Metamath Proof Explorer


Theorem facp2

Description: The factorial of a successor's successor. (Contributed by metakunt, 19-Apr-2024)

Ref Expression
Assertion facp2 ⊢ N ∈ ℕ 0 → N + 2 ! = N ! ⁢ N + 1 ⁢ N + 2

Proof

Step Hyp Ref Expression
1 nn0cn ⊢ N ∈ ℕ 0 → N ∈ ℂ
2 ax-1cn ⊢ 1 ∈ ℂ
3 addass ⊢ N ∈ ℂ ∧ 1 ∈ ℂ ∧ 1 ∈ ℂ → N + 1 + 1 = N + 1 + 1
4 2 2 3 mp3an23 ⊢ N ∈ ℂ → N + 1 + 1 = N + 1 + 1
5 1 4 syl ⊢ N ∈ ℕ 0 → N + 1 + 1 = N + 1 + 1
6 df-2 ⊢ 2 = 1 + 1
7 6 oveq2i ⊢ N + 2 = N + 1 + 1
8 7 eqcomi ⊢ N + 1 + 1 = N + 2
9 8 a1i ⊢ N ∈ ℕ 0 → N + 1 + 1 = N + 2
10 5 9 eqtrd ⊢ N ∈ ℕ 0 → N + 1 + 1 = N + 2
11 10 fveq2d ⊢ N ∈ ℕ 0 → N + 1 + 1 ! = N + 2 !
12 peano2nn0 ⊢ N ∈ ℕ 0 → N + 1 ∈ ℕ 0
13 facp1 ⊢ N + 1 ∈ ℕ 0 → N + 1 + 1 ! = N + 1 ! ⁢ N + 1 + 1
14 12 13 syl ⊢ N ∈ ℕ 0 → N + 1 + 1 ! = N + 1 ! ⁢ N + 1 + 1
15 11 14 eqtr3d ⊢ N ∈ ℕ 0 → N + 2 ! = N + 1 ! ⁢ N + 1 + 1
16 10 oveq2d ⊢ N ∈ ℕ 0 → N + 1 ! ⁢ N + 1 + 1 = N + 1 ! ⁢ N + 2
17 15 16 eqtrd ⊢ N ∈ ℕ 0 → N + 2 ! = N + 1 ! ⁢ N + 2
18 facp1 ⊢ N ∈ ℕ 0 → N + 1 ! = N ! ⁢ N + 1
19 18 oveq1d ⊢ N ∈ ℕ 0 → N + 1 ! ⁢ N + 2 = N ! ⁢ N + 1 ⁢ N + 2
20 17 19 eqtrd ⊢ N ∈ ℕ 0 → N + 2 ! = N ! ⁢ N + 1 ⁢ N + 2
21 faccl ⊢ N ∈ ℕ 0 → N ! ∈ ℕ
22 nncn ⊢ N ! ∈ ℕ → N ! ∈ ℂ
23 21 22 syl ⊢ N ∈ ℕ 0 → N ! ∈ ℂ
24 nn0cn ⊢ N + 1 ∈ ℕ 0 → N + 1 ∈ ℂ
25 12 24 syl ⊢ N ∈ ℕ 0 → N + 1 ∈ ℂ
26 2cn ⊢ 2 ∈ ℂ
27 addcl ⊢ N ∈ ℂ ∧ 2 ∈ ℂ → N + 2 ∈ ℂ
28 26 27 mpan2 ⊢ N ∈ ℂ → N + 2 ∈ ℂ
29 1 28 syl ⊢ N ∈ ℕ 0 → N + 2 ∈ ℂ
30 mulass ⊢ N ! ∈ ℂ ∧ N + 1 ∈ ℂ ∧ N + 2 ∈ ℂ → N ! ⁢ N + 1 ⁢ N + 2 = N ! ⁢ N + 1 ⁢ N + 2
31 23 25 29 30 syl3anc ⊢ N ∈ ℕ 0 → N ! ⁢ N + 1 ⁢ N + 2 = N ! ⁢ N + 1 ⁢ N + 2
32 20 31 eqtrd ⊢ N ∈ ℕ 0 → N + 2 ! = N ! ⁢ N + 1 ⁢ N + 2