Metamath Proof Explorer


Theorem ringurd

Description: Deduce the unity element of a ring from its properties. (Contributed by Thierry Arnoux, 6-Sep-2016)

Ref Expression
Hypotheses ringurd.b ⊢ φ → B = Base R
ringurd.p ⊢ φ → · ˙ = ⋅ R
ringurd.z ⊢ φ → 1 ˙ ∈ B
ringurd.i ⊢ φ ∧ x ∈ B → 1 ˙ · ˙ x = x
ringurd.j ⊢ φ ∧ x ∈ B → x · ˙ 1 ˙ = x
Assertion ringurd ⊢ φ → 1 ˙ = 1 R

Proof

Step Hyp Ref Expression
1 ringurd.b ⊢ φ → B = Base R
2 ringurd.p ⊢ φ → · ˙ = ⋅ R
3 ringurd.z ⊢ φ → 1 ˙ ∈ B
4 ringurd.i ⊢ φ ∧ x ∈ B → 1 ˙ · ˙ x = x
5 ringurd.j ⊢ φ ∧ x ∈ B → x · ˙ 1 ˙ = x
6 eqid ⊢ Base R = Base R
7 eqid ⊢ ⋅ R = ⋅ R
8 eqid ⊢ 1 R = 1 R
9 6 7 8 dfur2 ⊢ 1 R = ι e | e ∈ Base R ∧ ∀ x ∈ Base R e ⋅ R x = x ∧ x ⋅ R e = x
10 3 1 eleqtrd ⊢ φ → 1 ˙ ∈ Base R
11 4 5 jca ⊢ φ ∧ x ∈ B → 1 ˙ · ˙ x = x ∧ x · ˙ 1 ˙ = x
12 11 ralrimiva ⊢ φ → ∀ x ∈ B 1 ˙ · ˙ x = x ∧ x · ˙ 1 ˙ = x
13 2 adantr ⊢ φ ∧ x ∈ B → · ˙ = ⋅ R
14 13 oveqd ⊢ φ ∧ x ∈ B → 1 ˙ · ˙ x = 1 ˙ ⋅ R x
15 14 eqeq1d ⊢ φ ∧ x ∈ B → 1 ˙ · ˙ x = x ↔ 1 ˙ ⋅ R x = x
16 13 oveqd ⊢ φ ∧ x ∈ B → x · ˙ 1 ˙ = x ⋅ R 1 ˙
17 16 eqeq1d ⊢ φ ∧ x ∈ B → x · ˙ 1 ˙ = x ↔ x ⋅ R 1 ˙ = x
18 15 17 anbi12d ⊢ φ ∧ x ∈ B → 1 ˙ · ˙ x = x ∧ x · ˙ 1 ˙ = x ↔ 1 ˙ ⋅ R x = x ∧ x ⋅ R 1 ˙ = x
19 1 18 raleqbidva ⊢ φ → ∀ x ∈ B 1 ˙ · ˙ x = x ∧ x · ˙ 1 ˙ = x ↔ ∀ x ∈ Base R 1 ˙ ⋅ R x = x ∧ x ⋅ R 1 ˙ = x
20 12 19 mpbid ⊢ φ → ∀ x ∈ Base R 1 ˙ ⋅ R x = x ∧ x ⋅ R 1 ˙ = x
21 1 eleq2d ⊢ φ → e ∈ B ↔ e ∈ Base R
22 13 oveqd ⊢ φ ∧ x ∈ B → e · ˙ x = e ⋅ R x
23 22 eqeq1d ⊢ φ ∧ x ∈ B → e · ˙ x = x ↔ e ⋅ R x = x
24 13 oveqd ⊢ φ ∧ x ∈ B → x · ˙ e = x ⋅ R e
25 24 eqeq1d ⊢ φ ∧ x ∈ B → x · ˙ e = x ↔ x ⋅ R e = x
26 23 25 anbi12d ⊢ φ ∧ x ∈ B → e · ˙ x = x ∧ x · ˙ e = x ↔ e ⋅ R x = x ∧ x ⋅ R e = x
27 1 26 raleqbidva ⊢ φ → ∀ x ∈ B e · ˙ x = x ∧ x · ˙ e = x ↔ ∀ x ∈ Base R e ⋅ R x = x ∧ x ⋅ R e = x
28 21 27 anbi12d ⊢ φ → e ∈ B ∧ ∀ x ∈ B e · ˙ x = x ∧ x · ˙ e = x ↔ e ∈ Base R ∧ ∀ x ∈ Base R e ⋅ R x = x ∧ x ⋅ R e = x
29 4 ralrimiva ⊢ φ → ∀ x ∈ B 1 ˙ · ˙ x = x
30 29 adantr ⊢ φ ∧ e ∈ B → ∀ x ∈ B 1 ˙ · ˙ x = x
31 simpr ⊢ φ ∧ e ∈ B → e ∈ B
32 simpr ⊢ φ ∧ e ∈ B ∧ x = e → x = e
33 32 oveq2d ⊢ φ ∧ e ∈ B ∧ x = e → 1 ˙ · ˙ x = 1 ˙ · ˙ e
34 33 32 eqeq12d ⊢ φ ∧ e ∈ B ∧ x = e → 1 ˙ · ˙ x = x ↔ 1 ˙ · ˙ e = e
35 31 34 rspcdv ⊢ φ ∧ e ∈ B → ∀ x ∈ B 1 ˙ · ˙ x = x → 1 ˙ · ˙ e = e
36 30 35 mpd ⊢ φ ∧ e ∈ B → 1 ˙ · ˙ e = e
37 36 adantrr ⊢ φ ∧ e ∈ B ∧ ∀ x ∈ B e · ˙ x = x ∧ x · ˙ e = x → 1 ˙ · ˙ e = e
38 3 adantr ⊢ φ ∧ e ∈ B ∧ ∀ x ∈ B e · ˙ x = x ∧ x · ˙ e = x → 1 ˙ ∈ B
39 simprr ⊢ φ ∧ e ∈ B ∧ ∀ x ∈ B e · ˙ x = x ∧ x · ˙ e = x → ∀ x ∈ B e · ˙ x = x ∧ x · ˙ e = x
40 oveq2 ⊢ x = 1 ˙ → e · ˙ x = e · ˙ 1 ˙
41 id ⊢ x = 1 ˙ → x = 1 ˙
42 40 41 eqeq12d ⊢ x = 1 ˙ → e · ˙ x = x ↔ e · ˙ 1 ˙ = 1 ˙
43 oveq1 ⊢ x = 1 ˙ → x · ˙ e = 1 ˙ · ˙ e
44 43 41 eqeq12d ⊢ x = 1 ˙ → x · ˙ e = x ↔ 1 ˙ · ˙ e = 1 ˙
45 42 44 anbi12d ⊢ x = 1 ˙ → e · ˙ x = x ∧ x · ˙ e = x ↔ e · ˙ 1 ˙ = 1 ˙ ∧ 1 ˙ · ˙ e = 1 ˙
46 45 rspcva ⊢ 1 ˙ ∈ B ∧ ∀ x ∈ B e · ˙ x = x ∧ x · ˙ e = x → e · ˙ 1 ˙ = 1 ˙ ∧ 1 ˙ · ˙ e = 1 ˙
47 46 simprd ⊢ 1 ˙ ∈ B ∧ ∀ x ∈ B e · ˙ x = x ∧ x · ˙ e = x → 1 ˙ · ˙ e = 1 ˙
48 38 39 47 syl2anc ⊢ φ ∧ e ∈ B ∧ ∀ x ∈ B e · ˙ x = x ∧ x · ˙ e = x → 1 ˙ · ˙ e = 1 ˙
49 37 48 eqtr3d ⊢ φ ∧ e ∈ B ∧ ∀ x ∈ B e · ˙ x = x ∧ x · ˙ e = x → e = 1 ˙
50 49 ex ⊢ φ → e ∈ B ∧ ∀ x ∈ B e · ˙ x = x ∧ x · ˙ e = x → e = 1 ˙
51 28 50 sylbird ⊢ φ → e ∈ Base R ∧ ∀ x ∈ Base R e ⋅ R x = x ∧ x ⋅ R e = x → e = 1 ˙
52 51 alrimiv ⊢ φ → ∀ e e ∈ Base R ∧ ∀ x ∈ Base R e ⋅ R x = x ∧ x ⋅ R e = x → e = 1 ˙
53 eleq1 ⊢ e = 1 ˙ → e ∈ Base R ↔ 1 ˙ ∈ Base R
54 oveq1 ⊢ e = 1 ˙ → e ⋅ R x = 1 ˙ ⋅ R x
55 54 eqeq1d ⊢ e = 1 ˙ → e ⋅ R x = x ↔ 1 ˙ ⋅ R x = x
56 55 ovanraleqv ⊢ e = 1 ˙ → ∀ x ∈ Base R e ⋅ R x = x ∧ x ⋅ R e = x ↔ ∀ x ∈ Base R 1 ˙ ⋅ R x = x ∧ x ⋅ R 1 ˙ = x
57 53 56 anbi12d ⊢ e = 1 ˙ → e ∈ Base R ∧ ∀ x ∈ Base R e ⋅ R x = x ∧ x ⋅ R e = x ↔ 1 ˙ ∈ Base R ∧ ∀ x ∈ Base R 1 ˙ ⋅ R x = x ∧ x ⋅ R 1 ˙ = x
58 57 eqeu ⊢ 1 ˙ ∈ Base R ∧ 1 ˙ ∈ Base R ∧ ∀ x ∈ Base R 1 ˙ ⋅ R x = x ∧ x ⋅ R 1 ˙ = x ∧ ∀ e e ∈ Base R ∧ ∀ x ∈ Base R e ⋅ R x = x ∧ x ⋅ R e = x → e = 1 ˙ → ∃! e e ∈ Base R ∧ ∀ x ∈ Base R e ⋅ R x = x ∧ x ⋅ R e = x
59 10 10 20 52 58 syl121anc ⊢ φ → ∃! e e ∈ Base R ∧ ∀ x ∈ Base R e ⋅ R x = x ∧ x ⋅ R e = x
60 57 iota2 ⊢ 1 ˙ ∈ B ∧ ∃! e e ∈ Base R ∧ ∀ x ∈ Base R e ⋅ R x = x ∧ x ⋅ R e = x → 1 ˙ ∈ Base R ∧ ∀ x ∈ Base R 1 ˙ ⋅ R x = x ∧ x ⋅ R 1 ˙ = x ↔ ι e | e ∈ Base R ∧ ∀ x ∈ Base R e ⋅ R x = x ∧ x ⋅ R e = x = 1 ˙
61 3 59 60 syl2anc ⊢ φ → 1 ˙ ∈ Base R ∧ ∀ x ∈ Base R 1 ˙ ⋅ R x = x ∧ x ⋅ R 1 ˙ = x ↔ ι e | e ∈ Base R ∧ ∀ x ∈ Base R e ⋅ R x = x ∧ x ⋅ R e = x = 1 ˙
62 10 20 61 mpbi2and ⊢ φ → ι e | e ∈ Base R ∧ ∀ x ∈ Base R e ⋅ R x = x ∧ x ⋅ R e = x = 1 ˙
63 9 62 eqtr2id ⊢ φ → 1 ˙ = 1 R