Metamath Proof Explorer


Theorem itg0

Description: The integral of anything on the empty set is zero. (Contributed by Mario Carneiro, 13-Aug-2014)

Ref Expression
Assertion itg0 ⊢ ∫ ∅ A dx = 0

Proof

Step Hyp Ref Expression
1 eqid ⊢ ℜ ⁡ A i k = ℜ ⁡ A i k
2 1 dfitg ⊢ ∫ ∅ A dx = ∑ k = 0 3 i k ⁢ ∫ 2 ⁡ x ∈ ℝ ⟼ if x ∈ ∅ ∧ 0 ≤ ℜ ⁡ A i k ℜ ⁡ A i k 0
3 ifan ⊢ if x ∈ ∅ ∧ 0 ≤ ℜ ⁡ A i k ℜ ⁡ A i k 0 = if x ∈ ∅ if 0 ≤ ℜ ⁡ A i k ℜ ⁡ A i k 0 0
4 noel ⊢ ¬ x ∈ ∅
5 4 iffalsei ⊢ if x ∈ ∅ if 0 ≤ ℜ ⁡ A i k ℜ ⁡ A i k 0 0 = 0
6 3 5 eqtri ⊢ if x ∈ ∅ ∧ 0 ≤ ℜ ⁡ A i k ℜ ⁡ A i k 0 = 0
7 6 mpteq2i ⊢ x ∈ ℝ ⟼ if x ∈ ∅ ∧ 0 ≤ ℜ ⁡ A i k ℜ ⁡ A i k 0 = x ∈ ℝ ⟼ 0
8 fconstmpt ⊢ ℝ × 0 = x ∈ ℝ ⟼ 0
9 7 8 eqtr4i ⊢ x ∈ ℝ ⟼ if x ∈ ∅ ∧ 0 ≤ ℜ ⁡ A i k ℜ ⁡ A i k 0 = ℝ × 0
10 9 fveq2i ⊢ ∫ 2 ⁡ x ∈ ℝ ⟼ if x ∈ ∅ ∧ 0 ≤ ℜ ⁡ A i k ℜ ⁡ A i k 0 = ∫ 2 ⁡ ℝ × 0
11 itg20 ⊢ ∫ 2 ⁡ ℝ × 0 = 0
12 10 11 eqtri ⊢ ∫ 2 ⁡ x ∈ ℝ ⟼ if x ∈ ∅ ∧ 0 ≤ ℜ ⁡ A i k ℜ ⁡ A i k 0 = 0
13 12 oveq2i ⊢ i k ⁢ ∫ 2 ⁡ x ∈ ℝ ⟼ if x ∈ ∅ ∧ 0 ≤ ℜ ⁡ A i k ℜ ⁡ A i k 0 = i k ⋅ 0
14 ax-icn ⊢ i ∈ ℂ
15 elfznn0 ⊢ k ∈ 0 … 3 → k ∈ ℕ 0
16 expcl ⊢ i ∈ ℂ ∧ k ∈ ℕ 0 → i k ∈ ℂ
17 14 15 16 sylancr ⊢ k ∈ 0 … 3 → i k ∈ ℂ
18 17 mul01d ⊢ k ∈ 0 … 3 → i k ⋅ 0 = 0
19 13 18 eqtrid ⊢ k ∈ 0 … 3 → i k ⁢ ∫ 2 ⁡ x ∈ ℝ ⟼ if x ∈ ∅ ∧ 0 ≤ ℜ ⁡ A i k ℜ ⁡ A i k 0 = 0
20 19 sumeq2i ⊢ ∑ k = 0 3 i k ⁢ ∫ 2 ⁡ x ∈ ℝ ⟼ if x ∈ ∅ ∧ 0 ≤ ℜ ⁡ A i k ℜ ⁡ A i k 0 = ∑ k = 0 3 0
21 fzfi ⊢ 0 … 3 ∈ Fin
22 21 olci ⊢ 0 … 3 ⊆ ℤ ≥ 0 ∨ 0 … 3 ∈ Fin
23 sumz ⊢ 0 … 3 ⊆ ℤ ≥ 0 ∨ 0 … 3 ∈ Fin → ∑ k = 0 3 0 = 0
24 22 23 ax-mp ⊢ ∑ k = 0 3 0 = 0
25 20 24 eqtri ⊢ ∑ k = 0 3 i k ⁢ ∫ 2 ⁡ x ∈ ℝ ⟼ if x ∈ ∅ ∧ 0 ≤ ℜ ⁡ A i k ℜ ⁡ A i k 0 = 0
26 2 25 eqtri ⊢ ∫ ∅ A dx = 0