Metamath Proof Explorer


Theorem opeliunxp

Description: Membership in a union of Cartesian products. (Contributed by Mario Carneiro, 29-Dec-2014) (Revised by Mario Carneiro, 1-Jan-2017)

Ref Expression
Assertion opeliunxp ⊢ x C ∈ ⋃ x ∈ A x × B ↔ x ∈ A ∧ C ∈ B

Proof

Step Hyp Ref Expression
1 df-iun ⊢ ⋃ x ∈ A x × B = y | ∃ x ∈ A y ∈ x × B
2 1 eleq2i ⊢ x C ∈ ⋃ x ∈ A x × B ↔ x C ∈ y | ∃ x ∈ A y ∈ x × B
3 opex ⊢ x C ∈ V
4 df-rex ⊢ ∃ x ∈ A y ∈ x × B ↔ ∃ x x ∈ A ∧ y ∈ x × B
5 nfv ⊢ Ⅎ z x ∈ A ∧ y ∈ x × B
6 nfs1v ⊢ Ⅎ x z x x ∈ A
7 nfcv ⊢ Ⅎ _ x z
8 nfcsb1v ⊢ Ⅎ _ x ⦋ z / x⦌ B
9 7 8 nfxp ⊢ Ⅎ _ x z × ⦋ z / x⦌ B
10 9 nfcri ⊢ Ⅎ x y ∈ z × ⦋ z / x⦌ B
11 6 10 nfan ⊢ Ⅎ x z x x ∈ A ∧ y ∈ z × ⦋ z / x⦌ B
12 sbequ12 ⊢ x = z → x ∈ A ↔ z x x ∈ A
13 sneq ⊢ x = z → x = z
14 csbeq1a ⊢ x = z → B = ⦋ z / x⦌ B
15 13 14 xpeq12d ⊢ x = z → x × B = z × ⦋ z / x⦌ B
16 15 eleq2d ⊢ x = z → y ∈ x × B ↔ y ∈ z × ⦋ z / x⦌ B
17 12 16 anbi12d ⊢ x = z → x ∈ A ∧ y ∈ x × B ↔ z x x ∈ A ∧ y ∈ z × ⦋ z / x⦌ B
18 5 11 17 cbvexv1 ⊢ ∃ x x ∈ A ∧ y ∈ x × B ↔ ∃ z z x x ∈ A ∧ y ∈ z × ⦋ z / x⦌ B
19 4 18 bitri ⊢ ∃ x ∈ A y ∈ x × B ↔ ∃ z z x x ∈ A ∧ y ∈ z × ⦋ z / x⦌ B
20 eleq1 ⊢ y = x C → y ∈ z × ⦋ z / x⦌ B ↔ x C ∈ z × ⦋ z / x⦌ B
21 20 anbi2d ⊢ y = x C → z x x ∈ A ∧ y ∈ z × ⦋ z / x⦌ B ↔ z x x ∈ A ∧ x C ∈ z × ⦋ z / x⦌ B
22 21 exbidv ⊢ y = x C → ∃ z z x x ∈ A ∧ y ∈ z × ⦋ z / x⦌ B ↔ ∃ z z x x ∈ A ∧ x C ∈ z × ⦋ z / x⦌ B
23 19 22 bitrid ⊢ y = x C → ∃ x ∈ A y ∈ x × B ↔ ∃ z z x x ∈ A ∧ x C ∈ z × ⦋ z / x⦌ B
24 3 23 elab ⊢ x C ∈ y | ∃ x ∈ A y ∈ x × B ↔ ∃ z z x x ∈ A ∧ x C ∈ z × ⦋ z / x⦌ B
25 opelxp ⊢ x C ∈ z × ⦋ z / x⦌ B ↔ x ∈ z ∧ C ∈ ⦋ z / x⦌ B
26 25 anbi2i ⊢ z x x ∈ A ∧ x C ∈ z × ⦋ z / x⦌ B ↔ z x x ∈ A ∧ x ∈ z ∧ C ∈ ⦋ z / x⦌ B
27 an12 ⊢ z x x ∈ A ∧ x ∈ z ∧ C ∈ ⦋ z / x⦌ B ↔ x ∈ z ∧ z x x ∈ A ∧ C ∈ ⦋ z / x⦌ B
28 velsn ⊢ x ∈ z ↔ x = z
29 equcom ⊢ x = z ↔ z = x
30 28 29 bitri ⊢ x ∈ z ↔ z = x
31 30 anbi1i ⊢ x ∈ z ∧ z x x ∈ A ∧ C ∈ ⦋ z / x⦌ B ↔ z = x ∧ z x x ∈ A ∧ C ∈ ⦋ z / x⦌ B
32 26 27 31 3bitri ⊢ z x x ∈ A ∧ x C ∈ z × ⦋ z / x⦌ B ↔ z = x ∧ z x x ∈ A ∧ C ∈ ⦋ z / x⦌ B
33 32 exbii ⊢ ∃ z z x x ∈ A ∧ x C ∈ z × ⦋ z / x⦌ B ↔ ∃ z z = x ∧ z x x ∈ A ∧ C ∈ ⦋ z / x⦌ B
34 sbequ12r ⊢ z = x → z x x ∈ A ↔ x ∈ A
35 14 equcoms ⊢ z = x → B = ⦋ z / x⦌ B
36 35 eqcomd ⊢ z = x → ⦋ z / x⦌ B = B
37 36 eleq2d ⊢ z = x → C ∈ ⦋ z / x⦌ B ↔ C ∈ B
38 34 37 anbi12d ⊢ z = x → z x x ∈ A ∧ C ∈ ⦋ z / x⦌ B ↔ x ∈ A ∧ C ∈ B
39 38 equsexvw ⊢ ∃ z z = x ∧ z x x ∈ A ∧ C ∈ ⦋ z / x⦌ B ↔ x ∈ A ∧ C ∈ B
40 33 39 bitri ⊢ ∃ z z x x ∈ A ∧ x C ∈ z × ⦋ z / x⦌ B ↔ x ∈ A ∧ C ∈ B
41 2 24 40 3bitri ⊢ x C ∈ ⋃ x ∈ A x × B ↔ x ∈ A ∧ C ∈ B