Metamath Proof Explorer


Theorem ofrval

Description: Exhibit a function relation at a point. (Contributed by Mario Carneiro, 28-Jul-2014)

Ref Expression
Hypotheses offval.1 ⊢ φ → F Fn A
offval.2 ⊢ φ → G Fn B
offval.3 ⊢ φ → A ∈ V
offval.4 ⊢ φ → B ∈ W
offval.5 ⊢ A ∩ B = S
ofval.6 ⊢ φ ∧ X ∈ A → F ⁡ X = C
ofval.7 ⊢ φ ∧ X ∈ B → G ⁡ X = D
Assertion ofrval ⊢ φ ∧ F R f G ∧ X ∈ S → C R D

Proof

Step Hyp Ref Expression
1 offval.1 ⊢ φ → F Fn A
2 offval.2 ⊢ φ → G Fn B
3 offval.3 ⊢ φ → A ∈ V
4 offval.4 ⊢ φ → B ∈ W
5 offval.5 ⊢ A ∩ B = S
6 ofval.6 ⊢ φ ∧ X ∈ A → F ⁡ X = C
7 ofval.7 ⊢ φ ∧ X ∈ B → G ⁡ X = D
8 eqidd ⊢ φ ∧ x ∈ A → F ⁡ x = F ⁡ x
9 eqidd ⊢ φ ∧ x ∈ B → G ⁡ x = G ⁡ x
10 1 2 3 4 5 8 9 ofrfval ⊢ φ → F R f G ↔ ∀ x ∈ S F ⁡ x R G ⁡ x
11 10 biimpa ⊢ φ ∧ F R f G → ∀ x ∈ S F ⁡ x R G ⁡ x
12 fveq2 ⊢ x = X → F ⁡ x = F ⁡ X
13 fveq2 ⊢ x = X → G ⁡ x = G ⁡ X
14 12 13 breq12d ⊢ x = X → F ⁡ x R G ⁡ x ↔ F ⁡ X R G ⁡ X
15 14 rspccv ⊢ ∀ x ∈ S F ⁡ x R G ⁡ x → X ∈ S → F ⁡ X R G ⁡ X
16 11 15 syl ⊢ φ ∧ F R f G → X ∈ S → F ⁡ X R G ⁡ X
17 16 3impia ⊢ φ ∧ F R f G ∧ X ∈ S → F ⁡ X R G ⁡ X
18 simp1 ⊢ φ ∧ F R f G ∧ X ∈ S → φ
19 inss1 ⊢ A ∩ B ⊆ A
20 5 19 eqsstrri ⊢ S ⊆ A
21 simp3 ⊢ φ ∧ F R f G ∧ X ∈ S → X ∈ S
22 20 21 sselid ⊢ φ ∧ F R f G ∧ X ∈ S → X ∈ A
23 18 22 6 syl2anc ⊢ φ ∧ F R f G ∧ X ∈ S → F ⁡ X = C
24 inss2 ⊢ A ∩ B ⊆ B
25 5 24 eqsstrri ⊢ S ⊆ B
26 25 21 sselid ⊢ φ ∧ F R f G ∧ X ∈ S → X ∈ B
27 18 26 7 syl2anc ⊢ φ ∧ F R f G ∧ X ∈ S → G ⁡ X = D
28 17 23 27 3brtr3d ⊢ φ ∧ F R f G ∧ X ∈ S → C R D