Metamath Proof Explorer


Theorem rngqiprngfulem3

Description: Lemma 3 for rngqiprngfu (and lemma for rngqiprngu ). (Contributed by AV, 16-Mar-2025)

Ref Expression
Hypotheses rngqiprngfu.r ⊢ φ → R ∈ Rng
rngqiprngfu.i ⊢ φ → I ∈ 2Ideal ⁡ R
rngqiprngfu.j ⊢ J = R ↾ 𝑠 I
rngqiprngfu.u ⊢ φ → J ∈ Ring
rngqiprngfu.b ⊢ B = Base R
rngqiprngfu.t ⊢ · ˙ = ⋅ R
rngqiprngfu.1 ⊢ 1 ˙ = 1 J
rngqiprngfu.g ⊢ ∼ ˙ = R ~ QG I
rngqiprngfu.q ⊢ Q = R / 𝑠 ∼ ˙
rngqiprngfu.v ⊢ φ → Q ∈ Ring
rngqiprngfu.e ⊢ φ → E ∈ 1 Q
rngqiprngfu.m ⊢ - ˙ = - R
rngqiprngfu.a ⊢ + ˙ = + R
rngqiprngfu.n ⊢ U = E - ˙ 1 ˙ · ˙ E + ˙ 1 ˙
Assertion rngqiprngfulem3 ⊢ φ → U ∈ B

Proof

Step Hyp Ref Expression
1 rngqiprngfu.r ⊢ φ → R ∈ Rng
2 rngqiprngfu.i ⊢ φ → I ∈ 2Ideal ⁡ R
3 rngqiprngfu.j ⊢ J = R ↾ 𝑠 I
4 rngqiprngfu.u ⊢ φ → J ∈ Ring
5 rngqiprngfu.b ⊢ B = Base R
6 rngqiprngfu.t ⊢ · ˙ = ⋅ R
7 rngqiprngfu.1 ⊢ 1 ˙ = 1 J
8 rngqiprngfu.g ⊢ ∼ ˙ = R ~ QG I
9 rngqiprngfu.q ⊢ Q = R / 𝑠 ∼ ˙
10 rngqiprngfu.v ⊢ φ → Q ∈ Ring
11 rngqiprngfu.e ⊢ φ → E ∈ 1 Q
12 rngqiprngfu.m ⊢ - ˙ = - R
13 rngqiprngfu.a ⊢ + ˙ = + R
14 rngqiprngfu.n ⊢ U = E - ˙ 1 ˙ · ˙ E + ˙ 1 ˙
15 rnggrp ⊢ R ∈ Rng → R ∈ Grp
16 1 15 syl ⊢ φ → R ∈ Grp
17 1 2 3 4 5 6 7 8 9 10 11 rngqiprngfulem2 ⊢ φ → E ∈ B
18 1 2 3 4 5 6 7 rngqiprng1elbas ⊢ φ → 1 ˙ ∈ B
19 5 6 rngcl ⊢ R ∈ Rng ∧ 1 ˙ ∈ B ∧ E ∈ B → 1 ˙ · ˙ E ∈ B
20 1 18 17 19 syl3anc ⊢ φ → 1 ˙ · ˙ E ∈ B
21 5 12 grpsubcl ⊢ R ∈ Grp ∧ E ∈ B ∧ 1 ˙ · ˙ E ∈ B → E - ˙ 1 ˙ · ˙ E ∈ B
22 16 17 20 21 syl3anc ⊢ φ → E - ˙ 1 ˙ · ˙ E ∈ B
23 5 13 16 22 18 grpcld ⊢ φ → E - ˙ 1 ˙ · ˙ E + ˙ 1 ˙ ∈ B
24 14 23 eqeltrid ⊢ φ → U ∈ B