Metamath Proof Explorer


Theorem off

Description: The function operation produces a function. (Contributed by Mario Carneiro, 20-Jul-2014)

Ref Expression
Hypotheses off.1 ⊢ φ ∧ x ∈ S ∧ y ∈ T → x R y ∈ U
off.2 ⊢ φ → F : A ⟶ S
off.3 ⊢ φ → G : B ⟶ T
off.4 ⊢ φ → A ∈ V
off.5 ⊢ φ → B ∈ W
off.6 ⊢ A ∩ B = C
Assertion off ⊢ φ → F R f G : C ⟶ U

Proof

Step Hyp Ref Expression
1 off.1 ⊢ φ ∧ x ∈ S ∧ y ∈ T → x R y ∈ U
2 off.2 ⊢ φ → F : A ⟶ S
3 off.3 ⊢ φ → G : B ⟶ T
4 off.4 ⊢ φ → A ∈ V
5 off.5 ⊢ φ → B ∈ W
6 off.6 ⊢ A ∩ B = C
7 2 ffnd ⊢ φ → F Fn A
8 3 ffnd ⊢ φ → G Fn B
9 eqidd ⊢ φ ∧ z ∈ A → F ⁡ z = F ⁡ z
10 eqidd ⊢ φ ∧ z ∈ B → G ⁡ z = G ⁡ z
11 7 8 4 5 6 9 10 offval ⊢ φ → F R f G = z ∈ C ⟼ F ⁡ z R G ⁡ z
12 inss1 ⊢ A ∩ B ⊆ A
13 6 12 eqsstrri ⊢ C ⊆ A
14 13 sseli ⊢ z ∈ C → z ∈ A
15 ffvelcdm ⊢ F : A ⟶ S ∧ z ∈ A → F ⁡ z ∈ S
16 2 14 15 syl2an ⊢ φ ∧ z ∈ C → F ⁡ z ∈ S
17 inss2 ⊢ A ∩ B ⊆ B
18 6 17 eqsstrri ⊢ C ⊆ B
19 18 sseli ⊢ z ∈ C → z ∈ B
20 ffvelcdm ⊢ G : B ⟶ T ∧ z ∈ B → G ⁡ z ∈ T
21 3 19 20 syl2an ⊢ φ ∧ z ∈ C → G ⁡ z ∈ T
22 1 ralrimivva ⊢ φ → ∀ x ∈ S ∀ y ∈ T x R y ∈ U
23 22 adantr ⊢ φ ∧ z ∈ C → ∀ x ∈ S ∀ y ∈ T x R y ∈ U
24 ovrspc2v ⊢ F ⁡ z ∈ S ∧ G ⁡ z ∈ T ∧ ∀ x ∈ S ∀ y ∈ T x R y ∈ U → F ⁡ z R G ⁡ z ∈ U
25 16 21 23 24 syl21anc ⊢ φ ∧ z ∈ C → F ⁡ z R G ⁡ z ∈ U
26 11 25 fmpt3d ⊢ φ → F R f G : C ⟶ U