Metamath Proof Explorer


Theorem wl-sb8eutv

Description: Substitution of variable in universal quantifier. Closed form of sb8euv . (Contributed by Wolf Lammen, 3-May-2025)

Ref Expression
Assertion wl-sb8eutv ( ∀ 𝑥 Ⅎ 𝑦 𝜑 → ( ∃! 𝑥 𝜑 ↔ ∃! 𝑦 [ 𝑦 / 𝑥 ] 𝜑 ) )

Proof

Step Hyp Ref Expression
1 nfnf1 ⊢ Ⅎ 𝑦 Ⅎ 𝑦 𝜑
2 1 nfal ⊢ Ⅎ 𝑦 ∀ 𝑥 Ⅎ 𝑦 𝜑
3 equsb3 ⊢ ( [ 𝑣 / 𝑥 ] 𝑥 = 𝑢 ↔ 𝑣 = 𝑢 )
4 3 sblbis ⊢ ( [ 𝑣 / 𝑥 ] ( 𝜑 ↔ 𝑥 = 𝑢 ) ↔ ( [ 𝑣 / 𝑥 ] 𝜑 ↔ 𝑣 = 𝑢 ) )
5 wl-nfsbtv ⊢ ( ∀ 𝑥 Ⅎ 𝑦 𝜑 → Ⅎ 𝑦 [ 𝑣 / 𝑥 ] 𝜑 )
6 nfvd ⊢ ( ∀ 𝑥 Ⅎ 𝑦 𝜑 → Ⅎ 𝑦 𝑣 = 𝑢 )
7 5 6 nfbid ⊢ ( ∀ 𝑥 Ⅎ 𝑦 𝜑 → Ⅎ 𝑦 ( [ 𝑣 / 𝑥 ] 𝜑 ↔ 𝑣 = 𝑢 ) )
8 4 7 nfxfrd ⊢ ( ∀ 𝑥 Ⅎ 𝑦 𝜑 → Ⅎ 𝑦 [ 𝑣 / 𝑥 ] ( 𝜑 ↔ 𝑥 = 𝑢 ) )
9 sbequ ⊢ ( 𝑣 = 𝑦 → ( [ 𝑣 / 𝑥 ] ( 𝜑 ↔ 𝑥 = 𝑢 ) ↔ [ 𝑦 / 𝑥 ] ( 𝜑 ↔ 𝑥 = 𝑢 ) ) )
10 9 a1i ⊢ ( ∀ 𝑥 Ⅎ 𝑦 𝜑 → ( 𝑣 = 𝑦 → ( [ 𝑣 / 𝑥 ] ( 𝜑 ↔ 𝑥 = 𝑢 ) ↔ [ 𝑦 / 𝑥 ] ( 𝜑 ↔ 𝑥 = 𝑢 ) ) ) )
11 2 8 10 cbvaldw ⊢ ( ∀ 𝑥 Ⅎ 𝑦 𝜑 → ( ∀ 𝑣 [ 𝑣 / 𝑥 ] ( 𝜑 ↔ 𝑥 = 𝑢 ) ↔ ∀ 𝑦 [ 𝑦 / 𝑥 ] ( 𝜑 ↔ 𝑥 = 𝑢 ) ) )
12 sb8v ⊢ ( ∀ 𝑥 ( 𝜑 ↔ 𝑥 = 𝑢 ) ↔ ∀ 𝑣 [ 𝑣 / 𝑥 ] ( 𝜑 ↔ 𝑥 = 𝑢 ) )
13 12 bicomi ⊢ ( ∀ 𝑣 [ 𝑣 / 𝑥 ] ( 𝜑 ↔ 𝑥 = 𝑢 ) ↔ ∀ 𝑥 ( 𝜑 ↔ 𝑥 = 𝑢 ) )
14 equsb3 ⊢ ( [ 𝑦 / 𝑥 ] 𝑥 = 𝑢 ↔ 𝑦 = 𝑢 )
15 14 sblbis ⊢ ( [ 𝑦 / 𝑥 ] ( 𝜑 ↔ 𝑥 = 𝑢 ) ↔ ( [ 𝑦 / 𝑥 ] 𝜑 ↔ 𝑦 = 𝑢 ) )
16 15 albii ⊢ ( ∀ 𝑦 [ 𝑦 / 𝑥 ] ( 𝜑 ↔ 𝑥 = 𝑢 ) ↔ ∀ 𝑦 ( [ 𝑦 / 𝑥 ] 𝜑 ↔ 𝑦 = 𝑢 ) )
17 11 13 16 3bitr3g ⊢ ( ∀ 𝑥 Ⅎ 𝑦 𝜑 → ( ∀ 𝑥 ( 𝜑 ↔ 𝑥 = 𝑢 ) ↔ ∀ 𝑦 ( [ 𝑦 / 𝑥 ] 𝜑 ↔ 𝑦 = 𝑢 ) ) )
18 17 exbidv ⊢ ( ∀ 𝑥 Ⅎ 𝑦 𝜑 → ( ∃ 𝑢 ∀ 𝑥 ( 𝜑 ↔ 𝑥 = 𝑢 ) ↔ ∃ 𝑢 ∀ 𝑦 ( [ 𝑦 / 𝑥 ] 𝜑 ↔ 𝑦 = 𝑢 ) ) )
19 eu6 ⊢ ( ∃! 𝑥 𝜑 ↔ ∃ 𝑢 ∀ 𝑥 ( 𝜑 ↔ 𝑥 = 𝑢 ) )
20 eu6 ⊢ ( ∃! 𝑦 [ 𝑦 / 𝑥 ] 𝜑 ↔ ∃ 𝑢 ∀ 𝑦 ( [ 𝑦 / 𝑥 ] 𝜑 ↔ 𝑦 = 𝑢 ) )
21 18 19 20 3bitr4g ⊢ ( ∀ 𝑥 Ⅎ 𝑦 𝜑 → ( ∃! 𝑥 𝜑 ↔ ∃! 𝑦 [ 𝑦 / 𝑥 ] 𝜑 ) )