Metamath Proof Explorer


Theorem lcfrlem32

Description: Lemma for lcfr . (Contributed by NM, 10-Mar-2015)

Ref Expression
Hypotheses lcfrlem17.h ⊢ H = LHyp ⁡ K
lcfrlem17.o ⊢ ⊥ ˙ = ocH ⁡ K ⁡ W
lcfrlem17.u ⊢ U = DVecH ⁡ K ⁡ W
lcfrlem17.v ⊢ V = Base U
lcfrlem17.p ⊢ + ˙ = + U
lcfrlem17.z ⊢ 0 ˙ = 0 U
lcfrlem17.n ⊢ N = LSpan ⁡ U
lcfrlem17.a ⊢ A = LSAtoms ⁡ U
lcfrlem17.k ⊢ φ → K ∈ HL ∧ W ∈ H
lcfrlem17.x ⊢ φ → X ∈ V ∖ 0 ˙
lcfrlem17.y ⊢ φ → Y ∈ V ∖ 0 ˙
lcfrlem17.ne ⊢ φ → N ⁡ X ≠ N ⁡ Y
lcfrlem22.b ⊢ B = N ⁡ X Y ∩ ⊥ ˙ ⁡ X + ˙ Y
lcfrlem24.t ⊢ · ˙ = ⋅ U
lcfrlem24.s ⊢ S = Scalar ⁡ U
lcfrlem24.q ⊢ Q = 0 S
lcfrlem24.r ⊢ R = Base S
lcfrlem24.j ⊢ J = x ∈ V ∖ 0 ˙ ⟼ v ∈ V ⟼ ι k ∈ R | ∃ w ∈ ⊥ ˙ ⁡ x v = w + ˙ k · ˙ x
lcfrlem24.ib ⊢ φ → I ∈ B
lcfrlem24.l ⊢ L = LKer ⁡ U
lcfrlem25.d ⊢ D = LDual ⁡ U
lcfrlem28.jn ⊢ φ → J ⁡ Y ⁡ I ≠ Q
lcfrlem29.i ⊢ F = inv r ⁡ S
lcfrlem30.m ⊢ - ˙ = - D
lcfrlem30.c ⊢ C = J ⁡ X - ˙ F ⁡ J ⁡ Y ⁡ I ⋅ S J ⁡ X ⁡ I ⋅ D J ⁡ Y
lcfrlem31.xi ⊢ φ → J ⁡ X ⁡ I ≠ Q
Assertion lcfrlem32 ⊢ φ → C ≠ 0 D

Proof

Step Hyp Ref Expression
1 lcfrlem17.h ⊢ H = LHyp ⁡ K
2 lcfrlem17.o ⊢ ⊥ ˙ = ocH ⁡ K ⁡ W
3 lcfrlem17.u ⊢ U = DVecH ⁡ K ⁡ W
4 lcfrlem17.v ⊢ V = Base U
5 lcfrlem17.p ⊢ + ˙ = + U
6 lcfrlem17.z ⊢ 0 ˙ = 0 U
7 lcfrlem17.n ⊢ N = LSpan ⁡ U
8 lcfrlem17.a ⊢ A = LSAtoms ⁡ U
9 lcfrlem17.k ⊢ φ → K ∈ HL ∧ W ∈ H
10 lcfrlem17.x ⊢ φ → X ∈ V ∖ 0 ˙
11 lcfrlem17.y ⊢ φ → Y ∈ V ∖ 0 ˙
12 lcfrlem17.ne ⊢ φ → N ⁡ X ≠ N ⁡ Y
13 lcfrlem22.b ⊢ B = N ⁡ X Y ∩ ⊥ ˙ ⁡ X + ˙ Y
14 lcfrlem24.t ⊢ · ˙ = ⋅ U
15 lcfrlem24.s ⊢ S = Scalar ⁡ U
16 lcfrlem24.q ⊢ Q = 0 S
17 lcfrlem24.r ⊢ R = Base S
18 lcfrlem24.j ⊢ J = x ∈ V ∖ 0 ˙ ⟼ v ∈ V ⟼ ι k ∈ R | ∃ w ∈ ⊥ ˙ ⁡ x v = w + ˙ k · ˙ x
19 lcfrlem24.ib ⊢ φ → I ∈ B
20 lcfrlem24.l ⊢ L = LKer ⁡ U
21 lcfrlem25.d ⊢ D = LDual ⁡ U
22 lcfrlem28.jn ⊢ φ → J ⁡ Y ⁡ I ≠ Q
23 lcfrlem29.i ⊢ F = inv r ⁡ S
24 lcfrlem30.m ⊢ - ˙ = - D
25 lcfrlem30.c ⊢ C = J ⁡ X - ˙ F ⁡ J ⁡ Y ⁡ I ⋅ S J ⁡ X ⁡ I ⋅ D J ⁡ Y
26 lcfrlem31.xi ⊢ φ → J ⁡ X ⁡ I ≠ Q
27 9 adantr ⊢ φ ∧ C = 0 D → K ∈ HL ∧ W ∈ H
28 10 adantr ⊢ φ ∧ C = 0 D → X ∈ V ∖ 0 ˙
29 11 adantr ⊢ φ ∧ C = 0 D → Y ∈ V ∖ 0 ˙
30 12 adantr ⊢ φ ∧ C = 0 D → N ⁡ X ≠ N ⁡ Y
31 19 adantr ⊢ φ ∧ C = 0 D → I ∈ B
32 22 adantr ⊢ φ ∧ C = 0 D → J ⁡ Y ⁡ I ≠ Q
33 26 adantr ⊢ φ ∧ C = 0 D → J ⁡ X ⁡ I ≠ Q
34 simpr ⊢ φ ∧ C = 0 D → C = 0 D
35 1 2 3 4 5 6 7 8 27 28 29 30 13 14 15 16 17 18 31 20 21 32 23 24 25 33 34 lcfrlem31 ⊢ φ ∧ C = 0 D → N ⁡ X = N ⁡ Y
36 35 ex ⊢ φ → C = 0 D → N ⁡ X = N ⁡ Y
37 36 necon3d ⊢ φ → N ⁡ X ≠ N ⁡ Y → C ≠ 0 D
38 12 37 mpd ⊢ φ → C ≠ 0 D