Metamath Proof Explorer


Theorem primrootlekpowne0

Description: There is no smaller power of a primitive root that sends it to the neutral element. (Contributed by metakunt, 15-May-2025)

Ref Expression
Hypotheses primrootlekpowne0.1 ⊢ φ → R ∈ CMnd
primrootlekpowne0.2 ⊢ φ → K ∈ ℕ
primrootlekpowne0.3 ⊢ φ → M ∈ R PrimRoots K
primrootlekpowne0.4 ⊢ φ → N ∈ 1 … K − 1
Assertion primrootlekpowne0 ⊢ φ → N ⋅ R M ≠ 0 R

Proof

Step Hyp Ref Expression
1 primrootlekpowne0.1 ⊢ φ → R ∈ CMnd
2 primrootlekpowne0.2 ⊢ φ → K ∈ ℕ
3 primrootlekpowne0.3 ⊢ φ → M ∈ R PrimRoots K
4 primrootlekpowne0.4 ⊢ φ → N ∈ 1 … K − 1
5 oveq1 ⊢ l = N → l ⋅ R M = N ⋅ R M
6 5 eqeq1d ⊢ l = N → l ⋅ R M = 0 R ↔ N ⋅ R M = 0 R
7 breq2 ⊢ l = N → K ∥ l ↔ K ∥ N
8 6 7 imbi12d ⊢ l = N → l ⋅ R M = 0 R → K ∥ l ↔ N ⋅ R M = 0 R → K ∥ N
9 2 nnnn0d ⊢ φ → K ∈ ℕ 0
10 eqid ⊢ ⋅ R = ⋅ R
11 1 9 10 isprimroot ⊢ φ → M ∈ R PrimRoots K ↔ M ∈ Base R ∧ K ⋅ R M = 0 R ∧ ∀ l ∈ ℕ 0 l ⋅ R M = 0 R → K ∥ l
12 11 biimpd ⊢ φ → M ∈ R PrimRoots K → M ∈ Base R ∧ K ⋅ R M = 0 R ∧ ∀ l ∈ ℕ 0 l ⋅ R M = 0 R → K ∥ l
13 3 12 mpd ⊢ φ → M ∈ Base R ∧ K ⋅ R M = 0 R ∧ ∀ l ∈ ℕ 0 l ⋅ R M = 0 R → K ∥ l
14 13 simp3d ⊢ φ → ∀ l ∈ ℕ 0 l ⋅ R M = 0 R → K ∥ l
15 14 adantr ⊢ φ ∧ N ⋅ R M = 0 R → ∀ l ∈ ℕ 0 l ⋅ R M = 0 R → K ∥ l
16 elfznn ⊢ N ∈ 1 … K − 1 → N ∈ ℕ
17 4 16 syl ⊢ φ → N ∈ ℕ
18 17 nnnn0d ⊢ φ → N ∈ ℕ 0
19 18 adantr ⊢ φ ∧ N ⋅ R M = 0 R → N ∈ ℕ 0
20 8 15 19 rspcdva ⊢ φ ∧ N ⋅ R M = 0 R → N ⋅ R M = 0 R → K ∥ N
21 20 syldbl2 ⊢ φ ∧ N ⋅ R M = 0 R → K ∥ N
22 17 nnred ⊢ φ → N ∈ ℝ
23 2 nnred ⊢ φ → K ∈ ℝ
24 1red ⊢ φ → 1 ∈ ℝ
25 23 24 resubcld ⊢ φ → K − 1 ∈ ℝ
26 elfzle2 ⊢ N ∈ 1 … K − 1 → N ≤ K − 1
27 4 26 syl ⊢ φ → N ≤ K − 1
28 23 ltm1d ⊢ φ → K − 1 < K
29 22 25 23 27 28 lelttrd ⊢ φ → N < K
30 22 23 ltnled ⊢ φ → N < K ↔ ¬ K ≤ N
31 29 30 mpbid ⊢ φ → ¬ K ≤ N
32 9 nn0zd ⊢ φ → K ∈ ℤ
33 dvdsle ⊢ K ∈ ℤ ∧ N ∈ ℕ → K ∥ N → K ≤ N
34 32 17 33 syl2anc ⊢ φ → K ∥ N → K ≤ N
35 34 con3d ⊢ φ → ¬ K ≤ N → ¬ K ∥ N
36 31 35 mpd ⊢ φ → ¬ K ∥ N
37 36 adantr ⊢ φ ∧ N ⋅ R M = 0 R → ¬ K ∥ N
38 21 37 pm2.21dd ⊢ φ ∧ N ⋅ R M = 0 R → N ⋅ R M ≠ 0 R
39 simpr ⊢ φ ∧ N ⋅ R M ≠ 0 R → N ⋅ R M ≠ 0 R
40 38 39 pm2.61dane ⊢ φ → N ⋅ R M ≠ 0 R