Metamath Proof Explorer


Theorem readdcnnred

Description: The sum of a real number and an imaginary number is not a real number. (Contributed by AV, 23-Jan-2023)

Ref Expression
Hypotheses recnaddnred.a ⊢ φ → A ∈ ℝ
recnaddnred.b ⊢ φ → B ∈ ℂ ∖ ℝ
Assertion readdcnnred ⊢ φ → A + B ∉ ℝ

Proof

Step Hyp Ref Expression
1 recnaddnred.a ⊢ φ → A ∈ ℝ
2 recnaddnred.b ⊢ φ → B ∈ ℂ ∖ ℝ
3 2 eldifbd ⊢ φ → ¬ B ∈ ℝ
4 df-nel ⊢ A + B ∉ ℝ ↔ ¬ A + B ∈ ℝ
5 1 recnd ⊢ φ → A ∈ ℂ
6 2 eldifad ⊢ φ → B ∈ ℂ
7 5 6 addcld ⊢ φ → A + B ∈ ℂ
8 reim0b ⊢ A + B ∈ ℂ → A + B ∈ ℝ ↔ ℑ ⁡ A + B = 0
9 7 8 syl ⊢ φ → A + B ∈ ℝ ↔ ℑ ⁡ A + B = 0
10 1 reim0d ⊢ φ → ℑ ⁡ A = 0
11 10 oveq1d ⊢ φ → ℑ ⁡ A + ℑ ⁡ B = 0 + ℑ ⁡ B
12 6 imcld ⊢ φ → ℑ ⁡ B ∈ ℝ
13 12 recnd ⊢ φ → ℑ ⁡ B ∈ ℂ
14 13 addlidd ⊢ φ → 0 + ℑ ⁡ B = ℑ ⁡ B
15 11 14 eqtrd ⊢ φ → ℑ ⁡ A + ℑ ⁡ B = ℑ ⁡ B
16 15 eqeq1d ⊢ φ → ℑ ⁡ A + ℑ ⁡ B = 0 ↔ ℑ ⁡ B = 0
17 5 6 imaddd ⊢ φ → ℑ ⁡ A + B = ℑ ⁡ A + ℑ ⁡ B
18 17 eqeq1d ⊢ φ → ℑ ⁡ A + B = 0 ↔ ℑ ⁡ A + ℑ ⁡ B = 0
19 reim0b ⊢ B ∈ ℂ → B ∈ ℝ ↔ ℑ ⁡ B = 0
20 6 19 syl ⊢ φ → B ∈ ℝ ↔ ℑ ⁡ B = 0
21 16 18 20 3bitr4d ⊢ φ → ℑ ⁡ A + B = 0 ↔ B ∈ ℝ
22 9 21 bitrd ⊢ φ → A + B ∈ ℝ ↔ B ∈ ℝ
23 22 notbid ⊢ φ → ¬ A + B ∈ ℝ ↔ ¬ B ∈ ℝ
24 4 23 bitrid ⊢ φ → A + B ∉ ℝ ↔ ¬ B ∈ ℝ
25 3 24 mpbird ⊢ φ → A + B ∉ ℝ