Metamath Proof Explorer


Theorem infdju1

Description: An infinite set is equinumerous to itself added with one. (Contributed by Mario Carneiro, 15-May-2015)

Ref Expression
Assertion infdju1 ⊢ ω ≼ A → A ⊔︀ 1 𝑜 ≈ A

Proof

Step Hyp Ref Expression
1 difun2 ⊢ ∅ × A ∪ 1 𝑜 × 1 𝑜 ∖ 1 𝑜 × 1 𝑜 = ∅ × A ∖ 1 𝑜 × 1 𝑜
2 df-dju ⊢ A ⊔︀ 1 𝑜 = ∅ × A ∪ 1 𝑜 × 1 𝑜
3 df1o2 ⊢ 1 𝑜 = ∅
4 3 xpeq2i ⊢ 1 𝑜 × 1 𝑜 = 1 𝑜 × ∅
5 1oex ⊢ 1 𝑜 ∈ V
6 0ex ⊢ ∅ ∈ V
7 5 6 xpsn ⊢ 1 𝑜 × ∅ = 1 𝑜 ∅
8 4 7 eqtr2i ⊢ 1 𝑜 ∅ = 1 𝑜 × 1 𝑜
9 2 8 difeq12i ⊢ A ⊔︀ 1 𝑜 ∖ 1 𝑜 ∅ = ∅ × A ∪ 1 𝑜 × 1 𝑜 ∖ 1 𝑜 × 1 𝑜
10 xp01disjl ⊢ ∅ × A ∩ 1 𝑜 × 1 𝑜 = ∅
11 disj3 ⊢ ∅ × A ∩ 1 𝑜 × 1 𝑜 = ∅ ↔ ∅ × A = ∅ × A ∖ 1 𝑜 × 1 𝑜
12 10 11 mpbi ⊢ ∅ × A = ∅ × A ∖ 1 𝑜 × 1 𝑜
13 1 9 12 3eqtr4i ⊢ A ⊔︀ 1 𝑜 ∖ 1 𝑜 ∅ = ∅ × A
14 reldom ⊢ Rel ⁡ ≼
15 14 brrelex2i ⊢ ω ≼ A → A ∈ V
16 1on ⊢ 1 𝑜 ∈ On
17 djudoml ⊢ A ∈ V ∧ 1 𝑜 ∈ On → A ≼ A ⊔︀ 1 𝑜
18 15 16 17 sylancl ⊢ ω ≼ A → A ≼ A ⊔︀ 1 𝑜
19 domtr ⊢ ω ≼ A ∧ A ≼ A ⊔︀ 1 𝑜 → ω ≼ A ⊔︀ 1 𝑜
20 18 19 mpdan ⊢ ω ≼ A → ω ≼ A ⊔︀ 1 𝑜
21 infdifsn ⊢ ω ≼ A ⊔︀ 1 𝑜 → A ⊔︀ 1 𝑜 ∖ 1 𝑜 ∅ ≈ A ⊔︀ 1 𝑜
22 20 21 syl ⊢ ω ≼ A → A ⊔︀ 1 𝑜 ∖ 1 𝑜 ∅ ≈ A ⊔︀ 1 𝑜
23 13 22 eqbrtrrid ⊢ ω ≼ A → ∅ × A ≈ A ⊔︀ 1 𝑜
24 23 ensymd ⊢ ω ≼ A → A ⊔︀ 1 𝑜 ≈ ∅ × A
25 xpsnen2g ⊢ ∅ ∈ V ∧ A ∈ V → ∅ × A ≈ A
26 6 15 25 sylancr ⊢ ω ≼ A → ∅ × A ≈ A
27 entr ⊢ A ⊔︀ 1 𝑜 ≈ ∅ × A ∧ ∅ × A ≈ A → A ⊔︀ 1 𝑜 ≈ A
28 24 26 27 syl2anc ⊢ ω ≼ A → A ⊔︀ 1 𝑜 ≈ A