Metamath Proof Explorer


Theorem ditgeqiooicc

Description: A function F on an open interval, has the same directed integral as its extension G on the closed interval. (Contributed by Glauco Siliprandi, 11-Dec-2019)

Ref Expression
Hypotheses ditgeqiooicc.1 ⊢ G = x ∈ A B ⟼ if x = A R if x = B L F ⁡ x
ditgeqiooicc.2 ⊢ φ → A ∈ ℝ
ditgeqiooicc.3 ⊢ φ → B ∈ ℝ
ditgeqiooicc.4 ⊢ φ → A ≤ B
ditgeqiooicc.5 ⊢ φ → F : A B ⟶ ℝ
Assertion ditgeqiooicc ⊢ φ → ∫ A B F ⁡ x dx = ∫ A B G ⁡ x dx

Proof

Step Hyp Ref Expression
1 ditgeqiooicc.1 ⊢ G = x ∈ A B ⟼ if x = A R if x = B L F ⁡ x
2 ditgeqiooicc.2 ⊢ φ → A ∈ ℝ
3 ditgeqiooicc.3 ⊢ φ → B ∈ ℝ
4 ditgeqiooicc.4 ⊢ φ → A ≤ B
5 ditgeqiooicc.5 ⊢ φ → F : A B ⟶ ℝ
6 ioossicc ⊢ A B ⊆ A B
7 6 sseli ⊢ x ∈ A B → x ∈ A B
8 7 adantl ⊢ φ ∧ x ∈ A B → x ∈ A B
9 2 adantr ⊢ φ ∧ x ∈ A B → A ∈ ℝ
10 simpr ⊢ φ ∧ x ∈ A B → x ∈ A B
11 9 rexrd ⊢ φ ∧ x ∈ A B → A ∈ ℝ *
12 3 adantr ⊢ φ ∧ x ∈ A B → B ∈ ℝ
13 12 rexrd ⊢ φ ∧ x ∈ A B → B ∈ ℝ *
14 elioo2 ⊢ A ∈ ℝ * ∧ B ∈ ℝ * → x ∈ A B ↔ x ∈ ℝ ∧ A < x ∧ x < B
15 11 13 14 syl2anc ⊢ φ ∧ x ∈ A B → x ∈ A B ↔ x ∈ ℝ ∧ A < x ∧ x < B
16 10 15 mpbid ⊢ φ ∧ x ∈ A B → x ∈ ℝ ∧ A < x ∧ x < B
17 16 simp2d ⊢ φ ∧ x ∈ A B → A < x
18 9 17 gtned ⊢ φ ∧ x ∈ A B → x ≠ A
19 18 neneqd ⊢ φ ∧ x ∈ A B → ¬ x = A
20 19 iffalsed ⊢ φ ∧ x ∈ A B → if x = A R if x = B L F ⁡ x = if x = B L F ⁡ x
21 16 simp1d ⊢ φ ∧ x ∈ A B → x ∈ ℝ
22 16 simp3d ⊢ φ ∧ x ∈ A B → x < B
23 21 22 ltned ⊢ φ ∧ x ∈ A B → x ≠ B
24 23 neneqd ⊢ φ ∧ x ∈ A B → ¬ x = B
25 24 iffalsed ⊢ φ ∧ x ∈ A B → if x = B L F ⁡ x = F ⁡ x
26 20 25 eqtrd ⊢ φ ∧ x ∈ A B → if x = A R if x = B L F ⁡ x = F ⁡ x
27 5 ffvelcdmda ⊢ φ ∧ x ∈ A B → F ⁡ x ∈ ℝ
28 26 27 eqeltrd ⊢ φ ∧ x ∈ A B → if x = A R if x = B L F ⁡ x ∈ ℝ
29 1 fvmpt2 ⊢ x ∈ A B ∧ if x = A R if x = B L F ⁡ x ∈ ℝ → G ⁡ x = if x = A R if x = B L F ⁡ x
30 8 28 29 syl2anc ⊢ φ ∧ x ∈ A B → G ⁡ x = if x = A R if x = B L F ⁡ x
31 30 20 25 3eqtrrd ⊢ φ ∧ x ∈ A B → F ⁡ x = G ⁡ x
32 31 itgeq2dv ⊢ φ → ∫ A B F ⁡ x dx = ∫ A B G ⁡ x dx
33 4 ditgpos ⊢ φ → ∫ A B F ⁡ x dx = ∫ A B F ⁡ x dx
34 4 ditgpos ⊢ φ → ∫ A B G ⁡ x dx = ∫ A B G ⁡ x dx
35 32 33 34 3eqtr4d ⊢ φ → ∫ A B F ⁡ x dx = ∫ A B G ⁡ x dx