Metamath Proof Explorer


Theorem cdlemk55u

Description: Part of proof of Lemma K of Crawley p. 118. Line 11, p. 120. G , I stand for g, h. X represents tau. (Contributed by NM, 31-Jul-2013)

Ref Expression
Hypotheses cdlemk5.b ⊢ B = Base K
cdlemk5.l ⊢ ≤ ˙ = ≤ K
cdlemk5.j ⊢ ∨ ˙ = join ⁡ K
cdlemk5.m ⊢ ∧ ˙ = meet ⁡ K
cdlemk5.a ⊢ A = Atoms ⁡ K
cdlemk5.h ⊢ H = LHyp ⁡ K
cdlemk5.t ⊢ T = LTrn ⁡ K ⁡ W
cdlemk5.r ⊢ R = trL ⁡ K ⁡ W
cdlemk5.z ⊢ Z = P ∨ ˙ R ⁡ b ∧ ˙ N ⁡ P ∨ ˙ R ⁡ b ∘ F -1
cdlemk5.y ⊢ Y = P ∨ ˙ R ⁡ g ∧ ˙ Z ∨ ˙ R ⁡ g ∘ b -1
cdlemk5.x ⊢ X = ι z ∈ T | ∀ b ∈ T b ≠ I ↾ B ∧ R ⁡ b ≠ R ⁡ F ∧ R ⁡ b ≠ R ⁡ g → z ⁡ P = Y
cdlemk5.u ⊢ U = g ∈ T ⟼ if F = N g X
Assertion cdlemk55u ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ N ∈ T ∧ R ⁡ F = R ⁡ N ∧ G ∈ T ∧ I ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W → U ⁡ G ∘ I = U ⁡ G ∘ U ⁡ I

Proof

Step Hyp Ref Expression
1 cdlemk5.b ⊢ B = Base K
2 cdlemk5.l ⊢ ≤ ˙ = ≤ K
3 cdlemk5.j ⊢ ∨ ˙ = join ⁡ K
4 cdlemk5.m ⊢ ∧ ˙ = meet ⁡ K
5 cdlemk5.a ⊢ A = Atoms ⁡ K
6 cdlemk5.h ⊢ H = LHyp ⁡ K
7 cdlemk5.t ⊢ T = LTrn ⁡ K ⁡ W
8 cdlemk5.r ⊢ R = trL ⁡ K ⁡ W
9 cdlemk5.z ⊢ Z = P ∨ ˙ R ⁡ b ∧ ˙ N ⁡ P ∨ ˙ R ⁡ b ∘ F -1
10 cdlemk5.y ⊢ Y = P ∨ ˙ R ⁡ g ∧ ˙ Z ∨ ˙ R ⁡ g ∘ b -1
11 cdlemk5.x ⊢ X = ι z ∈ T | ∀ b ∈ T b ≠ I ↾ B ∧ R ⁡ b ≠ R ⁡ F ∧ R ⁡ b ≠ R ⁡ g → z ⁡ P = Y
12 cdlemk5.u ⊢ U = g ∈ T ⟼ if F = N g X
13 simpr ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ N ∈ T ∧ R ⁡ F = R ⁡ N ∧ G ∈ T ∧ I ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ F = N → F = N
14 simp11 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ N ∈ T ∧ R ⁡ F = R ⁡ N ∧ G ∈ T ∧ I ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W → K ∈ HL ∧ W ∈ H
15 simp22 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ N ∈ T ∧ R ⁡ F = R ⁡ N ∧ G ∈ T ∧ I ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W → G ∈ T
16 simp23 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ N ∈ T ∧ R ⁡ F = R ⁡ N ∧ G ∈ T ∧ I ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W → I ∈ T
17 6 7 ltrnco ⊢ K ∈ HL ∧ W ∈ H ∧ G ∈ T ∧ I ∈ T → G ∘ I ∈ T
18 14 15 16 17 syl3anc ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ N ∈ T ∧ R ⁡ F = R ⁡ N ∧ G ∈ T ∧ I ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W → G ∘ I ∈ T
19 18 adantr ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ N ∈ T ∧ R ⁡ F = R ⁡ N ∧ G ∈ T ∧ I ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ F = N → G ∘ I ∈ T
20 11 12 cdlemk40t ⊢ F = N ∧ G ∘ I ∈ T → U ⁡ G ∘ I = G ∘ I
21 13 19 20 syl2anc ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ N ∈ T ∧ R ⁡ F = R ⁡ N ∧ G ∈ T ∧ I ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ F = N → U ⁡ G ∘ I = G ∘ I
22 simpl22 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ N ∈ T ∧ R ⁡ F = R ⁡ N ∧ G ∈ T ∧ I ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ F = N → G ∈ T
23 11 12 cdlemk40t ⊢ F = N ∧ G ∈ T → U ⁡ G = G
24 13 22 23 syl2anc ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ N ∈ T ∧ R ⁡ F = R ⁡ N ∧ G ∈ T ∧ I ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ F = N → U ⁡ G = G
25 simpl23 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ N ∈ T ∧ R ⁡ F = R ⁡ N ∧ G ∈ T ∧ I ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ F = N → I ∈ T
26 11 12 cdlemk40t ⊢ F = N ∧ I ∈ T → U ⁡ I = I
27 13 25 26 syl2anc ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ N ∈ T ∧ R ⁡ F = R ⁡ N ∧ G ∈ T ∧ I ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ F = N → U ⁡ I = I
28 24 27 coeq12d ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ N ∈ T ∧ R ⁡ F = R ⁡ N ∧ G ∈ T ∧ I ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ F = N → U ⁡ G ∘ U ⁡ I = G ∘ I
29 21 28 eqtr4d ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ N ∈ T ∧ R ⁡ F = R ⁡ N ∧ G ∈ T ∧ I ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ F = N → U ⁡ G ∘ I = U ⁡ G ∘ U ⁡ I
30 simpl1 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ N ∈ T ∧ R ⁡ F = R ⁡ N ∧ G ∈ T ∧ I ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ F ≠ N → K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ N ∈ T
31 simpl21 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ N ∈ T ∧ R ⁡ F = R ⁡ N ∧ G ∈ T ∧ I ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ F ≠ N → R ⁡ F = R ⁡ N
32 simpr ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ N ∈ T ∧ R ⁡ F = R ⁡ N ∧ G ∈ T ∧ I ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ F ≠ N → F ≠ N
33 31 32 jca ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ N ∈ T ∧ R ⁡ F = R ⁡ N ∧ G ∈ T ∧ I ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ F ≠ N → R ⁡ F = R ⁡ N ∧ F ≠ N
34 simpl22 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ N ∈ T ∧ R ⁡ F = R ⁡ N ∧ G ∈ T ∧ I ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ F ≠ N → G ∈ T
35 simpl23 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ N ∈ T ∧ R ⁡ F = R ⁡ N ∧ G ∈ T ∧ I ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ F ≠ N → I ∈ T
36 simpl3 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ N ∈ T ∧ R ⁡ F = R ⁡ N ∧ G ∈ T ∧ I ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ F ≠ N → P ∈ A ∧ ¬ P ≤ ˙ W
37 1 2 3 4 5 6 7 8 9 10 11 12 cdlemk55u1 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ N ∈ T ∧ R ⁡ F = R ⁡ N ∧ F ≠ N ∧ G ∈ T ∧ I ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W → U ⁡ G ∘ I = U ⁡ G ∘ U ⁡ I
38 30 33 34 35 36 37 syl131anc ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ N ∈ T ∧ R ⁡ F = R ⁡ N ∧ G ∈ T ∧ I ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ F ≠ N → U ⁡ G ∘ I = U ⁡ G ∘ U ⁡ I
39 29 38 pm2.61dane ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ N ∈ T ∧ R ⁡ F = R ⁡ N ∧ G ∈ T ∧ I ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W → U ⁡ G ∘ I = U ⁡ G ∘ U ⁡ I