Metamath Proof Explorer


Theorem fmtnorec2

Description: The second recurrence relation for Fermat numbers, see ProofWiki "Product of Sequence of Fermat Numbers plus 2", 29-Jul-2021, https://proofwiki.org/wiki/Product_of_Sequence_of_Fermat_Numbers_plus_2 or Wikipedia "Fermat number", 29-Jul-2021, https://en.wikipedia.org/wiki/Fermat_number#Basic_properties . (Contributed by AV, 29-Jul-2021)

Ref Expression
Assertion fmtnorec2 ⊢ N ∈ ℕ 0 → FermatNo ⁡ N + 1 = ∏ n = 0 N FermatNo ⁡ n + 2

Proof

Step Hyp Ref Expression
1 fvoveq1 ⊢ x = 0 → FermatNo ⁡ x + 1 = FermatNo ⁡ 0 + 1
2 oveq2 ⊢ x = 0 → 0 … x = 0 … 0
3 2 prodeq1d ⊢ x = 0 → ∏ n = 0 x FermatNo ⁡ n = ∏ n = 0 0 FermatNo ⁡ n
4 3 oveq1d ⊢ x = 0 → ∏ n = 0 x FermatNo ⁡ n + 2 = ∏ n = 0 0 FermatNo ⁡ n + 2
5 1 4 eqeq12d ⊢ x = 0 → FermatNo ⁡ x + 1 = ∏ n = 0 x FermatNo ⁡ n + 2 ↔ FermatNo ⁡ 0 + 1 = ∏ n = 0 0 FermatNo ⁡ n + 2
6 fvoveq1 ⊢ x = y → FermatNo ⁡ x + 1 = FermatNo ⁡ y + 1
7 oveq2 ⊢ x = y → 0 … x = 0 … y
8 7 prodeq1d ⊢ x = y → ∏ n = 0 x FermatNo ⁡ n = ∏ n = 0 y FermatNo ⁡ n
9 8 oveq1d ⊢ x = y → ∏ n = 0 x FermatNo ⁡ n + 2 = ∏ n = 0 y FermatNo ⁡ n + 2
10 6 9 eqeq12d ⊢ x = y → FermatNo ⁡ x + 1 = ∏ n = 0 x FermatNo ⁡ n + 2 ↔ FermatNo ⁡ y + 1 = ∏ n = 0 y FermatNo ⁡ n + 2
11 fvoveq1 ⊢ x = y + 1 → FermatNo ⁡ x + 1 = FermatNo ⁡ y + 1 + 1
12 oveq2 ⊢ x = y + 1 → 0 … x = 0 … y + 1
13 12 prodeq1d ⊢ x = y + 1 → ∏ n = 0 x FermatNo ⁡ n = ∏ n = 0 y + 1 FermatNo ⁡ n
14 13 oveq1d ⊢ x = y + 1 → ∏ n = 0 x FermatNo ⁡ n + 2 = ∏ n = 0 y + 1 FermatNo ⁡ n + 2
15 11 14 eqeq12d ⊢ x = y + 1 → FermatNo ⁡ x + 1 = ∏ n = 0 x FermatNo ⁡ n + 2 ↔ FermatNo ⁡ y + 1 + 1 = ∏ n = 0 y + 1 FermatNo ⁡ n + 2
16 fvoveq1 ⊢ x = N → FermatNo ⁡ x + 1 = FermatNo ⁡ N + 1
17 oveq2 ⊢ x = N → 0 … x = 0 … N
18 prodeq1 ⊢ 0 … x = 0 … N → ∏ n = 0 x FermatNo ⁡ n = ∏ n = 0 N FermatNo ⁡ n
19 18 oveq1d ⊢ 0 … x = 0 … N → ∏ n = 0 x FermatNo ⁡ n + 2 = ∏ n = 0 N FermatNo ⁡ n + 2
20 17 19 syl ⊢ x = N → ∏ n = 0 x FermatNo ⁡ n + 2 = ∏ n = 0 N FermatNo ⁡ n + 2
21 16 20 eqeq12d ⊢ x = N → FermatNo ⁡ x + 1 = ∏ n = 0 x FermatNo ⁡ n + 2 ↔ FermatNo ⁡ N + 1 = ∏ n = 0 N FermatNo ⁡ n + 2
22 fmtno0 ⊢ FermatNo ⁡ 0 = 3
23 22 oveq1i ⊢ FermatNo ⁡ 0 + 2 = 3 + 2
24 3p2e5 ⊢ 3 + 2 = 5
25 23 24 eqtri ⊢ FermatNo ⁡ 0 + 2 = 5
26 fz0sn ⊢ 0 … 0 = 0
27 26 prodeq1i ⊢ ∏ n = 0 0 FermatNo ⁡ n = ∏ n ∈ 0 FermatNo ⁡ n
28 0z ⊢ 0 ∈ ℤ
29 0nn0 ⊢ 0 ∈ ℕ 0
30 fmtnonn ⊢ 0 ∈ ℕ 0 → FermatNo ⁡ 0 ∈ ℕ
31 30 nncnd ⊢ 0 ∈ ℕ 0 → FermatNo ⁡ 0 ∈ ℂ
32 29 31 ax-mp ⊢ FermatNo ⁡ 0 ∈ ℂ
33 fveq2 ⊢ n = 0 → FermatNo ⁡ n = FermatNo ⁡ 0
34 33 prodsn ⊢ 0 ∈ ℤ ∧ FermatNo ⁡ 0 ∈ ℂ → ∏ n ∈ 0 FermatNo ⁡ n = FermatNo ⁡ 0
35 28 32 34 mp2an ⊢ ∏ n ∈ 0 FermatNo ⁡ n = FermatNo ⁡ 0
36 27 35 eqtri ⊢ ∏ n = 0 0 FermatNo ⁡ n = FermatNo ⁡ 0
37 36 oveq1i ⊢ ∏ n = 0 0 FermatNo ⁡ n + 2 = FermatNo ⁡ 0 + 2
38 0p1e1 ⊢ 0 + 1 = 1
39 38 fveq2i ⊢ FermatNo ⁡ 0 + 1 = FermatNo ⁡ 1
40 fmtno1 ⊢ FermatNo ⁡ 1 = 5
41 39 40 eqtri ⊢ FermatNo ⁡ 0 + 1 = 5
42 25 37 41 3eqtr4ri ⊢ FermatNo ⁡ 0 + 1 = ∏ n = 0 0 FermatNo ⁡ n + 2
43 fmtnorec2lem ⊢ y ∈ ℕ 0 → FermatNo ⁡ y + 1 = ∏ n = 0 y FermatNo ⁡ n + 2 → FermatNo ⁡ y + 1 + 1 = ∏ n = 0 y + 1 FermatNo ⁡ n + 2
44 5 10 15 21 42 43 nn0ind ⊢ N ∈ ℕ 0 → FermatNo ⁡ N + 1 = ∏ n = 0 N FermatNo ⁡ n + 2