Metamath Proof Explorer


Theorem m2detleiblem1

Description: Lemma 1 for m2detleib . (Contributed by AV, 12-Dec-2018)

Ref Expression
Hypotheses m2detleiblem1.n ⊢ N = 1 2
m2detleiblem1.p ⊢ P = Base SymGrp ⁡ N
m2detleiblem1.y ⊢ Y = ℤRHom ⁡ R
m2detleiblem1.s ⊢ S = pmSgn ⁡ N
m2detleiblem1.o ⊢ 1 ˙ = 1 R
Assertion m2detleiblem1 ⊢ R ∈ Ring ∧ Q ∈ P → Y ⁡ S ⁡ Q = pmSgn ⁡ N ⁡ Q ⋅ R 1 ˙

Proof

Step Hyp Ref Expression
1 m2detleiblem1.n ⊢ N = 1 2
2 m2detleiblem1.p ⊢ P = Base SymGrp ⁡ N
3 m2detleiblem1.y ⊢ Y = ℤRHom ⁡ R
4 m2detleiblem1.s ⊢ S = pmSgn ⁡ N
5 m2detleiblem1.o ⊢ 1 ˙ = 1 R
6 elpri ⊢ Q ∈ 1 1 2 2 1 2 2 1 → Q = 1 1 2 2 ∨ Q = 1 2 2 1
7 fveq2 ⊢ Q = 1 1 2 2 → S ⁡ Q = S ⁡ 1 1 2 2
8 eqid ⊢ SymGrp ⁡ N = SymGrp ⁡ N
9 eqid ⊢ ran ⁡ pmTrsp ⁡ N = ran ⁡ pmTrsp ⁡ N
10 1 8 2 9 4 psgnprfval1 ⊢ S ⁡ 1 1 2 2 = 1
11 7 10 eqtrdi ⊢ Q = 1 1 2 2 → S ⁡ Q = 1
12 1z ⊢ 1 ∈ ℤ
13 11 12 eqeltrdi ⊢ Q = 1 1 2 2 → S ⁡ Q ∈ ℤ
14 fveq2 ⊢ Q = 1 2 2 1 → S ⁡ Q = S ⁡ 1 2 2 1
15 1 8 2 9 4 psgnprfval2 ⊢ S ⁡ 1 2 2 1 = − 1
16 14 15 eqtrdi ⊢ Q = 1 2 2 1 → S ⁡ Q = − 1
17 neg1z ⊢ − 1 ∈ ℤ
18 16 17 eqeltrdi ⊢ Q = 1 2 2 1 → S ⁡ Q ∈ ℤ
19 13 18 jaoi ⊢ Q = 1 1 2 2 ∨ Q = 1 2 2 1 → S ⁡ Q ∈ ℤ
20 6 19 syl ⊢ Q ∈ 1 1 2 2 1 2 2 1 → S ⁡ Q ∈ ℤ
21 1ex ⊢ 1 ∈ V
22 2nn ⊢ 2 ∈ ℕ
23 8 2 1 symg2bas ⊢ 1 ∈ V ∧ 2 ∈ ℕ → P = 1 1 2 2 1 2 2 1
24 21 22 23 mp2an ⊢ P = 1 1 2 2 1 2 2 1
25 20 24 eleq2s ⊢ Q ∈ P → S ⁡ Q ∈ ℤ
26 eqid ⊢ ⋅ R = ⋅ R
27 3 26 5 zrhmulg ⊢ R ∈ Ring ∧ S ⁡ Q ∈ ℤ → Y ⁡ S ⁡ Q = S ⁡ Q ⋅ R 1 ˙
28 25 27 sylan2 ⊢ R ∈ Ring ∧ Q ∈ P → Y ⁡ S ⁡ Q = S ⁡ Q ⋅ R 1 ˙
29 4 a1i ⊢ R ∈ Ring ∧ Q ∈ P → S = pmSgn ⁡ N
30 29 fveq1d ⊢ R ∈ Ring ∧ Q ∈ P → S ⁡ Q = pmSgn ⁡ N ⁡ Q
31 30 oveq1d ⊢ R ∈ Ring ∧ Q ∈ P → S ⁡ Q ⋅ R 1 ˙ = pmSgn ⁡ N ⁡ Q ⋅ R 1 ˙
32 28 31 eqtrd ⊢ R ∈ Ring ∧ Q ∈ P → Y ⁡ S ⁡ Q = pmSgn ⁡ N ⁡ Q ⋅ R 1 ˙