Metamath Proof Explorer


Theorem flt4lem5

Description: In the context of the lemmas of pythagtrip , M and N are coprime. (Contributed by SN, 23-Aug-2024)

Ref Expression
Hypotheses flt4lem5.1 ⊢ M = C + B + C − B 2
flt4lem5.2 ⊢ N = C + B − C − B 2
Assertion flt4lem5 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → M gcd N = 1

Proof

Step Hyp Ref Expression
1 flt4lem5.1 ⊢ M = C + B + C − B 2
2 flt4lem5.2 ⊢ N = C + B − C − B 2
3 simp3l ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → A gcd B = 1
4 simp11 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → A ∈ ℕ
5 simp12 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → B ∈ ℕ
6 coprmgcdb ⊢ A ∈ ℕ ∧ B ∈ ℕ → ∀ i ∈ ℕ i ∥ A ∧ i ∥ B → i = 1 ↔ A gcd B = 1
7 4 5 6 syl2anc ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → ∀ i ∈ ℕ i ∥ A ∧ i ∥ B → i = 1 ↔ A gcd B = 1
8 3 7 mpbird ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → ∀ i ∈ ℕ i ∥ A ∧ i ∥ B → i = 1
9 simplr ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A ∧ i ∈ ℕ ∧ i ∥ M ∧ i ∥ N → i ∈ ℕ
10 9 nnzd ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A ∧ i ∈ ℕ ∧ i ∥ M ∧ i ∥ N → i ∈ ℤ
11 1 pythagtriplem11 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → M ∈ ℕ
12 11 ad2antrr ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A ∧ i ∈ ℕ ∧ i ∥ M ∧ i ∥ N → M ∈ ℕ
13 12 nnsqcld ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A ∧ i ∈ ℕ ∧ i ∥ M ∧ i ∥ N → M 2 ∈ ℕ
14 13 nnzd ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A ∧ i ∈ ℕ ∧ i ∥ M ∧ i ∥ N → M 2 ∈ ℤ
15 2 pythagtriplem13 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → N ∈ ℕ
16 15 ad2antrr ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A ∧ i ∈ ℕ ∧ i ∥ M ∧ i ∥ N → N ∈ ℕ
17 16 nnsqcld ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A ∧ i ∈ ℕ ∧ i ∥ M ∧ i ∥ N → N 2 ∈ ℕ
18 17 nnzd ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A ∧ i ∈ ℕ ∧ i ∥ M ∧ i ∥ N → N 2 ∈ ℤ
19 simprl ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A ∧ i ∈ ℕ ∧ i ∥ M ∧ i ∥ N → i ∥ M
20 12 nnzd ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A ∧ i ∈ ℕ ∧ i ∥ M ∧ i ∥ N → M ∈ ℤ
21 2nn ⊢ 2 ∈ ℕ
22 21 a1i ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A ∧ i ∈ ℕ ∧ i ∥ M ∧ i ∥ N → 2 ∈ ℕ
23 dvdsexp2im ⊢ i ∈ ℤ ∧ M ∈ ℤ ∧ 2 ∈ ℕ → i ∥ M → i ∥ M 2
24 10 20 22 23 syl3anc ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A ∧ i ∈ ℕ ∧ i ∥ M ∧ i ∥ N → i ∥ M → i ∥ M 2
25 19 24 mpd ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A ∧ i ∈ ℕ ∧ i ∥ M ∧ i ∥ N → i ∥ M 2
26 simprr ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A ∧ i ∈ ℕ ∧ i ∥ M ∧ i ∥ N → i ∥ N
27 16 nnzd ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A ∧ i ∈ ℕ ∧ i ∥ M ∧ i ∥ N → N ∈ ℤ
28 dvdsexp2im ⊢ i ∈ ℤ ∧ N ∈ ℤ ∧ 2 ∈ ℕ → i ∥ N → i ∥ N 2
29 10 27 22 28 syl3anc ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A ∧ i ∈ ℕ ∧ i ∥ M ∧ i ∥ N → i ∥ N → i ∥ N 2
30 26 29 mpd ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A ∧ i ∈ ℕ ∧ i ∥ M ∧ i ∥ N → i ∥ N 2
31 10 14 18 25 30 dvds2subd ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A ∧ i ∈ ℕ ∧ i ∥ M ∧ i ∥ N → i ∥ M 2 − N 2
32 1 2 pythagtriplem15 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → A = M 2 − N 2
33 32 ad2antrr ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A ∧ i ∈ ℕ ∧ i ∥ M ∧ i ∥ N → A = M 2 − N 2
34 31 33 breqtrrd ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A ∧ i ∈ ℕ ∧ i ∥ M ∧ i ∥ N → i ∥ A
35 2z ⊢ 2 ∈ ℤ
36 35 a1i ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A ∧ i ∈ ℕ ∧ i ∥ M ∧ i ∥ N → 2 ∈ ℤ
37 12 16 nnmulcld ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A ∧ i ∈ ℕ ∧ i ∥ M ∧ i ∥ N → M ⋅ N ∈ ℕ
38 37 nnzd ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A ∧ i ∈ ℕ ∧ i ∥ M ∧ i ∥ N → M ⋅ N ∈ ℤ
39 10 20 27 26 dvdsmultr2d ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A ∧ i ∈ ℕ ∧ i ∥ M ∧ i ∥ N → i ∥ M ⋅ N
40 10 36 38 39 dvdsmultr2d ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A ∧ i ∈ ℕ ∧ i ∥ M ∧ i ∥ N → i ∥ 2 ⁢ M ⋅ N
41 1 2 pythagtriplem16 ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → B = 2 ⁢ M ⋅ N
42 41 ad2antrr ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A ∧ i ∈ ℕ ∧ i ∥ M ∧ i ∥ N → B = 2 ⁢ M ⋅ N
43 40 42 breqtrrd ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A ∧ i ∈ ℕ ∧ i ∥ M ∧ i ∥ N → i ∥ B
44 34 43 jca ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A ∧ i ∈ ℕ ∧ i ∥ M ∧ i ∥ N → i ∥ A ∧ i ∥ B
45 44 ex ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A ∧ i ∈ ℕ → i ∥ M ∧ i ∥ N → i ∥ A ∧ i ∥ B
46 45 imim1d ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A ∧ i ∈ ℕ → i ∥ A ∧ i ∥ B → i = 1 → i ∥ M ∧ i ∥ N → i = 1
47 46 ralimdva ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → ∀ i ∈ ℕ i ∥ A ∧ i ∥ B → i = 1 → ∀ i ∈ ℕ i ∥ M ∧ i ∥ N → i = 1
48 8 47 mpd ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → ∀ i ∈ ℕ i ∥ M ∧ i ∥ N → i = 1
49 coprmgcdb ⊢ M ∈ ℕ ∧ N ∈ ℕ → ∀ i ∈ ℕ i ∥ M ∧ i ∥ N → i = 1 ↔ M gcd N = 1
50 11 15 49 syl2anc ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → ∀ i ∈ ℕ i ∥ M ∧ i ∥ N → i = 1 ↔ M gcd N = 1
51 48 50 mpbid ⊢ A ∈ ℕ ∧ B ∈ ℕ ∧ C ∈ ℕ ∧ A 2 + B 2 = C 2 ∧ A gcd B = 1 ∧ ¬ 2 ∥ A → M gcd N = 1