ Ⅎ 𝑥 𝜑
smfmulc1.s ⊢ ( 𝜑 → 𝑆 ∈ SAlg )
smfmulc1.a ⊢ ( 𝜑 → 𝐴 ∈ 𝑉 )
smfmulc1.b ⊢ ( ( 𝜑 ∧ 𝑥 ∈ 𝐴 ) → 𝐵 ∈ ℝ )
smfmulc1.c ⊢ ( 𝜑 → 𝐶 ∈ ℝ )
smfmulc1.m ⊢ ( 𝜑 → ( 𝑥 ∈ 𝐴 ↦ 𝐵 ) ∈ ( SMblFn ‘ 𝑆 ) )
Assertion smfmulc1 ( 𝜑 → ( 𝑥 ∈ 𝐴 ↦ ( 𝐶 · 𝐵 ) ) ∈ ( SMblFn ‘ 𝑆 ) )

Proof

Step Hyp Ref Expression
1 smfmulc1.x ⊢ Ⅎ 𝑥 𝜑
2 smfmulc1.s ⊢ ( 𝜑 → 𝑆 ∈ SAlg )
3 smfmulc1.a ⊢ ( 𝜑 → 𝐴 ∈ 𝑉 )
4 smfmulc1.b ⊢ ( ( 𝜑 ∧ 𝑥 ∈ 𝐴 ) → 𝐵 ∈ ℝ )
5 smfmulc1.c ⊢ ( 𝜑 → 𝐶 ∈ ℝ )
6 smfmulc1.m ⊢ ( 𝜑 → ( 𝑥 ∈ 𝐴 ↦ 𝐵 ) ∈ ( SMblFn ‘ 𝑆 ) )
7 inidm ⊢ ( 𝐴 ∩ 𝐴 ) = 𝐴
8 7 eqcomi ⊢ 𝐴 = ( 𝐴 ∩ 𝐴 )
9 8 mpteq1i ⊢ ( 𝑥 ∈ 𝐴 ↦ ( 𝐶 · 𝐵 ) ) = ( 𝑥 ∈ ( 𝐴 ∩ 𝐴 ) ↦ ( 𝐶 · 𝐵 ) )
10 9 a1i ⊢ ( 𝜑 → ( 𝑥 ∈ 𝐴 ↦ ( 𝐶 · 𝐵 ) ) = ( 𝑥 ∈ ( 𝐴 ∩ 𝐴 ) ↦ ( 𝐶 · 𝐵 ) ) )
11 5 adantr ⊢ ( ( 𝜑 ∧ 𝑥 ∈ 𝐴 ) → 𝐶 ∈ ℝ )
12 eqid ⊢ ( 𝑥 ∈ 𝐴 ↦ 𝐵 ) = ( 𝑥 ∈ 𝐴 ↦ 𝐵 )
13 1 12 4 dmmptdf ⊢ ( 𝜑 → dom ( 𝑥 ∈ 𝐴 ↦ 𝐵 ) = 𝐴 )
14 13 eqcomd ⊢ ( 𝜑 → 𝐴 = dom ( 𝑥 ∈ 𝐴 ↦ 𝐵 ) )
15 eqid ⊢ dom ( 𝑥 ∈ 𝐴 ↦ 𝐵 ) = dom ( 𝑥 ∈ 𝐴 ↦ 𝐵 )
16 2 6 15 smfdmss ⊢ ( 𝜑 → dom ( 𝑥 ∈ 𝐴 ↦ 𝐵 ) ⊆ ∪ 𝑆 )
17 14 16 eqsstrd ⊢ ( 𝜑 → 𝐴 ⊆ ∪ 𝑆 )
18 eqid ⊢ ( 𝑥 ∈ 𝐴 ↦ 𝐶 ) = ( 𝑥 ∈ 𝐴 ↦ 𝐶 )
19 1 2 17 5 18 smfconst ⊢ ( 𝜑 → ( 𝑥 ∈ 𝐴 ↦ 𝐶 ) ∈ ( SMblFn ‘ 𝑆 ) )
20 1 2 3 11 4 19 6 smfmul ⊢ ( 𝜑 → ( 𝑥 ∈ ( 𝐴 ∩ 𝐴 ) ↦ ( 𝐶 · 𝐵 ) ) ∈ ( SMblFn ‘ 𝑆 ) )
21 10 20 eqeltrd ⊢ ( 𝜑 → ( 𝑥 ∈ 𝐴 ↦ ( 𝐶 · 𝐵 ) ) ∈ ( SMblFn ‘ 𝑆 ) )