Metamath Proof Explorer


Theorem fsplit

Description: A function that can be used to feed a common value to both operands of an operation. Use as the second argument of a composition with the function of fpar in order to build compound functions such as ( x e. ( 0 [,) +oo ) |-> ( ( sqrtx ) + ( sinx ) ) ) . (Contributed by NM, 17-Sep-2007) Replace use of dfid2 with df-id . (Revised by BJ, 31-Dec-2023)

Ref Expression
Assertion fsplit ⊢ 1 st ↾ I -1 = x ∈ V ⟼ x x

Proof

Step Hyp Ref Expression
1 vex ⊢ x ∈ V
2 vex ⊢ y ∈ V
3 1 2 brcnv ⊢ x 1 st ↾ I -1 y ↔ y 1 st ↾ I x
4 1 brresi ⊢ y 1 st ↾ I x ↔ y ∈ I ∧ y 1 st x
5 19.42v ⊢ ∃ z 1 st ⁡ y = x ∧ y = z z ↔ 1 st ⁡ y = x ∧ ∃ z y = z z
6 vex ⊢ z ∈ V
7 6 6 op1std ⊢ y = z z → 1 st ⁡ y = z
8 7 eqeq1d ⊢ y = z z → 1 st ⁡ y = x ↔ z = x
9 8 pm5.32ri ⊢ 1 st ⁡ y = x ∧ y = z z ↔ z = x ∧ y = z z
10 9 exbii ⊢ ∃ z 1 st ⁡ y = x ∧ y = z z ↔ ∃ z z = x ∧ y = z z
11 fo1st ⊢ 1 st : V ⟶ onto V
12 fofn ⊢ 1 st : V ⟶ onto V → 1 st Fn V
13 11 12 ax-mp ⊢ 1 st Fn V
14 fnbrfvb ⊢ 1 st Fn V ∧ y ∈ V → 1 st ⁡ y = x ↔ y 1 st x
15 13 2 14 mp2an ⊢ 1 st ⁡ y = x ↔ y 1 st x
16 df-id ⊢ I = z t | z = t
17 16 eleq2i ⊢ y ∈ I ↔ y ∈ z t | z = t
18 elopab ⊢ y ∈ z t | z = t ↔ ∃ z ∃ t y = z t ∧ z = t
19 ancom ⊢ y = z t ∧ z = t ↔ z = t ∧ y = z t
20 equcom ⊢ z = t ↔ t = z
21 20 anbi1i ⊢ z = t ∧ y = z t ↔ t = z ∧ y = z t
22 opeq2 ⊢ t = z → z t = z z
23 22 eqeq2d ⊢ t = z → y = z t ↔ y = z z
24 23 pm5.32i ⊢ t = z ∧ y = z t ↔ t = z ∧ y = z z
25 19 21 24 3bitri ⊢ y = z t ∧ z = t ↔ t = z ∧ y = z z
26 25 exbii ⊢ ∃ t y = z t ∧ z = t ↔ ∃ t t = z ∧ y = z z
27 biidd ⊢ t = z → y = z z ↔ y = z z
28 27 equsexvw ⊢ ∃ t t = z ∧ y = z z ↔ y = z z
29 26 28 bitri ⊢ ∃ t y = z t ∧ z = t ↔ y = z z
30 29 exbii ⊢ ∃ z ∃ t y = z t ∧ z = t ↔ ∃ z y = z z
31 17 18 30 3bitrri ⊢ ∃ z y = z z ↔ y ∈ I
32 15 31 anbi12ci ⊢ 1 st ⁡ y = x ∧ ∃ z y = z z ↔ y ∈ I ∧ y 1 st x
33 5 10 32 3bitr3ri ⊢ y ∈ I ∧ y 1 st x ↔ ∃ z z = x ∧ y = z z
34 id ⊢ z = x → z = x
35 34 34 opeq12d ⊢ z = x → z z = x x
36 35 eqeq2d ⊢ z = x → y = z z ↔ y = x x
37 36 equsexvw ⊢ ∃ z z = x ∧ y = z z ↔ y = x x
38 33 37 bitri ⊢ y ∈ I ∧ y 1 st x ↔ y = x x
39 3 4 38 3bitri ⊢ x 1 st ↾ I -1 y ↔ y = x x
40 39 opabbii ⊢ x y | x 1 st ↾ I -1 y = x y | y = x x
41 relcnv ⊢ Rel ⁡ 1 st ↾ I -1
42 dfrel4v ⊢ Rel ⁡ 1 st ↾ I -1 ↔ 1 st ↾ I -1 = x y | x 1 st ↾ I -1 y
43 41 42 mpbi ⊢ 1 st ↾ I -1 = x y | x 1 st ↾ I -1 y
44 mptv ⊢ x ∈ V ⟼ x x = x y | y = x x
45 40 43 44 3eqtr4i ⊢ 1 st ↾ I -1 = x ∈ V ⟼ x x