Metamath Proof Explorer


Theorem lidlrng

Description: A (left) ideal of a ring is a non-unital ring. (Contributed by AV, 17-Feb-2020) (Proof shortened by AV, 11-Mar-2025)

Ref Expression
Hypotheses lidlabl.l ⊢ 𝐿 = ( LIdeal ‘ 𝑅 )
lidlabl.i ⊢ 𝐼 = ( 𝑅 ↾s 𝑈 )
Assertion lidlrng ( ( 𝑅 ∈ Ring ∧ 𝑈 ∈ 𝐿 ) → 𝐼 ∈ Rng )

Proof

Step Hyp Ref Expression
1 lidlabl.l ⊢ 𝐿 = ( LIdeal ‘ 𝑅 )
2 lidlabl.i ⊢ 𝐼 = ( 𝑅 ↾s 𝑈 )
3 ringrng ⊢ ( 𝑅 ∈ Ring → 𝑅 ∈ Rng )
4 3 adantr ⊢ ( ( 𝑅 ∈ Ring ∧ 𝑈 ∈ 𝐿 ) → 𝑅 ∈ Rng )
5 simpr ⊢ ( ( 𝑅 ∈ Ring ∧ 𝑈 ∈ 𝐿 ) → 𝑈 ∈ 𝐿 )
6 1 lidlsubg ⊢ ( ( 𝑅 ∈ Ring ∧ 𝑈 ∈ 𝐿 ) → 𝑈 ∈ ( SubGrp ‘ 𝑅 ) )
7 1 2 rnglidlrng ⊢ ( ( 𝑅 ∈ Rng ∧ 𝑈 ∈ 𝐿 ∧ 𝑈 ∈ ( SubGrp ‘ 𝑅 ) ) → 𝐼 ∈ Rng )
8 4 5 6 7 syl3anc ⊢ ( ( 𝑅 ∈ Ring ∧ 𝑈 ∈ 𝐿 ) → 𝐼 ∈ Rng )