Metamath Proof Explorer


Theorem lnatexN

Description: There is an atom in a line different from any other. (Contributed by NM, 30-Apr-2012) (New usage is discouraged.)

Ref Expression
Hypotheses lnatex.b ⊢ B = Base K
lnatex.l ⊢ ≤ ˙ = ≤ K
lnatex.a ⊢ A = Atoms ⁡ K
lnatex.n ⊢ N = Lines ⁡ K
lnatex.m ⊢ M = pmap ⁡ K
Assertion lnatexN ⊢ K ∈ HL ∧ X ∈ B ∧ M ⁡ X ∈ N → ∃ q ∈ A q ≠ P ∧ q ≤ ˙ X

Proof

Step Hyp Ref Expression
1 lnatex.b ⊢ B = Base K
2 lnatex.l ⊢ ≤ ˙ = ≤ K
3 lnatex.a ⊢ A = Atoms ⁡ K
4 lnatex.n ⊢ N = Lines ⁡ K
5 lnatex.m ⊢ M = pmap ⁡ K
6 eqid ⊢ join ⁡ K = join ⁡ K
7 1 6 3 4 5 isline3 ⊢ K ∈ HL ∧ X ∈ B → M ⁡ X ∈ N ↔ ∃ r ∈ A ∃ s ∈ A r ≠ s ∧ X = r join ⁡ K s
8 7 biimp3a ⊢ K ∈ HL ∧ X ∈ B ∧ M ⁡ X ∈ N → ∃ r ∈ A ∃ s ∈ A r ≠ s ∧ X = r join ⁡ K s
9 simpl2r ⊢ K ∈ HL ∧ X ∈ B ∧ M ⁡ X ∈ N ∧ r ∈ A ∧ s ∈ A ∧ r ≠ s ∧ X = r join ⁡ K s ∧ r = P → s ∈ A
10 simpl3l ⊢ K ∈ HL ∧ X ∈ B ∧ M ⁡ X ∈ N ∧ r ∈ A ∧ s ∈ A ∧ r ≠ s ∧ X = r join ⁡ K s ∧ r = P → r ≠ s
11 10 necomd ⊢ K ∈ HL ∧ X ∈ B ∧ M ⁡ X ∈ N ∧ r ∈ A ∧ s ∈ A ∧ r ≠ s ∧ X = r join ⁡ K s ∧ r = P → s ≠ r
12 simpr ⊢ K ∈ HL ∧ X ∈ B ∧ M ⁡ X ∈ N ∧ r ∈ A ∧ s ∈ A ∧ r ≠ s ∧ X = r join ⁡ K s ∧ r = P → r = P
13 11 12 neeqtrd ⊢ K ∈ HL ∧ X ∈ B ∧ M ⁡ X ∈ N ∧ r ∈ A ∧ s ∈ A ∧ r ≠ s ∧ X = r join ⁡ K s ∧ r = P → s ≠ P
14 simpl11 ⊢ K ∈ HL ∧ X ∈ B ∧ M ⁡ X ∈ N ∧ r ∈ A ∧ s ∈ A ∧ r ≠ s ∧ X = r join ⁡ K s ∧ r = P → K ∈ HL
15 simpl2l ⊢ K ∈ HL ∧ X ∈ B ∧ M ⁡ X ∈ N ∧ r ∈ A ∧ s ∈ A ∧ r ≠ s ∧ X = r join ⁡ K s ∧ r = P → r ∈ A
16 2 6 3 hlatlej2 ⊢ K ∈ HL ∧ r ∈ A ∧ s ∈ A → s ≤ ˙ r join ⁡ K s
17 14 15 9 16 syl3anc ⊢ K ∈ HL ∧ X ∈ B ∧ M ⁡ X ∈ N ∧ r ∈ A ∧ s ∈ A ∧ r ≠ s ∧ X = r join ⁡ K s ∧ r = P → s ≤ ˙ r join ⁡ K s
18 simpl3r ⊢ K ∈ HL ∧ X ∈ B ∧ M ⁡ X ∈ N ∧ r ∈ A ∧ s ∈ A ∧ r ≠ s ∧ X = r join ⁡ K s ∧ r = P → X = r join ⁡ K s
19 17 18 breqtrrd ⊢ K ∈ HL ∧ X ∈ B ∧ M ⁡ X ∈ N ∧ r ∈ A ∧ s ∈ A ∧ r ≠ s ∧ X = r join ⁡ K s ∧ r = P → s ≤ ˙ X
20 neeq1 ⊢ q = s → q ≠ P ↔ s ≠ P
21 breq1 ⊢ q = s → q ≤ ˙ X ↔ s ≤ ˙ X
22 20 21 anbi12d ⊢ q = s → q ≠ P ∧ q ≤ ˙ X ↔ s ≠ P ∧ s ≤ ˙ X
23 22 rspcev ⊢ s ∈ A ∧ s ≠ P ∧ s ≤ ˙ X → ∃ q ∈ A q ≠ P ∧ q ≤ ˙ X
24 9 13 19 23 syl12anc ⊢ K ∈ HL ∧ X ∈ B ∧ M ⁡ X ∈ N ∧ r ∈ A ∧ s ∈ A ∧ r ≠ s ∧ X = r join ⁡ K s ∧ r = P → ∃ q ∈ A q ≠ P ∧ q ≤ ˙ X
25 simpl2l ⊢ K ∈ HL ∧ X ∈ B ∧ M ⁡ X ∈ N ∧ r ∈ A ∧ s ∈ A ∧ r ≠ s ∧ X = r join ⁡ K s ∧ r ≠ P → r ∈ A
26 simpr ⊢ K ∈ HL ∧ X ∈ B ∧ M ⁡ X ∈ N ∧ r ∈ A ∧ s ∈ A ∧ r ≠ s ∧ X = r join ⁡ K s ∧ r ≠ P → r ≠ P
27 simpl11 ⊢ K ∈ HL ∧ X ∈ B ∧ M ⁡ X ∈ N ∧ r ∈ A ∧ s ∈ A ∧ r ≠ s ∧ X = r join ⁡ K s ∧ r ≠ P → K ∈ HL
28 simpl2r ⊢ K ∈ HL ∧ X ∈ B ∧ M ⁡ X ∈ N ∧ r ∈ A ∧ s ∈ A ∧ r ≠ s ∧ X = r join ⁡ K s ∧ r ≠ P → s ∈ A
29 2 6 3 hlatlej1 ⊢ K ∈ HL ∧ r ∈ A ∧ s ∈ A → r ≤ ˙ r join ⁡ K s
30 27 25 28 29 syl3anc ⊢ K ∈ HL ∧ X ∈ B ∧ M ⁡ X ∈ N ∧ r ∈ A ∧ s ∈ A ∧ r ≠ s ∧ X = r join ⁡ K s ∧ r ≠ P → r ≤ ˙ r join ⁡ K s
31 simpl3r ⊢ K ∈ HL ∧ X ∈ B ∧ M ⁡ X ∈ N ∧ r ∈ A ∧ s ∈ A ∧ r ≠ s ∧ X = r join ⁡ K s ∧ r ≠ P → X = r join ⁡ K s
32 30 31 breqtrrd ⊢ K ∈ HL ∧ X ∈ B ∧ M ⁡ X ∈ N ∧ r ∈ A ∧ s ∈ A ∧ r ≠ s ∧ X = r join ⁡ K s ∧ r ≠ P → r ≤ ˙ X
33 neeq1 ⊢ q = r → q ≠ P ↔ r ≠ P
34 breq1 ⊢ q = r → q ≤ ˙ X ↔ r ≤ ˙ X
35 33 34 anbi12d ⊢ q = r → q ≠ P ∧ q ≤ ˙ X ↔ r ≠ P ∧ r ≤ ˙ X
36 35 rspcev ⊢ r ∈ A ∧ r ≠ P ∧ r ≤ ˙ X → ∃ q ∈ A q ≠ P ∧ q ≤ ˙ X
37 25 26 32 36 syl12anc ⊢ K ∈ HL ∧ X ∈ B ∧ M ⁡ X ∈ N ∧ r ∈ A ∧ s ∈ A ∧ r ≠ s ∧ X = r join ⁡ K s ∧ r ≠ P → ∃ q ∈ A q ≠ P ∧ q ≤ ˙ X
38 24 37 pm2.61dane ⊢ K ∈ HL ∧ X ∈ B ∧ M ⁡ X ∈ N ∧ r ∈ A ∧ s ∈ A ∧ r ≠ s ∧ X = r join ⁡ K s → ∃ q ∈ A q ≠ P ∧ q ≤ ˙ X
39 38 3exp ⊢ K ∈ HL ∧ X ∈ B ∧ M ⁡ X ∈ N → r ∈ A ∧ s ∈ A → r ≠ s ∧ X = r join ⁡ K s → ∃ q ∈ A q ≠ P ∧ q ≤ ˙ X
40 39 rexlimdvv ⊢ K ∈ HL ∧ X ∈ B ∧ M ⁡ X ∈ N → ∃ r ∈ A ∃ s ∈ A r ≠ s ∧ X = r join ⁡ K s → ∃ q ∈ A q ≠ P ∧ q ≤ ˙ X
41 8 40 mpd ⊢ K ∈ HL ∧ X ∈ B ∧ M ⁡ X ∈ N → ∃ q ∈ A q ≠ P ∧ q ≤ ˙ X