Metamath Proof Explorer


Theorem fvcosymgeq

Description: The values of two compositions of permutations are equal if the values of the composed permutations are pairwise equal. (Contributed by AV, 26-Jan-2019)

Ref Expression
Hypotheses gsmsymgrfix.s ⊢ S = SymGrp ⁡ N
gsmsymgrfix.b ⊢ B = Base S
gsmsymgreq.z ⊢ Z = SymGrp ⁡ M
gsmsymgreq.p ⊢ P = Base Z
gsmsymgreq.i ⊢ I = N ∩ M
Assertion fvcosymgeq ⊢ G ∈ B ∧ K ∈ P → X ∈ I ∧ G ⁡ X = K ⁡ X ∧ ∀ n ∈ I F ⁡ n = H ⁡ n → F ∘ G ⁡ X = H ∘ K ⁡ X

Proof

Step Hyp Ref Expression
1 gsmsymgrfix.s ⊢ S = SymGrp ⁡ N
2 gsmsymgrfix.b ⊢ B = Base S
3 gsmsymgreq.z ⊢ Z = SymGrp ⁡ M
4 gsmsymgreq.p ⊢ P = Base Z
5 gsmsymgreq.i ⊢ I = N ∩ M
6 1 2 symgbasf ⊢ G ∈ B → G : N ⟶ N
7 6 ffnd ⊢ G ∈ B → G Fn N
8 3 4 symgbasf ⊢ K ∈ P → K : M ⟶ M
9 8 ffnd ⊢ K ∈ P → K Fn M
10 7 9 anim12i ⊢ G ∈ B ∧ K ∈ P → G Fn N ∧ K Fn M
11 10 adantr ⊢ G ∈ B ∧ K ∈ P ∧ X ∈ I ∧ G ⁡ X = K ⁡ X ∧ ∀ n ∈ I F ⁡ n = H ⁡ n → G Fn N ∧ K Fn M
12 5 eleq2i ⊢ X ∈ I ↔ X ∈ N ∩ M
13 12 biimpi ⊢ X ∈ I → X ∈ N ∩ M
14 13 3ad2ant1 ⊢ X ∈ I ∧ G ⁡ X = K ⁡ X ∧ ∀ n ∈ I F ⁡ n = H ⁡ n → X ∈ N ∩ M
15 14 adantl ⊢ G ∈ B ∧ K ∈ P ∧ X ∈ I ∧ G ⁡ X = K ⁡ X ∧ ∀ n ∈ I F ⁡ n = H ⁡ n → X ∈ N ∩ M
16 simpr2 ⊢ G ∈ B ∧ K ∈ P ∧ X ∈ I ∧ G ⁡ X = K ⁡ X ∧ ∀ n ∈ I F ⁡ n = H ⁡ n → G ⁡ X = K ⁡ X
17 1 2 symgbasf1o ⊢ G ∈ B → G : N ⟶ 1-1 onto N
18 dff1o5 ⊢ G : N ⟶ 1-1 onto N ↔ G : N ⟶ 1-1 N ∧ ran ⁡ G = N
19 eqcom ⊢ ran ⁡ G = N ↔ N = ran ⁡ G
20 19 biimpi ⊢ ran ⁡ G = N → N = ran ⁡ G
21 18 20 simplbiim ⊢ G : N ⟶ 1-1 onto N → N = ran ⁡ G
22 17 21 syl ⊢ G ∈ B → N = ran ⁡ G
23 3 4 symgbasf1o ⊢ K ∈ P → K : M ⟶ 1-1 onto M
24 dff1o5 ⊢ K : M ⟶ 1-1 onto M ↔ K : M ⟶ 1-1 M ∧ ran ⁡ K = M
25 eqcom ⊢ ran ⁡ K = M ↔ M = ran ⁡ K
26 25 biimpi ⊢ ran ⁡ K = M → M = ran ⁡ K
27 24 26 simplbiim ⊢ K : M ⟶ 1-1 onto M → M = ran ⁡ K
28 23 27 syl ⊢ K ∈ P → M = ran ⁡ K
29 22 28 ineqan12d ⊢ G ∈ B ∧ K ∈ P → N ∩ M = ran ⁡ G ∩ ran ⁡ K
30 5 29 eqtrid ⊢ G ∈ B ∧ K ∈ P → I = ran ⁡ G ∩ ran ⁡ K
31 30 raleqdv ⊢ G ∈ B ∧ K ∈ P → ∀ n ∈ I F ⁡ n = H ⁡ n ↔ ∀ n ∈ ran ⁡ G ∩ ran ⁡ K F ⁡ n = H ⁡ n
32 31 biimpcd ⊢ ∀ n ∈ I F ⁡ n = H ⁡ n → G ∈ B ∧ K ∈ P → ∀ n ∈ ran ⁡ G ∩ ran ⁡ K F ⁡ n = H ⁡ n
33 32 3ad2ant3 ⊢ X ∈ I ∧ G ⁡ X = K ⁡ X ∧ ∀ n ∈ I F ⁡ n = H ⁡ n → G ∈ B ∧ K ∈ P → ∀ n ∈ ran ⁡ G ∩ ran ⁡ K F ⁡ n = H ⁡ n
34 33 impcom ⊢ G ∈ B ∧ K ∈ P ∧ X ∈ I ∧ G ⁡ X = K ⁡ X ∧ ∀ n ∈ I F ⁡ n = H ⁡ n → ∀ n ∈ ran ⁡ G ∩ ran ⁡ K F ⁡ n = H ⁡ n
35 15 16 34 3jca ⊢ G ∈ B ∧ K ∈ P ∧ X ∈ I ∧ G ⁡ X = K ⁡ X ∧ ∀ n ∈ I F ⁡ n = H ⁡ n → X ∈ N ∩ M ∧ G ⁡ X = K ⁡ X ∧ ∀ n ∈ ran ⁡ G ∩ ran ⁡ K F ⁡ n = H ⁡ n
36 fvcofneq ⊢ G Fn N ∧ K Fn M → X ∈ N ∩ M ∧ G ⁡ X = K ⁡ X ∧ ∀ n ∈ ran ⁡ G ∩ ran ⁡ K F ⁡ n = H ⁡ n → F ∘ G ⁡ X = H ∘ K ⁡ X
37 11 35 36 sylc ⊢ G ∈ B ∧ K ∈ P ∧ X ∈ I ∧ G ⁡ X = K ⁡ X ∧ ∀ n ∈ I F ⁡ n = H ⁡ n → F ∘ G ⁡ X = H ∘ K ⁡ X
38 37 ex ⊢ G ∈ B ∧ K ∈ P → X ∈ I ∧ G ⁡ X = K ⁡ X ∧ ∀ n ∈ I F ⁡ n = H ⁡ n → F ∘ G ⁡ X = H ∘ K ⁡ X