Metamath Proof Explorer


Theorem oppccofval

Description: Composition in the opposite category. (Contributed by Mario Carneiro, 2-Jan-2017)

Ref Expression
Hypotheses oppcco.b ⊢ B = Base C
oppcco.c ⊢ · ˙ = comp ⁡ C
oppcco.o ⊢ O = oppCat ⁡ C
oppcco.x ⊢ φ → X ∈ B
oppcco.y ⊢ φ → Y ∈ B
oppcco.z ⊢ φ → Z ∈ B
Assertion oppccofval ⊢ φ → X Y comp ⁡ O Z = tpos Z Y · ˙ X

Proof

Step Hyp Ref Expression
1 oppcco.b ⊢ B = Base C
2 oppcco.c ⊢ · ˙ = comp ⁡ C
3 oppcco.o ⊢ O = oppCat ⁡ C
4 oppcco.x ⊢ φ → X ∈ B
5 oppcco.y ⊢ φ → Y ∈ B
6 oppcco.z ⊢ φ → Z ∈ B
7 elfvex ⊢ X ∈ Base C → C ∈ V
8 7 1 eleq2s ⊢ X ∈ B → C ∈ V
9 eqid ⊢ Hom ⁡ C = Hom ⁡ C
10 1 9 2 3 oppcval ⊢ C ∈ V → O = C sSet Hom ⁡ ndx tpos Hom ⁡ C sSet comp ⁡ ndx u ∈ B × B , z ∈ B ⟼ tpos z 2 nd ⁡ u · ˙ 1 st ⁡ u
11 4 8 10 3syl ⊢ φ → O = C sSet Hom ⁡ ndx tpos Hom ⁡ C sSet comp ⁡ ndx u ∈ B × B , z ∈ B ⟼ tpos z 2 nd ⁡ u · ˙ 1 st ⁡ u
12 11 fveq2d ⊢ φ → comp ⁡ O = comp ⁡ C sSet Hom ⁡ ndx tpos Hom ⁡ C sSet comp ⁡ ndx u ∈ B × B , z ∈ B ⟼ tpos z 2 nd ⁡ u · ˙ 1 st ⁡ u
13 ovex ⊢ C sSet Hom ⁡ ndx tpos Hom ⁡ C ∈ V
14 1 fvexi ⊢ B ∈ V
15 14 14 xpex ⊢ B × B ∈ V
16 15 14 mpoex ⊢ u ∈ B × B , z ∈ B ⟼ tpos z 2 nd ⁡ u · ˙ 1 st ⁡ u ∈ V
17 ccoid ⊢ comp = Slot comp ⁡ ndx
18 17 setsid ⊢ C sSet Hom ⁡ ndx tpos Hom ⁡ C ∈ V ∧ u ∈ B × B , z ∈ B ⟼ tpos z 2 nd ⁡ u · ˙ 1 st ⁡ u ∈ V → u ∈ B × B , z ∈ B ⟼ tpos z 2 nd ⁡ u · ˙ 1 st ⁡ u = comp ⁡ C sSet Hom ⁡ ndx tpos Hom ⁡ C sSet comp ⁡ ndx u ∈ B × B , z ∈ B ⟼ tpos z 2 nd ⁡ u · ˙ 1 st ⁡ u
19 13 16 18 mp2an ⊢ u ∈ B × B , z ∈ B ⟼ tpos z 2 nd ⁡ u · ˙ 1 st ⁡ u = comp ⁡ C sSet Hom ⁡ ndx tpos Hom ⁡ C sSet comp ⁡ ndx u ∈ B × B , z ∈ B ⟼ tpos z 2 nd ⁡ u · ˙ 1 st ⁡ u
20 12 19 eqtr4di ⊢ φ → comp ⁡ O = u ∈ B × B , z ∈ B ⟼ tpos z 2 nd ⁡ u · ˙ 1 st ⁡ u
21 simprr ⊢ φ ∧ u = X Y ∧ z = Z → z = Z
22 simprl ⊢ φ ∧ u = X Y ∧ z = Z → u = X Y
23 22 fveq2d ⊢ φ ∧ u = X Y ∧ z = Z → 2 nd ⁡ u = 2 nd ⁡ X Y
24 5 adantr ⊢ φ ∧ u = X Y ∧ z = Z → Y ∈ B
25 op2ndg ⊢ X ∈ B ∧ Y ∈ B → 2 nd ⁡ X Y = Y
26 4 24 25 syl2an2r ⊢ φ ∧ u = X Y ∧ z = Z → 2 nd ⁡ X Y = Y
27 23 26 eqtrd ⊢ φ ∧ u = X Y ∧ z = Z → 2 nd ⁡ u = Y
28 21 27 opeq12d ⊢ φ ∧ u = X Y ∧ z = Z → z 2 nd ⁡ u = Z Y
29 22 fveq2d ⊢ φ ∧ u = X Y ∧ z = Z → 1 st ⁡ u = 1 st ⁡ X Y
30 op1stg ⊢ X ∈ B ∧ Y ∈ B → 1 st ⁡ X Y = X
31 4 24 30 syl2an2r ⊢ φ ∧ u = X Y ∧ z = Z → 1 st ⁡ X Y = X
32 29 31 eqtrd ⊢ φ ∧ u = X Y ∧ z = Z → 1 st ⁡ u = X
33 28 32 oveq12d ⊢ φ ∧ u = X Y ∧ z = Z → z 2 nd ⁡ u · ˙ 1 st ⁡ u = Z Y · ˙ X
34 33 tposeqd ⊢ φ ∧ u = X Y ∧ z = Z → tpos z 2 nd ⁡ u · ˙ 1 st ⁡ u = tpos Z Y · ˙ X
35 4 5 opelxpd ⊢ φ → X Y ∈ B × B
36 ovex ⊢ Z Y · ˙ X ∈ V
37 36 tposex ⊢ tpos Z Y · ˙ X ∈ V
38 37 a1i ⊢ φ → tpos Z Y · ˙ X ∈ V
39 20 34 35 6 38 ovmpod ⊢ φ → X Y comp ⁡ O Z = tpos Z Y · ˙ X