Metamath Proof Explorer


Theorem meassle

Description: The measure of a set is greater than or equal to the measure of a subset, Property 112C (b) of Fremlin1 p. 15. (Contributed by Glauco Siliprandi, 17-Aug-2020)

Ref Expression
Hypotheses meassle.m ⊢ φ → M ∈ Meas
meassle.x ⊢ S = dom ⁡ M
meassle.a ⊢ φ → A ∈ S
meassle.b ⊢ φ → B ∈ S
meassle.ss ⊢ φ → A ⊆ B
Assertion meassle ⊢ φ → M ⁡ A ≤ M ⁡ B

Proof

Step Hyp Ref Expression
1 meassle.m ⊢ φ → M ∈ Meas
2 meassle.x ⊢ S = dom ⁡ M
3 meassle.a ⊢ φ → A ∈ S
4 meassle.b ⊢ φ → B ∈ S
5 meassle.ss ⊢ φ → A ⊆ B
6 1 2 3 meaxrcl ⊢ φ → M ⁡ A ∈ ℝ *
7 1 2 dmmeasal ⊢ φ → S ∈ SAlg
8 saldifcl2 ⊢ S ∈ SAlg ∧ B ∈ S ∧ A ∈ S → B ∖ A ∈ S
9 7 4 3 8 syl3anc ⊢ φ → B ∖ A ∈ S
10 1 2 9 meacl ⊢ φ → M ⁡ B ∖ A ∈ 0 +∞
11 6 10 xadd0ge ⊢ φ → M ⁡ A ≤ M ⁡ A + 𝑒 M ⁡ B ∖ A
12 undif ⊢ A ⊆ B ↔ A ∪ B ∖ A = B
13 12 biimpi ⊢ A ⊆ B → A ∪ B ∖ A = B
14 5 13 syl ⊢ φ → A ∪ B ∖ A = B
15 14 fveq2d ⊢ φ → M ⁡ A ∪ B ∖ A = M ⁡ B
16 15 eqcomd ⊢ φ → M ⁡ B = M ⁡ A ∪ B ∖ A
17 disjdif ⊢ A ∩ B ∖ A = ∅
18 17 a1i ⊢ φ → A ∩ B ∖ A = ∅
19 1 2 3 9 18 meadjun ⊢ φ → M ⁡ A ∪ B ∖ A = M ⁡ A + 𝑒 M ⁡ B ∖ A
20 16 19 eqtr2d ⊢ φ → M ⁡ A + 𝑒 M ⁡ B ∖ A = M ⁡ B
21 11 20 breqtrd ⊢ φ → M ⁡ A ≤ M ⁡ B