Metamath Proof Explorer


Theorem hstoh

Description: A Hilbert-space-valued state orthogonal to the state of the lattice one is zero. (Contributed by NM, 25-Jun-2006) (New usage is discouraged.)

Ref Expression
Assertion hstoh ⊢ S ∈ CHStates ∧ A ∈ C ℋ ∧ S ⁡ A ⋅ ih S ⁡ ℋ = 0 → S ⁡ A = 0 ℎ

Proof

Step Hyp Ref Expression
1 hstcl ⊢ S ∈ CHStates ∧ A ∈ C ℋ → S ⁡ A ∈ ℋ
2 choccl ⊢ A ∈ C ℋ → ⊥ ⁡ A ∈ C ℋ
3 hstcl ⊢ S ∈ CHStates ∧ ⊥ ⁡ A ∈ C ℋ → S ⁡ ⊥ ⁡ A ∈ ℋ
4 2 3 sylan2 ⊢ S ∈ CHStates ∧ A ∈ C ℋ → S ⁡ ⊥ ⁡ A ∈ ℋ
5 his7 ⊢ S ⁡ A ∈ ℋ ∧ S ⁡ A ∈ ℋ ∧ S ⁡ ⊥ ⁡ A ∈ ℋ → S ⁡ A ⋅ ih S ⁡ A + ℎ S ⁡ ⊥ ⁡ A = S ⁡ A ⋅ ih S ⁡ A + S ⁡ A ⋅ ih S ⁡ ⊥ ⁡ A
6 1 1 4 5 syl3anc ⊢ S ∈ CHStates ∧ A ∈ C ℋ → S ⁡ A ⋅ ih S ⁡ A + ℎ S ⁡ ⊥ ⁡ A = S ⁡ A ⋅ ih S ⁡ A + S ⁡ A ⋅ ih S ⁡ ⊥ ⁡ A
7 normsq ⊢ S ⁡ A ∈ ℋ → norm ℎ ⁡ S ⁡ A 2 = S ⁡ A ⋅ ih S ⁡ A
8 1 7 syl ⊢ S ∈ CHStates ∧ A ∈ C ℋ → norm ℎ ⁡ S ⁡ A 2 = S ⁡ A ⋅ ih S ⁡ A
9 8 eqcomd ⊢ S ∈ CHStates ∧ A ∈ C ℋ → S ⁡ A ⋅ ih S ⁡ A = norm ℎ ⁡ S ⁡ A 2
10 ococ ⊢ A ∈ C ℋ → ⊥ ⁡ ⊥ ⁡ A = A
11 eqimss2 ⊢ ⊥ ⁡ ⊥ ⁡ A = A → A ⊆ ⊥ ⁡ ⊥ ⁡ A
12 10 11 syl ⊢ A ∈ C ℋ → A ⊆ ⊥ ⁡ ⊥ ⁡ A
13 2 12 jca ⊢ A ∈ C ℋ → ⊥ ⁡ A ∈ C ℋ ∧ A ⊆ ⊥ ⁡ ⊥ ⁡ A
14 13 adantl ⊢ S ∈ CHStates ∧ A ∈ C ℋ → ⊥ ⁡ A ∈ C ℋ ∧ A ⊆ ⊥ ⁡ ⊥ ⁡ A
15 hstorth ⊢ S ∈ CHStates ∧ A ∈ C ℋ ∧ ⊥ ⁡ A ∈ C ℋ ∧ A ⊆ ⊥ ⁡ ⊥ ⁡ A → S ⁡ A ⋅ ih S ⁡ ⊥ ⁡ A = 0
16 14 15 mpdan ⊢ S ∈ CHStates ∧ A ∈ C ℋ → S ⁡ A ⋅ ih S ⁡ ⊥ ⁡ A = 0
17 9 16 oveq12d ⊢ S ∈ CHStates ∧ A ∈ C ℋ → S ⁡ A ⋅ ih S ⁡ A + S ⁡ A ⋅ ih S ⁡ ⊥ ⁡ A = norm ℎ ⁡ S ⁡ A 2 + 0
18 normcl ⊢ S ⁡ A ∈ ℋ → norm ℎ ⁡ S ⁡ A ∈ ℝ
19 1 18 syl ⊢ S ∈ CHStates ∧ A ∈ C ℋ → norm ℎ ⁡ S ⁡ A ∈ ℝ
20 19 resqcld ⊢ S ∈ CHStates ∧ A ∈ C ℋ → norm ℎ ⁡ S ⁡ A 2 ∈ ℝ
21 20 recnd ⊢ S ∈ CHStates ∧ A ∈ C ℋ → norm ℎ ⁡ S ⁡ A 2 ∈ ℂ
22 21 addridd ⊢ S ∈ CHStates ∧ A ∈ C ℋ → norm ℎ ⁡ S ⁡ A 2 + 0 = norm ℎ ⁡ S ⁡ A 2
23 6 17 22 3eqtrrd ⊢ S ∈ CHStates ∧ A ∈ C ℋ → norm ℎ ⁡ S ⁡ A 2 = S ⁡ A ⋅ ih S ⁡ A + ℎ S ⁡ ⊥ ⁡ A
24 hstoc ⊢ S ∈ CHStates ∧ A ∈ C ℋ → S ⁡ A + ℎ S ⁡ ⊥ ⁡ A = S ⁡ ℋ
25 24 oveq2d ⊢ S ∈ CHStates ∧ A ∈ C ℋ → S ⁡ A ⋅ ih S ⁡ A + ℎ S ⁡ ⊥ ⁡ A = S ⁡ A ⋅ ih S ⁡ ℋ
26 23 25 eqtrd ⊢ S ∈ CHStates ∧ A ∈ C ℋ → norm ℎ ⁡ S ⁡ A 2 = S ⁡ A ⋅ ih S ⁡ ℋ
27 id ⊢ S ⁡ A ⋅ ih S ⁡ ℋ = 0 → S ⁡ A ⋅ ih S ⁡ ℋ = 0
28 26 27 sylan9eq ⊢ S ∈ CHStates ∧ A ∈ C ℋ ∧ S ⁡ A ⋅ ih S ⁡ ℋ = 0 → norm ℎ ⁡ S ⁡ A 2 = 0
29 28 3impa ⊢ S ∈ CHStates ∧ A ∈ C ℋ ∧ S ⁡ A ⋅ ih S ⁡ ℋ = 0 → norm ℎ ⁡ S ⁡ A 2 = 0
30 19 recnd ⊢ S ∈ CHStates ∧ A ∈ C ℋ → norm ℎ ⁡ S ⁡ A ∈ ℂ
31 sqeq0 ⊢ norm ℎ ⁡ S ⁡ A ∈ ℂ → norm ℎ ⁡ S ⁡ A 2 = 0 ↔ norm ℎ ⁡ S ⁡ A = 0
32 30 31 syl ⊢ S ∈ CHStates ∧ A ∈ C ℋ → norm ℎ ⁡ S ⁡ A 2 = 0 ↔ norm ℎ ⁡ S ⁡ A = 0
33 32 3adant3 ⊢ S ∈ CHStates ∧ A ∈ C ℋ ∧ S ⁡ A ⋅ ih S ⁡ ℋ = 0 → norm ℎ ⁡ S ⁡ A 2 = 0 ↔ norm ℎ ⁡ S ⁡ A = 0
34 29 33 mpbid ⊢ S ∈ CHStates ∧ A ∈ C ℋ ∧ S ⁡ A ⋅ ih S ⁡ ℋ = 0 → norm ℎ ⁡ S ⁡ A = 0
35 hst0h ⊢ S ∈ CHStates ∧ A ∈ C ℋ → norm ℎ ⁡ S ⁡ A = 0 ↔ S ⁡ A = 0 ℎ
36 35 3adant3 ⊢ S ∈ CHStates ∧ A ∈ C ℋ ∧ S ⁡ A ⋅ ih S ⁡ ℋ = 0 → norm ℎ ⁡ S ⁡ A = 0 ↔ S ⁡ A = 0 ℎ
37 34 36 mpbid ⊢ S ∈ CHStates ∧ A ∈ C ℋ ∧ S ⁡ A ⋅ ih S ⁡ ℋ = 0 → S ⁡ A = 0 ℎ