Metamath Proof Explorer


Theorem k0004lem1

Description: Application of ssin to range of a function. (Contributed by RP, 1-Apr-2021)

Ref Expression
Assertion k0004lem1 D = B C F : A B F A C F : A D

Proof

Step Hyp Ref Expression
1 fnima F Fn A F A = ran F
2 1 sseq1d F Fn A F A C ran F C
3 2 anbi2d F Fn A ran F B F A C ran F B ran F C
4 ssin ran F B ran F C ran F B C
5 3 4 bitrdi F Fn A ran F B F A C ran F B C
6 5 pm5.32i F Fn A ran F B F A C F Fn A ran F B C
7 df-f F : A B F Fn A ran F B
8 7 anbi1i F : A B F A C F Fn A ran F B F A C
9 anass F Fn A ran F B F A C F Fn A ran F B F A C
10 8 9 bitri F : A B F A C F Fn A ran F B F A C
11 df-f F : A B C F Fn A ran F B C
12 6 10 11 3bitr4i F : A B F A C F : A B C
13 feq3 D = B C F : A D F : A B C
14 12 13 bitr4id D = B C F : A B F A C F : A D