Metamath Proof Explorer


Theorem bhmafibid1

Description: The Brahmagupta-Fibonacci identity. Express the product of two sums of two squares as a sum of two squares. First result. Remark: The proof uses a different approach than the proof of bhmafibid1cn , and is a little bit shorter. (Contributed by Thierry Arnoux, 1-Feb-2020) (Proof modification is discouraged.)

Ref Expression
Assertion bhmafibid1 ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ → A 2 + B 2 ⁢ C 2 + D 2 = A ⁢ C − B ⁢ D 2 + A ⁢ D + B ⁢ C 2

Proof

Step Hyp Ref Expression
1 simpll ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ → A ∈ ℝ
2 1 recnd ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ → A ∈ ℂ
3 ax-icn ⊢ i ∈ ℂ
4 3 a1i ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ → i ∈ ℂ
5 simplr ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ → B ∈ ℝ
6 5 recnd ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ → B ∈ ℂ
7 4 6 mulcld ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ → i ⁢ B ∈ ℂ
8 2 7 addcld ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ → A + i ⁢ B ∈ ℂ
9 simprl ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ → C ∈ ℝ
10 9 recnd ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ → C ∈ ℂ
11 simprr ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ → D ∈ ℝ
12 11 recnd ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ → D ∈ ℂ
13 4 12 mulcld ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ → i ⁢ D ∈ ℂ
14 10 13 addcld ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ → C + i ⁢ D ∈ ℂ
15 8 14 mulcld ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ → A + i ⁢ B ⁢ C + i ⁢ D ∈ ℂ
16 15 replimd ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ → A + i ⁢ B ⁢ C + i ⁢ D = ℜ ⁡ A + i ⁢ B ⁢ C + i ⁢ D + i ⁢ ℑ ⁡ A + i ⁢ B ⁢ C + i ⁢ D
17 8 14 remuld ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ → ℜ ⁡ A + i ⁢ B ⁢ C + i ⁢ D = ℜ ⁡ A + i ⁢ B ⁢ ℜ ⁡ C + i ⁢ D − ℑ ⁡ A + i ⁢ B ⁢ ℑ ⁡ C + i ⁢ D
18 1 5 crred ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ → ℜ ⁡ A + i ⁢ B = A
19 9 11 crred ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ → ℜ ⁡ C + i ⁢ D = C
20 18 19 oveq12d ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ → ℜ ⁡ A + i ⁢ B ⁢ ℜ ⁡ C + i ⁢ D = A ⁢ C
21 1 5 crimd ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ → ℑ ⁡ A + i ⁢ B = B
22 9 11 crimd ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ → ℑ ⁡ C + i ⁢ D = D
23 21 22 oveq12d ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ → ℑ ⁡ A + i ⁢ B ⁢ ℑ ⁡ C + i ⁢ D = B ⁢ D
24 20 23 oveq12d ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ → ℜ ⁡ A + i ⁢ B ⁢ ℜ ⁡ C + i ⁢ D − ℑ ⁡ A + i ⁢ B ⁢ ℑ ⁡ C + i ⁢ D = A ⁢ C − B ⁢ D
25 17 24 eqtrd ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ → ℜ ⁡ A + i ⁢ B ⁢ C + i ⁢ D = A ⁢ C − B ⁢ D
26 8 14 immuld ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ → ℑ ⁡ A + i ⁢ B ⁢ C + i ⁢ D = ℜ ⁡ A + i ⁢ B ⁢ ℑ ⁡ C + i ⁢ D + ℑ ⁡ A + i ⁢ B ⁢ ℜ ⁡ C + i ⁢ D
27 18 22 oveq12d ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ → ℜ ⁡ A + i ⁢ B ⁢ ℑ ⁡ C + i ⁢ D = A ⁢ D
28 21 19 oveq12d ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ → ℑ ⁡ A + i ⁢ B ⁢ ℜ ⁡ C + i ⁢ D = B ⁢ C
29 27 28 oveq12d ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ → ℜ ⁡ A + i ⁢ B ⁢ ℑ ⁡ C + i ⁢ D + ℑ ⁡ A + i ⁢ B ⁢ ℜ ⁡ C + i ⁢ D = A ⁢ D + B ⁢ C
30 26 29 eqtrd ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ → ℑ ⁡ A + i ⁢ B ⁢ C + i ⁢ D = A ⁢ D + B ⁢ C
31 30 oveq2d ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ → i ⁢ ℑ ⁡ A + i ⁢ B ⁢ C + i ⁢ D = i ⁢ A ⁢ D + B ⁢ C
32 25 31 oveq12d ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ → ℜ ⁡ A + i ⁢ B ⁢ C + i ⁢ D + i ⁢ ℑ ⁡ A + i ⁢ B ⁢ C + i ⁢ D = A ⁢ C - B ⁢ D + i ⁢ A ⁢ D + B ⁢ C
33 16 32 eqtrd ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ → A + i ⁢ B ⁢ C + i ⁢ D = A ⁢ C - B ⁢ D + i ⁢ A ⁢ D + B ⁢ C
34 33 fveq2d ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ → A + i ⁢ B ⁢ C + i ⁢ D = A ⁢ C - B ⁢ D + i ⁢ A ⁢ D + B ⁢ C
35 34 oveq1d ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ → A + i ⁢ B ⁢ C + i ⁢ D 2 = A ⁢ C - B ⁢ D + i ⁢ A ⁢ D + B ⁢ C 2
36 8 14 absmuld ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ → A + i ⁢ B ⁢ C + i ⁢ D = A + i ⁢ B ⁢ C + i ⁢ D
37 36 oveq1d ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ → A + i ⁢ B ⁢ C + i ⁢ D 2 = A + i ⁢ B ⁢ C + i ⁢ D 2
38 8 abscld ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ → A + i ⁢ B ∈ ℝ
39 38 recnd ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ → A + i ⁢ B ∈ ℂ
40 14 abscld ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ → C + i ⁢ D ∈ ℝ
41 40 recnd ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ → C + i ⁢ D ∈ ℂ
42 39 41 sqmuld ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ → A + i ⁢ B ⁢ C + i ⁢ D 2 = A + i ⁢ B 2 ⁢ C + i ⁢ D 2
43 absreimsq ⊢ A ∈ ℝ ∧ B ∈ ℝ → A + i ⁢ B 2 = A 2 + B 2
44 absreimsq ⊢ C ∈ ℝ ∧ D ∈ ℝ → C + i ⁢ D 2 = C 2 + D 2
45 43 44 oveqan12d ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ → A + i ⁢ B 2 ⁢ C + i ⁢ D 2 = A 2 + B 2 ⁢ C 2 + D 2
46 37 42 45 3eqtrd ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ → A + i ⁢ B ⁢ C + i ⁢ D 2 = A 2 + B 2 ⁢ C 2 + D 2
47 1 9 remulcld ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ → A ⁢ C ∈ ℝ
48 5 11 remulcld ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ → B ⁢ D ∈ ℝ
49 47 48 resubcld ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ → A ⁢ C − B ⁢ D ∈ ℝ
50 1 11 remulcld ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ → A ⁢ D ∈ ℝ
51 5 9 remulcld ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ → B ⁢ C ∈ ℝ
52 50 51 readdcld ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ → A ⁢ D + B ⁢ C ∈ ℝ
53 absreimsq ⊢ A ⁢ C − B ⁢ D ∈ ℝ ∧ A ⁢ D + B ⁢ C ∈ ℝ → A ⁢ C - B ⁢ D + i ⁢ A ⁢ D + B ⁢ C 2 = A ⁢ C − B ⁢ D 2 + A ⁢ D + B ⁢ C 2
54 49 52 53 syl2anc ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ → A ⁢ C - B ⁢ D + i ⁢ A ⁢ D + B ⁢ C 2 = A ⁢ C − B ⁢ D 2 + A ⁢ D + B ⁢ C 2
55 35 46 54 3eqtr3d ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ → A 2 + B 2 ⁢ C 2 + D 2 = A ⁢ C − B ⁢ D 2 + A ⁢ D + B ⁢ C 2