Metamath Proof Explorer


Theorem saldifcl2

Description: The difference of two elements of a sigma-algebra is in the sigma-algebra. (Contributed by Glauco Siliprandi, 17-Aug-2020)

Ref Expression
Assertion saldifcl2 ( ( 𝑆 ∈ SAlg ∧ 𝐸 ∈ 𝑆 ∧ 𝐹 ∈ 𝑆 ) → ( 𝐸 ∖ 𝐹 ) ∈ 𝑆 )

Proof

Step Hyp Ref Expression
1 indif2 ⊢ ( 𝐸 ∩ ( ∪ 𝑆 ∖ 𝐹 ) ) = ( ( 𝐸 ∩ ∪ 𝑆 ) ∖ 𝐹 )
2 1 a1i ⊢ ( ( 𝑆 ∈ SAlg ∧ 𝐸 ∈ 𝑆 ∧ 𝐹 ∈ 𝑆 ) → ( 𝐸 ∩ ( ∪ 𝑆 ∖ 𝐹 ) ) = ( ( 𝐸 ∩ ∪ 𝑆 ) ∖ 𝐹 ) )
3 elssuni ⊢ ( 𝐸 ∈ 𝑆 → 𝐸 ⊆ ∪ 𝑆 )
4 dfss2 ⊢ ( 𝐸 ⊆ ∪ 𝑆 ↔ ( 𝐸 ∩ ∪ 𝑆 ) = 𝐸 )
5 3 4 sylib ⊢ ( 𝐸 ∈ 𝑆 → ( 𝐸 ∩ ∪ 𝑆 ) = 𝐸 )
6 5 difeq1d ⊢ ( 𝐸 ∈ 𝑆 → ( ( 𝐸 ∩ ∪ 𝑆 ) ∖ 𝐹 ) = ( 𝐸 ∖ 𝐹 ) )
7 6 3ad2ant2 ⊢ ( ( 𝑆 ∈ SAlg ∧ 𝐸 ∈ 𝑆 ∧ 𝐹 ∈ 𝑆 ) → ( ( 𝐸 ∩ ∪ 𝑆 ) ∖ 𝐹 ) = ( 𝐸 ∖ 𝐹 ) )
8 2 7 eqtr2d ⊢ ( ( 𝑆 ∈ SAlg ∧ 𝐸 ∈ 𝑆 ∧ 𝐹 ∈ 𝑆 ) → ( 𝐸 ∖ 𝐹 ) = ( 𝐸 ∩ ( ∪ 𝑆 ∖ 𝐹 ) ) )
9 simp1 ⊢ ( ( 𝑆 ∈ SAlg ∧ 𝐸 ∈ 𝑆 ∧ 𝐹 ∈ 𝑆 ) → 𝑆 ∈ SAlg )
10 simp2 ⊢ ( ( 𝑆 ∈ SAlg ∧ 𝐸 ∈ 𝑆 ∧ 𝐹 ∈ 𝑆 ) → 𝐸 ∈ 𝑆 )
11 saldifcl ⊢ ( ( 𝑆 ∈ SAlg ∧ 𝐹 ∈ 𝑆 ) → ( ∪ 𝑆 ∖ 𝐹 ) ∈ 𝑆 )
12 11 3adant2 ⊢ ( ( 𝑆 ∈ SAlg ∧ 𝐸 ∈ 𝑆 ∧ 𝐹 ∈ 𝑆 ) → ( ∪ 𝑆 ∖ 𝐹 ) ∈ 𝑆 )
13 salincl ⊢ ( ( 𝑆 ∈ SAlg ∧ 𝐸 ∈ 𝑆 ∧ ( ∪ 𝑆 ∖ 𝐹 ) ∈ 𝑆 ) → ( 𝐸 ∩ ( ∪ 𝑆 ∖ 𝐹 ) ) ∈ 𝑆 )
14 9 10 12 13 syl3anc ⊢ ( ( 𝑆 ∈ SAlg ∧ 𝐸 ∈ 𝑆 ∧ 𝐹 ∈ 𝑆 ) → ( 𝐸 ∩ ( ∪ 𝑆 ∖ 𝐹 ) ) ∈ 𝑆 )
15 8 14 eqeltrd ⊢ ( ( 𝑆 ∈ SAlg ∧ 𝐸 ∈ 𝑆 ∧ 𝐹 ∈ 𝑆 ) → ( 𝐸 ∖ 𝐹 ) ∈ 𝑆 )