Metamath Proof Explorer


Theorem omlimcl2

Description: The product of a limit ordinal with any nonzero ordinal is a limit ordinal. (Contributed by RP, 8-Jan-2025)

Ref Expression
Assertion omlimcl2 ⊢ A ∈ On ∧ B ∈ C ∧ Lim ⁡ B ∧ ∅ ∈ A → Lim ⁡ B ⋅ 𝑜 A

Proof

Step Hyp Ref Expression
1 eloni ⊢ A ∈ On → Ord ⁡ A
2 1 ad2antrr ⊢ A ∈ On ∧ B ∈ C ∧ Lim ⁡ B ∧ ∅ ∈ A → Ord ⁡ A
3 ne0i ⊢ ∅ ∈ A → A ≠ ∅
4 3 adantl ⊢ A ∈ On ∧ B ∈ C ∧ Lim ⁡ B ∧ ∅ ∈ A → A ≠ ∅
5 id ⊢ A = ⋃ A → A = ⋃ A
6 df-lim ⊢ Lim ⁡ A ↔ Ord ⁡ A ∧ A ≠ ∅ ∧ A = ⋃ A
7 6 biimpri ⊢ Ord ⁡ A ∧ A ≠ ∅ ∧ A = ⋃ A → Lim ⁡ A
8 2 4 5 7 syl2an3an ⊢ A ∈ On ∧ B ∈ C ∧ Lim ⁡ B ∧ ∅ ∈ A ∧ A = ⋃ A → Lim ⁡ A
9 8 ex ⊢ A ∈ On ∧ B ∈ C ∧ Lim ⁡ B ∧ ∅ ∈ A → A = ⋃ A → Lim ⁡ A
10 limelon ⊢ B ∈ C ∧ Lim ⁡ B → B ∈ On
11 10 ad3antlr ⊢ A ∈ On ∧ B ∈ C ∧ Lim ⁡ B ∧ ∅ ∈ A ∧ Lim ⁡ A → B ∈ On
12 simpll ⊢ A ∈ On ∧ B ∈ C ∧ Lim ⁡ B ∧ ∅ ∈ A → A ∈ On
13 12 anim1i ⊢ A ∈ On ∧ B ∈ C ∧ Lim ⁡ B ∧ ∅ ∈ A ∧ Lim ⁡ A → A ∈ On ∧ Lim ⁡ A
14 0ellim ⊢ Lim ⁡ B → ∅ ∈ B
15 14 adantl ⊢ B ∈ C ∧ Lim ⁡ B → ∅ ∈ B
16 15 ad3antlr ⊢ A ∈ On ∧ B ∈ C ∧ Lim ⁡ B ∧ ∅ ∈ A ∧ Lim ⁡ A → ∅ ∈ B
17 omlimcl ⊢ B ∈ On ∧ A ∈ On ∧ Lim ⁡ A ∧ ∅ ∈ B → Lim ⁡ B ⋅ 𝑜 A
18 11 13 16 17 syl21anc ⊢ A ∈ On ∧ B ∈ C ∧ Lim ⁡ B ∧ ∅ ∈ A ∧ Lim ⁡ A → Lim ⁡ B ⋅ 𝑜 A
19 18 ex ⊢ A ∈ On ∧ B ∈ C ∧ Lim ⁡ B ∧ ∅ ∈ A → Lim ⁡ A → Lim ⁡ B ⋅ 𝑜 A
20 9 19 syld ⊢ A ∈ On ∧ B ∈ C ∧ Lim ⁡ B ∧ ∅ ∈ A → A = ⋃ A → Lim ⁡ B ⋅ 𝑜 A
21 onuni ⊢ A ∈ On → ⋃ A ∈ On
22 21 10 anim12ci ⊢ A ∈ On ∧ B ∈ C ∧ Lim ⁡ B → B ∈ On ∧ ⋃ A ∈ On
23 omcl ⊢ B ∈ On ∧ ⋃ A ∈ On → B ⋅ 𝑜 ⋃ A ∈ On
24 22 23 syl ⊢ A ∈ On ∧ B ∈ C ∧ Lim ⁡ B → B ⋅ 𝑜 ⋃ A ∈ On
25 simpr ⊢ A ∈ On ∧ B ∈ C ∧ Lim ⁡ B → B ∈ C ∧ Lim ⁡ B
26 24 25 jca ⊢ A ∈ On ∧ B ∈ C ∧ Lim ⁡ B → B ⋅ 𝑜 ⋃ A ∈ On ∧ B ∈ C ∧ Lim ⁡ B
27 26 ad2antrr ⊢ A ∈ On ∧ B ∈ C ∧ Lim ⁡ B ∧ ∅ ∈ A ∧ A = suc ⁡ ⋃ A → B ⋅ 𝑜 ⋃ A ∈ On ∧ B ∈ C ∧ Lim ⁡ B
28 oalimcl ⊢ B ⋅ 𝑜 ⋃ A ∈ On ∧ B ∈ C ∧ Lim ⁡ B → Lim ⁡ B ⋅ 𝑜 ⋃ A + 𝑜 B
29 27 28 syl ⊢ A ∈ On ∧ B ∈ C ∧ Lim ⁡ B ∧ ∅ ∈ A ∧ A = suc ⁡ ⋃ A → Lim ⁡ B ⋅ 𝑜 ⋃ A + 𝑜 B
30 simpr ⊢ A ∈ On ∧ B ∈ C ∧ Lim ⁡ B ∧ ∅ ∈ A ∧ A = suc ⁡ ⋃ A → A = suc ⁡ ⋃ A
31 30 oveq2d ⊢ A ∈ On ∧ B ∈ C ∧ Lim ⁡ B ∧ ∅ ∈ A ∧ A = suc ⁡ ⋃ A → B ⋅ 𝑜 A = B ⋅ 𝑜 suc ⁡ ⋃ A
32 22 ad2antrr ⊢ A ∈ On ∧ B ∈ C ∧ Lim ⁡ B ∧ ∅ ∈ A ∧ A = suc ⁡ ⋃ A → B ∈ On ∧ ⋃ A ∈ On
33 omsuc ⊢ B ∈ On ∧ ⋃ A ∈ On → B ⋅ 𝑜 suc ⁡ ⋃ A = B ⋅ 𝑜 ⋃ A + 𝑜 B
34 32 33 syl ⊢ A ∈ On ∧ B ∈ C ∧ Lim ⁡ B ∧ ∅ ∈ A ∧ A = suc ⁡ ⋃ A → B ⋅ 𝑜 suc ⁡ ⋃ A = B ⋅ 𝑜 ⋃ A + 𝑜 B
35 31 34 eqtrd ⊢ A ∈ On ∧ B ∈ C ∧ Lim ⁡ B ∧ ∅ ∈ A ∧ A = suc ⁡ ⋃ A → B ⋅ 𝑜 A = B ⋅ 𝑜 ⋃ A + 𝑜 B
36 limeq ⊢ B ⋅ 𝑜 A = B ⋅ 𝑜 ⋃ A + 𝑜 B → Lim ⁡ B ⋅ 𝑜 A ↔ Lim ⁡ B ⋅ 𝑜 ⋃ A + 𝑜 B
37 35 36 syl ⊢ A ∈ On ∧ B ∈ C ∧ Lim ⁡ B ∧ ∅ ∈ A ∧ A = suc ⁡ ⋃ A → Lim ⁡ B ⋅ 𝑜 A ↔ Lim ⁡ B ⋅ 𝑜 ⋃ A + 𝑜 B
38 29 37 mpbird ⊢ A ∈ On ∧ B ∈ C ∧ Lim ⁡ B ∧ ∅ ∈ A ∧ A = suc ⁡ ⋃ A → Lim ⁡ B ⋅ 𝑜 A
39 38 ex ⊢ A ∈ On ∧ B ∈ C ∧ Lim ⁡ B ∧ ∅ ∈ A → A = suc ⁡ ⋃ A → Lim ⁡ B ⋅ 𝑜 A
40 orduniorsuc ⊢ Ord ⁡ A → A = ⋃ A ∨ A = suc ⁡ ⋃ A
41 2 40 syl ⊢ A ∈ On ∧ B ∈ C ∧ Lim ⁡ B ∧ ∅ ∈ A → A = ⋃ A ∨ A = suc ⁡ ⋃ A
42 20 39 41 mpjaod ⊢ A ∈ On ∧ B ∈ C ∧ Lim ⁡ B ∧ ∅ ∈ A → Lim ⁡ B ⋅ 𝑜 A