Metamath Proof Explorer


Theorem dffrege76

Description: If from the two propositions that every result of an application of the procedure R to B has property f and that property f is hereditary in the R -sequence, it can be inferred, whatever f may be, that E has property f , then we say E follows B in the R -sequence. Definition 76 of Frege1879 p. 60.

Each of B , E and R must be sets. (Contributed by RP, 2-Jul-2020)

Ref Expression
Hypotheses frege76.b ⊢ B ∈ U
frege76.e ⊢ E ∈ V
frege76.r ⊢ R ∈ W
Assertion dffrege76 ⊢ ∀ f R hereditary f → ∀ a B R a → a ∈ f → E ∈ f ↔ B t+ ⁡ R E

Proof

Step Hyp Ref Expression
1 frege76.b ⊢ B ∈ U
2 frege76.e ⊢ E ∈ V
3 frege76.r ⊢ R ∈ W
4 brtrclfv2 ⊢ B ∈ U ∧ E ∈ V ∧ R ∈ W → B t+ ⁡ R E ↔ E ∈ ⋂ f | R B ∪ f ⊆ f
5 1 2 3 4 mp3an ⊢ B t+ ⁡ R E ↔ E ∈ ⋂ f | R B ∪ f ⊆ f
6 2 elexi ⊢ E ∈ V
7 6 elintab ⊢ E ∈ ⋂ f | R B ∪ f ⊆ f ↔ ∀ f R B ∪ f ⊆ f → E ∈ f
8 imaundi ⊢ R B ∪ f = R B ∪ R f
9 8 equncomi ⊢ R B ∪ f = R f ∪ R B
10 9 sseq1i ⊢ R B ∪ f ⊆ f ↔ R f ∪ R B ⊆ f
11 unss ⊢ R f ⊆ f ∧ R B ⊆ f ↔ R f ∪ R B ⊆ f
12 10 11 bitr4i ⊢ R B ∪ f ⊆ f ↔ R f ⊆ f ∧ R B ⊆ f
13 df-he ⊢ R hereditary f ↔ R f ⊆ f
14 13 bicomi ⊢ R f ⊆ f ↔ R hereditary f
15 df-ss ⊢ R B ⊆ f ↔ ∀ a a ∈ R B → a ∈ f
16 1 elexi ⊢ B ∈ V
17 vex ⊢ a ∈ V
18 16 17 elimasn ⊢ a ∈ R B ↔ B a ∈ R
19 df-br ⊢ B R a ↔ B a ∈ R
20 18 19 bitr4i ⊢ a ∈ R B ↔ B R a
21 20 imbi1i ⊢ a ∈ R B → a ∈ f ↔ B R a → a ∈ f
22 21 albii ⊢ ∀ a a ∈ R B → a ∈ f ↔ ∀ a B R a → a ∈ f
23 15 22 bitri ⊢ R B ⊆ f ↔ ∀ a B R a → a ∈ f
24 14 23 anbi12i ⊢ R f ⊆ f ∧ R B ⊆ f ↔ R hereditary f ∧ ∀ a B R a → a ∈ f
25 12 24 bitri ⊢ R B ∪ f ⊆ f ↔ R hereditary f ∧ ∀ a B R a → a ∈ f
26 25 imbi1i ⊢ R B ∪ f ⊆ f → E ∈ f ↔ R hereditary f ∧ ∀ a B R a → a ∈ f → E ∈ f
27 impexp ⊢ R hereditary f ∧ ∀ a B R a → a ∈ f → E ∈ f ↔ R hereditary f → ∀ a B R a → a ∈ f → E ∈ f
28 26 27 bitri ⊢ R B ∪ f ⊆ f → E ∈ f ↔ R hereditary f → ∀ a B R a → a ∈ f → E ∈ f
29 28 albii ⊢ ∀ f R B ∪ f ⊆ f → E ∈ f ↔ ∀ f R hereditary f → ∀ a B R a → a ∈ f → E ∈ f
30 5 7 29 3bitrri ⊢ ∀ f R hereditary f → ∀ a B R a → a ∈ f → E ∈ f ↔ B t+ ⁡ R E