Metamath Proof Explorer


Theorem relexpxpnnidm

Description: Any positive power of a Cartesian product of non-disjoint sets is itself. (Contributed by RP, 13-Jun-2020)

Ref Expression
Assertion relexpxpnnidm ⊢ N ∈ ℕ → A ∈ U ∧ B ∈ V ∧ A ∩ B ≠ ∅ → A × B ↑ r N = A × B

Proof

Step Hyp Ref Expression
1 oveq2 ⊢ x = 1 → A × B ↑ r x = A × B ↑ r 1
2 1 eqeq1d ⊢ x = 1 → A × B ↑ r x = A × B ↔ A × B ↑ r 1 = A × B
3 2 imbi2d ⊢ x = 1 → A ∈ U ∧ B ∈ V ∧ A ∩ B ≠ ∅ → A × B ↑ r x = A × B ↔ A ∈ U ∧ B ∈ V ∧ A ∩ B ≠ ∅ → A × B ↑ r 1 = A × B
4 oveq2 ⊢ x = y → A × B ↑ r x = A × B ↑ r y
5 4 eqeq1d ⊢ x = y → A × B ↑ r x = A × B ↔ A × B ↑ r y = A × B
6 5 imbi2d ⊢ x = y → A ∈ U ∧ B ∈ V ∧ A ∩ B ≠ ∅ → A × B ↑ r x = A × B ↔ A ∈ U ∧ B ∈ V ∧ A ∩ B ≠ ∅ → A × B ↑ r y = A × B
7 oveq2 ⊢ x = y + 1 → A × B ↑ r x = A × B ↑ r y + 1
8 7 eqeq1d ⊢ x = y + 1 → A × B ↑ r x = A × B ↔ A × B ↑ r y + 1 = A × B
9 8 imbi2d ⊢ x = y + 1 → A ∈ U ∧ B ∈ V ∧ A ∩ B ≠ ∅ → A × B ↑ r x = A × B ↔ A ∈ U ∧ B ∈ V ∧ A ∩ B ≠ ∅ → A × B ↑ r y + 1 = A × B
10 oveq2 ⊢ x = N → A × B ↑ r x = A × B ↑ r N
11 10 eqeq1d ⊢ x = N → A × B ↑ r x = A × B ↔ A × B ↑ r N = A × B
12 11 imbi2d ⊢ x = N → A ∈ U ∧ B ∈ V ∧ A ∩ B ≠ ∅ → A × B ↑ r x = A × B ↔ A ∈ U ∧ B ∈ V ∧ A ∩ B ≠ ∅ → A × B ↑ r N = A × B
13 3simpa ⊢ A ∈ U ∧ B ∈ V ∧ A ∩ B ≠ ∅ → A ∈ U ∧ B ∈ V
14 xpexg ⊢ A ∈ U ∧ B ∈ V → A × B ∈ V
15 relexp1g ⊢ A × B ∈ V → A × B ↑ r 1 = A × B
16 13 14 15 3syl ⊢ A ∈ U ∧ B ∈ V ∧ A ∩ B ≠ ∅ → A × B ↑ r 1 = A × B
17 simp2 ⊢ y ∈ ℕ ∧ A ∈ U ∧ B ∈ V ∧ A ∩ B ≠ ∅ ∧ A × B ↑ r y = A × B → A ∈ U ∧ B ∈ V ∧ A ∩ B ≠ ∅
18 17 13 14 3syl ⊢ y ∈ ℕ ∧ A ∈ U ∧ B ∈ V ∧ A ∩ B ≠ ∅ ∧ A × B ↑ r y = A × B → A × B ∈ V
19 simp1 ⊢ y ∈ ℕ ∧ A ∈ U ∧ B ∈ V ∧ A ∩ B ≠ ∅ ∧ A × B ↑ r y = A × B → y ∈ ℕ
20 relexpsucnnr ⊢ A × B ∈ V ∧ y ∈ ℕ → A × B ↑ r y + 1 = A × B ↑ r y ∘ A × B
21 18 19 20 syl2anc ⊢ y ∈ ℕ ∧ A ∈ U ∧ B ∈ V ∧ A ∩ B ≠ ∅ ∧ A × B ↑ r y = A × B → A × B ↑ r y + 1 = A × B ↑ r y ∘ A × B
22 simp3 ⊢ y ∈ ℕ ∧ A ∈ U ∧ B ∈ V ∧ A ∩ B ≠ ∅ ∧ A × B ↑ r y = A × B → A × B ↑ r y = A × B
23 22 coeq1d ⊢ y ∈ ℕ ∧ A ∈ U ∧ B ∈ V ∧ A ∩ B ≠ ∅ ∧ A × B ↑ r y = A × B → A × B ↑ r y ∘ A × B = A × B ∘ A × B
24 simp23 ⊢ y ∈ ℕ ∧ A ∈ U ∧ B ∈ V ∧ A ∩ B ≠ ∅ ∧ A × B ↑ r y = A × B → A ∩ B ≠ ∅
25 24 xpcoidgend ⊢ y ∈ ℕ ∧ A ∈ U ∧ B ∈ V ∧ A ∩ B ≠ ∅ ∧ A × B ↑ r y = A × B → A × B ∘ A × B = A × B
26 21 23 25 3eqtrd ⊢ y ∈ ℕ ∧ A ∈ U ∧ B ∈ V ∧ A ∩ B ≠ ∅ ∧ A × B ↑ r y = A × B → A × B ↑ r y + 1 = A × B
27 26 3exp ⊢ y ∈ ℕ → A ∈ U ∧ B ∈ V ∧ A ∩ B ≠ ∅ → A × B ↑ r y = A × B → A × B ↑ r y + 1 = A × B
28 27 a2d ⊢ y ∈ ℕ → A ∈ U ∧ B ∈ V ∧ A ∩ B ≠ ∅ → A × B ↑ r y = A × B → A ∈ U ∧ B ∈ V ∧ A ∩ B ≠ ∅ → A × B ↑ r y + 1 = A × B
29 3 6 9 12 16 28 nnind ⊢ N ∈ ℕ → A ∈ U ∧ B ∈ V ∧ A ∩ B ≠ ∅ → A × B ↑ r N = A × B