Metamath Proof Explorer


Theorem inf3lem5

Description: Lemma for our Axiom of Infinity => standard Axiom of Infinity. See inf3 for detailed description. (Contributed by NM, 29-Oct-1996)

Ref Expression
Hypotheses inf3lem.1 ⊢ G = y ∈ V ⟼ w ∈ x | w ∩ x ⊆ y
inf3lem.2 ⊢ F = rec ⁡ G ∅ ↾ ω
inf3lem.3 ⊢ A ∈ V
inf3lem.4 ⊢ B ∈ V
Assertion inf3lem5 ⊢ x ≠ ∅ ∧ x ⊆ ⋃ x → A ∈ ω ∧ B ∈ A → F ⁡ B ⊂ F ⁡ A

Proof

Step Hyp Ref Expression
1 inf3lem.1 ⊢ G = y ∈ V ⟼ w ∈ x | w ∩ x ⊆ y
2 inf3lem.2 ⊢ F = rec ⁡ G ∅ ↾ ω
3 inf3lem.3 ⊢ A ∈ V
4 inf3lem.4 ⊢ B ∈ V
5 elnn ⊢ B ∈ A ∧ A ∈ ω → B ∈ ω
6 5 ancoms ⊢ A ∈ ω ∧ B ∈ A → B ∈ ω
7 nnord ⊢ A ∈ ω → Ord ⁡ A
8 ordsucss ⊢ Ord ⁡ A → B ∈ A → suc ⁡ B ⊆ A
9 7 8 syl ⊢ A ∈ ω → B ∈ A → suc ⁡ B ⊆ A
10 9 adantr ⊢ A ∈ ω ∧ B ∈ ω → B ∈ A → suc ⁡ B ⊆ A
11 peano2b ⊢ B ∈ ω ↔ suc ⁡ B ∈ ω
12 fveq2 ⊢ v = suc ⁡ B → F ⁡ v = F ⁡ suc ⁡ B
13 12 psseq2d ⊢ v = suc ⁡ B → F ⁡ B ⊂ F ⁡ v ↔ F ⁡ B ⊂ F ⁡ suc ⁡ B
14 13 imbi2d ⊢ v = suc ⁡ B → x ≠ ∅ ∧ x ⊆ ⋃ x → F ⁡ B ⊂ F ⁡ v ↔ x ≠ ∅ ∧ x ⊆ ⋃ x → F ⁡ B ⊂ F ⁡ suc ⁡ B
15 fveq2 ⊢ v = u → F ⁡ v = F ⁡ u
16 15 psseq2d ⊢ v = u → F ⁡ B ⊂ F ⁡ v ↔ F ⁡ B ⊂ F ⁡ u
17 16 imbi2d ⊢ v = u → x ≠ ∅ ∧ x ⊆ ⋃ x → F ⁡ B ⊂ F ⁡ v ↔ x ≠ ∅ ∧ x ⊆ ⋃ x → F ⁡ B ⊂ F ⁡ u
18 fveq2 ⊢ v = suc ⁡ u → F ⁡ v = F ⁡ suc ⁡ u
19 18 psseq2d ⊢ v = suc ⁡ u → F ⁡ B ⊂ F ⁡ v ↔ F ⁡ B ⊂ F ⁡ suc ⁡ u
20 19 imbi2d ⊢ v = suc ⁡ u → x ≠ ∅ ∧ x ⊆ ⋃ x → F ⁡ B ⊂ F ⁡ v ↔ x ≠ ∅ ∧ x ⊆ ⋃ x → F ⁡ B ⊂ F ⁡ suc ⁡ u
21 fveq2 ⊢ v = A → F ⁡ v = F ⁡ A
22 21 psseq2d ⊢ v = A → F ⁡ B ⊂ F ⁡ v ↔ F ⁡ B ⊂ F ⁡ A
23 22 imbi2d ⊢ v = A → x ≠ ∅ ∧ x ⊆ ⋃ x → F ⁡ B ⊂ F ⁡ v ↔ x ≠ ∅ ∧ x ⊆ ⋃ x → F ⁡ B ⊂ F ⁡ A
24 1 2 4 4 inf3lem4 ⊢ x ≠ ∅ ∧ x ⊆ ⋃ x → B ∈ ω → F ⁡ B ⊂ F ⁡ suc ⁡ B
25 24 com12 ⊢ B ∈ ω → x ≠ ∅ ∧ x ⊆ ⋃ x → F ⁡ B ⊂ F ⁡ suc ⁡ B
26 11 25 sylbir ⊢ suc ⁡ B ∈ ω → x ≠ ∅ ∧ x ⊆ ⋃ x → F ⁡ B ⊂ F ⁡ suc ⁡ B
27 vex ⊢ u ∈ V
28 1 2 27 4 inf3lem4 ⊢ x ≠ ∅ ∧ x ⊆ ⋃ x → u ∈ ω → F ⁡ u ⊂ F ⁡ suc ⁡ u
29 psstr ⊢ F ⁡ B ⊂ F ⁡ u ∧ F ⁡ u ⊂ F ⁡ suc ⁡ u → F ⁡ B ⊂ F ⁡ suc ⁡ u
30 29 expcom ⊢ F ⁡ u ⊂ F ⁡ suc ⁡ u → F ⁡ B ⊂ F ⁡ u → F ⁡ B ⊂ F ⁡ suc ⁡ u
31 28 30 syl6com ⊢ u ∈ ω → x ≠ ∅ ∧ x ⊆ ⋃ x → F ⁡ B ⊂ F ⁡ u → F ⁡ B ⊂ F ⁡ suc ⁡ u
32 31 a2d ⊢ u ∈ ω → x ≠ ∅ ∧ x ⊆ ⋃ x → F ⁡ B ⊂ F ⁡ u → x ≠ ∅ ∧ x ⊆ ⋃ x → F ⁡ B ⊂ F ⁡ suc ⁡ u
33 32 ad2antrr ⊢ u ∈ ω ∧ suc ⁡ B ∈ ω ∧ suc ⁡ B ⊆ u → x ≠ ∅ ∧ x ⊆ ⋃ x → F ⁡ B ⊂ F ⁡ u → x ≠ ∅ ∧ x ⊆ ⋃ x → F ⁡ B ⊂ F ⁡ suc ⁡ u
34 14 17 20 23 26 33 findsg ⊢ A ∈ ω ∧ suc ⁡ B ∈ ω ∧ suc ⁡ B ⊆ A → x ≠ ∅ ∧ x ⊆ ⋃ x → F ⁡ B ⊂ F ⁡ A
35 34 ex ⊢ A ∈ ω ∧ suc ⁡ B ∈ ω → suc ⁡ B ⊆ A → x ≠ ∅ ∧ x ⊆ ⋃ x → F ⁡ B ⊂ F ⁡ A
36 11 35 sylan2b ⊢ A ∈ ω ∧ B ∈ ω → suc ⁡ B ⊆ A → x ≠ ∅ ∧ x ⊆ ⋃ x → F ⁡ B ⊂ F ⁡ A
37 10 36 syld ⊢ A ∈ ω ∧ B ∈ ω → B ∈ A → x ≠ ∅ ∧ x ⊆ ⋃ x → F ⁡ B ⊂ F ⁡ A
38 37 impancom ⊢ A ∈ ω ∧ B ∈ A → B ∈ ω → x ≠ ∅ ∧ x ⊆ ⋃ x → F ⁡ B ⊂ F ⁡ A
39 6 38 mpd ⊢ A ∈ ω ∧ B ∈ A → x ≠ ∅ ∧ x ⊆ ⋃ x → F ⁡ B ⊂ F ⁡ A
40 39 com12 ⊢ x ≠ ∅ ∧ x ⊆ ⋃ x → A ∈ ω ∧ B ∈ A → F ⁡ B ⊂ F ⁡ A