Metamath Proof Explorer


Theorem bnj1190

Description: Technical lemma for bnj69 . This lemma may no longer be used or have become an indirect lemma of the theorem in question (i.e. a lemma of a lemma... of the theorem). (Contributed by Jonathan Ben-Naim, 3-Jun-2011) (New usage is discouraged.)

Ref Expression
Hypotheses bnj1190.1 ⊢ φ ↔ R FrSe A ∧ B ⊆ A ∧ B ≠ ∅
bnj1190.2 ⊢ ψ ↔ x ∈ B ∧ y ∈ B ∧ y R x
Assertion bnj1190 ⊢ φ ∧ ψ → ∃ w ∈ B ∀ z ∈ B ¬ z R w

Proof

Step Hyp Ref Expression
1 bnj1190.1 ⊢ φ ↔ R FrSe A ∧ B ⊆ A ∧ B ≠ ∅
2 bnj1190.2 ⊢ ψ ↔ x ∈ B ∧ y ∈ B ∧ y R x
3 1 simp2bi ⊢ φ → B ⊆ A
4 3 adantr ⊢ φ ∧ ψ → B ⊆ A
5 eqid ⊢ trCl x A R ∩ B = trCl x A R ∩ B
6 1 simp1bi ⊢ φ → R FrSe A
7 6 adantr ⊢ φ ∧ ψ → R FrSe A
8 2 simp1bi ⊢ ψ → x ∈ B
9 ssel2 ⊢ B ⊆ A ∧ x ∈ B → x ∈ A
10 3 8 9 syl2an ⊢ φ ∧ ψ → x ∈ A
11 2 5 7 4 10 bnj1177 ⊢ φ ∧ ψ → R Fr A ∧ trCl x A R ∩ B ⊆ A ∧ trCl x A R ∩ B ≠ ∅ ∧ trCl x A R ∩ B ∈ V
12 bnj1154 ⊢ R Fr A ∧ trCl x A R ∩ B ⊆ A ∧ trCl x A R ∩ B ≠ ∅ ∧ trCl x A R ∩ B ∈ V → ∃ u ∈ trCl x A R ∩ B ∀ v ∈ trCl x A R ∩ B ¬ v R u
13 11 12 bnj1176 ⊢ ∃ u ∀ v φ ∧ ψ → u ∈ trCl x A R ∩ B ∧ R FrSe A ∧ x ∈ A ∧ u ∈ trCl x A R ∧ R FrSe A ∧ u ∈ A ∧ v ∈ A → v R u → ¬ v ∈ trCl x A R ∩ B
14 biid ⊢ R FrSe A ∧ x ∈ A ∧ u ∈ trCl x A R ∧ R FrSe A ∧ u ∈ A ∧ v ∈ A ∧ v R u ↔ R FrSe A ∧ x ∈ A ∧ u ∈ trCl x A R ∧ R FrSe A ∧ u ∈ A ∧ v ∈ A ∧ v R u
15 biid ⊢ R FrSe A ∧ x ∈ A ∧ u ∈ trCl x A R ∧ R FrSe A ∧ u ∈ A ∧ v ∈ A ↔ R FrSe A ∧ x ∈ A ∧ u ∈ trCl x A R ∧ R FrSe A ∧ u ∈ A ∧ v ∈ A
16 5 14 15 bnj1175 ⊢ R FrSe A ∧ x ∈ A ∧ u ∈ trCl x A R ∧ R FrSe A ∧ u ∈ A ∧ v ∈ A → v R u → v ∈ trCl x A R
17 5 13 16 bnj1174 ⊢ ∃ u ∀ v φ ∧ ψ → φ ∧ ψ ∧ u ∈ trCl x A R ∩ B ∧ R FrSe A ∧ x ∈ A ∧ u ∈ trCl x A R ∧ R FrSe A ∧ u ∈ A ∧ v ∈ A → v R u → ¬ v ∈ B
18 5 15 7 10 bnj1173 ⊢ φ ∧ ψ ∧ u ∈ trCl x A R ∩ B → R FrSe A ∧ x ∈ A ∧ u ∈ trCl x A R ∧ R FrSe A ∧ u ∈ A ∧ v ∈ A ↔ v ∈ A
19 5 17 18 bnj1172 ⊢ ∃ u ∀ v φ ∧ ψ → u ∈ B ∧ v ∈ A → v R u → ¬ v ∈ B
20 4 19 bnj1171 ⊢ ∃ u ∀ v φ ∧ ψ → u ∈ B ∧ v ∈ B → ¬ v R u
21 20 bnj1186 ⊢ φ ∧ ψ → ∃ u ∈ B ∀ v ∈ B ¬ v R u
22 21 bnj1185 ⊢ φ ∧ ψ → ∃ x ∈ B ∀ y ∈ B ¬ y R x
23 22 bnj1185 ⊢ φ ∧ ψ → ∃ w ∈ B ∀ z ∈ B ¬ z R w