Metamath Proof Explorer


Theorem hstel2

Description: Properties of a Hilbert-space-valued state. (Contributed by NM, 25-Jun-2006) (New usage is discouraged.)

Ref Expression
Assertion hstel2 ⊢ S ∈ CHStates ∧ A ∈ C ℋ ∧ B ∈ C ℋ ∧ A ⊆ ⊥ ⁡ B → S ⁡ A ⋅ ih S ⁡ B = 0 ∧ S ⁡ A ∨ ℋ B = S ⁡ A + ℎ S ⁡ B

Proof

Step Hyp Ref Expression
1 ishst ⊢ S ∈ CHStates ↔ S : C ℋ ⟶ ℋ ∧ norm ℎ ⁡ S ⁡ ℋ = 1 ∧ ∀ x ∈ C ℋ ∀ y ∈ C ℋ x ⊆ ⊥ ⁡ y → S ⁡ x ⋅ ih S ⁡ y = 0 ∧ S ⁡ x ∨ ℋ y = S ⁡ x + ℎ S ⁡ y
2 1 simp3bi ⊢ S ∈ CHStates → ∀ x ∈ C ℋ ∀ y ∈ C ℋ x ⊆ ⊥ ⁡ y → S ⁡ x ⋅ ih S ⁡ y = 0 ∧ S ⁡ x ∨ ℋ y = S ⁡ x + ℎ S ⁡ y
3 2 ad2antrr ⊢ S ∈ CHStates ∧ A ∈ C ℋ ∧ B ∈ C ℋ ∧ A ⊆ ⊥ ⁡ B → ∀ x ∈ C ℋ ∀ y ∈ C ℋ x ⊆ ⊥ ⁡ y → S ⁡ x ⋅ ih S ⁡ y = 0 ∧ S ⁡ x ∨ ℋ y = S ⁡ x + ℎ S ⁡ y
4 sseq1 ⊢ x = A → x ⊆ ⊥ ⁡ y ↔ A ⊆ ⊥ ⁡ y
5 fveq2 ⊢ x = A → S ⁡ x = S ⁡ A
6 5 oveq1d ⊢ x = A → S ⁡ x ⋅ ih S ⁡ y = S ⁡ A ⋅ ih S ⁡ y
7 6 eqeq1d ⊢ x = A → S ⁡ x ⋅ ih S ⁡ y = 0 ↔ S ⁡ A ⋅ ih S ⁡ y = 0
8 fvoveq1 ⊢ x = A → S ⁡ x ∨ ℋ y = S ⁡ A ∨ ℋ y
9 5 oveq1d ⊢ x = A → S ⁡ x + ℎ S ⁡ y = S ⁡ A + ℎ S ⁡ y
10 8 9 eqeq12d ⊢ x = A → S ⁡ x ∨ ℋ y = S ⁡ x + ℎ S ⁡ y ↔ S ⁡ A ∨ ℋ y = S ⁡ A + ℎ S ⁡ y
11 7 10 anbi12d ⊢ x = A → S ⁡ x ⋅ ih S ⁡ y = 0 ∧ S ⁡ x ∨ ℋ y = S ⁡ x + ℎ S ⁡ y ↔ S ⁡ A ⋅ ih S ⁡ y = 0 ∧ S ⁡ A ∨ ℋ y = S ⁡ A + ℎ S ⁡ y
12 4 11 imbi12d ⊢ x = A → x ⊆ ⊥ ⁡ y → S ⁡ x ⋅ ih S ⁡ y = 0 ∧ S ⁡ x ∨ ℋ y = S ⁡ x + ℎ S ⁡ y ↔ A ⊆ ⊥ ⁡ y → S ⁡ A ⋅ ih S ⁡ y = 0 ∧ S ⁡ A ∨ ℋ y = S ⁡ A + ℎ S ⁡ y
13 fveq2 ⊢ y = B → ⊥ ⁡ y = ⊥ ⁡ B
14 13 sseq2d ⊢ y = B → A ⊆ ⊥ ⁡ y ↔ A ⊆ ⊥ ⁡ B
15 fveq2 ⊢ y = B → S ⁡ y = S ⁡ B
16 15 oveq2d ⊢ y = B → S ⁡ A ⋅ ih S ⁡ y = S ⁡ A ⋅ ih S ⁡ B
17 16 eqeq1d ⊢ y = B → S ⁡ A ⋅ ih S ⁡ y = 0 ↔ S ⁡ A ⋅ ih S ⁡ B = 0
18 oveq2 ⊢ y = B → A ∨ ℋ y = A ∨ ℋ B
19 18 fveq2d ⊢ y = B → S ⁡ A ∨ ℋ y = S ⁡ A ∨ ℋ B
20 15 oveq2d ⊢ y = B → S ⁡ A + ℎ S ⁡ y = S ⁡ A + ℎ S ⁡ B
21 19 20 eqeq12d ⊢ y = B → S ⁡ A ∨ ℋ y = S ⁡ A + ℎ S ⁡ y ↔ S ⁡ A ∨ ℋ B = S ⁡ A + ℎ S ⁡ B
22 17 21 anbi12d ⊢ y = B → S ⁡ A ⋅ ih S ⁡ y = 0 ∧ S ⁡ A ∨ ℋ y = S ⁡ A + ℎ S ⁡ y ↔ S ⁡ A ⋅ ih S ⁡ B = 0 ∧ S ⁡ A ∨ ℋ B = S ⁡ A + ℎ S ⁡ B
23 14 22 imbi12d ⊢ y = B → A ⊆ ⊥ ⁡ y → S ⁡ A ⋅ ih S ⁡ y = 0 ∧ S ⁡ A ∨ ℋ y = S ⁡ A + ℎ S ⁡ y ↔ A ⊆ ⊥ ⁡ B → S ⁡ A ⋅ ih S ⁡ B = 0 ∧ S ⁡ A ∨ ℋ B = S ⁡ A + ℎ S ⁡ B
24 12 23 rspc2v ⊢ A ∈ C ℋ ∧ B ∈ C ℋ → ∀ x ∈ C ℋ ∀ y ∈ C ℋ x ⊆ ⊥ ⁡ y → S ⁡ x ⋅ ih S ⁡ y = 0 ∧ S ⁡ x ∨ ℋ y = S ⁡ x + ℎ S ⁡ y → A ⊆ ⊥ ⁡ B → S ⁡ A ⋅ ih S ⁡ B = 0 ∧ S ⁡ A ∨ ℋ B = S ⁡ A + ℎ S ⁡ B
25 24 com23 ⊢ A ∈ C ℋ ∧ B ∈ C ℋ → A ⊆ ⊥ ⁡ B → ∀ x ∈ C ℋ ∀ y ∈ C ℋ x ⊆ ⊥ ⁡ y → S ⁡ x ⋅ ih S ⁡ y = 0 ∧ S ⁡ x ∨ ℋ y = S ⁡ x + ℎ S ⁡ y → S ⁡ A ⋅ ih S ⁡ B = 0 ∧ S ⁡ A ∨ ℋ B = S ⁡ A + ℎ S ⁡ B
26 25 impr ⊢ A ∈ C ℋ ∧ B ∈ C ℋ ∧ A ⊆ ⊥ ⁡ B → ∀ x ∈ C ℋ ∀ y ∈ C ℋ x ⊆ ⊥ ⁡ y → S ⁡ x ⋅ ih S ⁡ y = 0 ∧ S ⁡ x ∨ ℋ y = S ⁡ x + ℎ S ⁡ y → S ⁡ A ⋅ ih S ⁡ B = 0 ∧ S ⁡ A ∨ ℋ B = S ⁡ A + ℎ S ⁡ B
27 26 adantll ⊢ S ∈ CHStates ∧ A ∈ C ℋ ∧ B ∈ C ℋ ∧ A ⊆ ⊥ ⁡ B → ∀ x ∈ C ℋ ∀ y ∈ C ℋ x ⊆ ⊥ ⁡ y → S ⁡ x ⋅ ih S ⁡ y = 0 ∧ S ⁡ x ∨ ℋ y = S ⁡ x + ℎ S ⁡ y → S ⁡ A ⋅ ih S ⁡ B = 0 ∧ S ⁡ A ∨ ℋ B = S ⁡ A + ℎ S ⁡ B
28 3 27 mpd ⊢ S ∈ CHStates ∧ A ∈ C ℋ ∧ B ∈ C ℋ ∧ A ⊆ ⊥ ⁡ B → S ⁡ A ⋅ ih S ⁡ B = 0 ∧ S ⁡ A ∨ ℋ B = S ⁡ A + ℎ S ⁡ B