Description: Statement 10 in Huneke p. 2: "If n > 1, then the number of closed
n-walks v(0) ... v(n-2) v(n-1) v(n) from v = v(0) = v(n) ... with v(n-2)
=/= v is k^(n-2) - f(n-2)." According to rusgrnumwlkg , we have
k^(n-2) different walks of length (n-2): v(0) ... v(n-2). From this
number, the number of closed walks of length (n-2), which is f(n-2) per
definition, must be subtracted, because for these walks v(n-2) =/= v(0)
= v would hold. Because of the friendship condition, there is exactly
one vertex v(n-1) which is a neighbor of v(n-2) as well as of
v(n)=v=v(0), because v(n-2) and v(n)=v are different, so the number of
walks v(0) ... v(n-2) is identical with the number of walks v(0) ...
v(n), that means each (not closed) walk v(0) ... v(n-2) can be extended
by two edges to a closed walk v(0) ... v(n)=v=v(0) in exactly one way.
(Contributed by Alexander van der Vekens, 6-Oct-2018)(Revised by AV, 31-May-2021)(Revised by AV, 1-May-2022)