Description: Lemma for fta : Discharge the auxiliary variables in ftalem5 . (Contributed by Mario Carneiro, 20-Sep-2014) (Proof shortened by AV, 28-Sep-2020)
Ref | Expression | ||
---|---|---|---|
Hypotheses | ftalem.1 | |
|
ftalem.2 | |
||
ftalem.3 | |
||
ftalem.4 | |
||
ftalem6.5 | |
||
Assertion | ftalem6 | |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | ftalem.1 | |
|
2 | ftalem.2 | |
|
3 | ftalem.3 | |
|
4 | ftalem.4 | |
|
5 | ftalem6.5 | |
|
6 | fveq2 | |
|
7 | 6 | neeq1d | |
8 | 7 | cbvrabv | |
9 | 8 | infeq1i | |
10 | eqid | |
|
11 | fveq2 | |
|
12 | oveq2 | |
|
13 | 11 12 | oveq12d | |
14 | 13 | fveq2d | |
15 | 14 | cbvsumv | |
16 | 15 | oveq1i | |
17 | 16 | oveq2i | |
18 | eqid | |
|
19 | 1 2 3 4 5 9 10 17 18 | ftalem5 | |