Metamath Proof Explorer


Theorem isrrext

Description: Express the property " R is an extension of RR ". (Contributed by Thierry Arnoux, 2-May-2018)

Ref Expression
Hypotheses isrrext.b ⊢ B = Base R
isrrext.v ⊢ D = dist ⁡ R ↾ B × B
isrrext.z ⊢ Z = ℤMod ⁡ R
Assertion isrrext ⊢ R ∈ ℝExt ↔ R ∈ NrmRing ∧ R ∈ DivRing ∧ Z ∈ NrmMod ∧ chr ⁡ R = 0 ∧ R ∈ CUnifSp ∧ UnifSt ⁡ R = metUnif ⁡ D

Proof

Step Hyp Ref Expression
1 isrrext.b ⊢ B = Base R
2 isrrext.v ⊢ D = dist ⁡ R ↾ B × B
3 isrrext.z ⊢ Z = ℤMod ⁡ R
4 elin ⊢ R ∈ NrmRing ∩ DivRing ↔ R ∈ NrmRing ∧ R ∈ DivRing
5 4 anbi1i ⊢ R ∈ NrmRing ∩ DivRing ∧ Z ∈ NrmMod ∧ chr ⁡ R = 0 ∧ R ∈ CUnifSp ∧ UnifSt ⁡ R = metUnif ⁡ D ↔ R ∈ NrmRing ∧ R ∈ DivRing ∧ Z ∈ NrmMod ∧ chr ⁡ R = 0 ∧ R ∈ CUnifSp ∧ UnifSt ⁡ R = metUnif ⁡ D
6 fveq2 ⊢ r = R → ℤMod ⁡ r = ℤMod ⁡ R
7 6 eleq1d ⊢ r = R → ℤMod ⁡ r ∈ NrmMod ↔ ℤMod ⁡ R ∈ NrmMod
8 3 eleq1i ⊢ Z ∈ NrmMod ↔ ℤMod ⁡ R ∈ NrmMod
9 7 8 bitr4di ⊢ r = R → ℤMod ⁡ r ∈ NrmMod ↔ Z ∈ NrmMod
10 fveqeq2 ⊢ r = R → chr ⁡ r = 0 ↔ chr ⁡ R = 0
11 9 10 anbi12d ⊢ r = R → ℤMod ⁡ r ∈ NrmMod ∧ chr ⁡ r = 0 ↔ Z ∈ NrmMod ∧ chr ⁡ R = 0
12 eleq1 ⊢ r = R → r ∈ CUnifSp ↔ R ∈ CUnifSp
13 fveq2 ⊢ r = R → UnifSt ⁡ r = UnifSt ⁡ R
14 fveq2 ⊢ r = R → dist ⁡ r = dist ⁡ R
15 fveq2 ⊢ r = R → Base r = Base R
16 15 1 eqtr4di ⊢ r = R → Base r = B
17 16 sqxpeqd ⊢ r = R → Base r × Base r = B × B
18 14 17 reseq12d ⊢ r = R → dist ⁡ r ↾ Base r × Base r = dist ⁡ R ↾ B × B
19 18 2 eqtr4di ⊢ r = R → dist ⁡ r ↾ Base r × Base r = D
20 19 fveq2d ⊢ r = R → metUnif ⁡ dist ⁡ r ↾ Base r × Base r = metUnif ⁡ D
21 13 20 eqeq12d ⊢ r = R → UnifSt ⁡ r = metUnif ⁡ dist ⁡ r ↾ Base r × Base r ↔ UnifSt ⁡ R = metUnif ⁡ D
22 12 21 anbi12d ⊢ r = R → r ∈ CUnifSp ∧ UnifSt ⁡ r = metUnif ⁡ dist ⁡ r ↾ Base r × Base r ↔ R ∈ CUnifSp ∧ UnifSt ⁡ R = metUnif ⁡ D
23 11 22 anbi12d ⊢ r = R → ℤMod ⁡ r ∈ NrmMod ∧ chr ⁡ r = 0 ∧ r ∈ CUnifSp ∧ UnifSt ⁡ r = metUnif ⁡ dist ⁡ r ↾ Base r × Base r ↔ Z ∈ NrmMod ∧ chr ⁡ R = 0 ∧ R ∈ CUnifSp ∧ UnifSt ⁡ R = metUnif ⁡ D
24 df-rrext ⊢ ℝExt = r ∈ NrmRing ∩ DivRing | ℤMod ⁡ r ∈ NrmMod ∧ chr ⁡ r = 0 ∧ r ∈ CUnifSp ∧ UnifSt ⁡ r = metUnif ⁡ dist ⁡ r ↾ Base r × Base r
25 23 24 elrab2 ⊢ R ∈ ℝExt ↔ R ∈ NrmRing ∩ DivRing ∧ Z ∈ NrmMod ∧ chr ⁡ R = 0 ∧ R ∈ CUnifSp ∧ UnifSt ⁡ R = metUnif ⁡ D
26 3anass ⊢ R ∈ NrmRing ∧ R ∈ DivRing ∧ Z ∈ NrmMod ∧ chr ⁡ R = 0 ∧ R ∈ CUnifSp ∧ UnifSt ⁡ R = metUnif ⁡ D ↔ R ∈ NrmRing ∧ R ∈ DivRing ∧ Z ∈ NrmMod ∧ chr ⁡ R = 0 ∧ R ∈ CUnifSp ∧ UnifSt ⁡ R = metUnif ⁡ D
27 5 25 26 3bitr4i ⊢ R ∈ ℝExt ↔ R ∈ NrmRing ∧ R ∈ DivRing ∧ Z ∈ NrmMod ∧ chr ⁡ R = 0 ∧ R ∈ CUnifSp ∧ UnifSt ⁡ R = metUnif ⁡ D