Metamath Proof Explorer


Theorem 3cubes

Description: Every rational number is a sum of three rational cubes. See S. Ryley, The Ladies' Diary 122 (1825), 35. (Contributed by Igor Ieskov, 22-Jan-2024)

Ref Expression
Assertion 3cubes ⊢ A ∈ ℚ ↔ ∃ a ∈ ℚ ∃ b ∈ ℚ ∃ c ∈ ℚ A = a 3 + b 3 + c 3

Proof

Step Hyp Ref Expression
1 3nn ⊢ 3 ∈ ℕ
2 1 a1i ⊢ ¬ 3 3 ∈ ℕ → 3 ∈ ℕ
3 3nn0 ⊢ 3 ∈ ℕ 0
4 3 a1i ⊢ ¬ 3 3 ∈ ℕ → 3 ∈ ℕ 0
5 2 4 nnexpcld ⊢ ¬ 3 3 ∈ ℕ → 3 3 ∈ ℕ
6 5 pm2.18i ⊢ 3 3 ∈ ℕ
7 nnq ⊢ 3 3 ∈ ℕ → 3 3 ∈ ℚ
8 6 7 mp1i ⊢ A ∈ ℚ → 3 3 ∈ ℚ
9 qexpcl ⊢ A ∈ ℚ ∧ 3 ∈ ℕ 0 → A 3 ∈ ℚ
10 3 9 mpan2 ⊢ A ∈ ℚ → A 3 ∈ ℚ
11 qmulcl ⊢ 3 3 ∈ ℚ ∧ A 3 ∈ ℚ → 3 3 ⁢ A 3 ∈ ℚ
12 8 10 11 syl2anc ⊢ A ∈ ℚ → 3 3 ⁢ A 3 ∈ ℚ
13 1nn ⊢ 1 ∈ ℕ
14 nnq ⊢ 1 ∈ ℕ → 1 ∈ ℚ
15 13 14 ax-mp ⊢ 1 ∈ ℚ
16 qsubcl ⊢ 3 3 ⁢ A 3 ∈ ℚ ∧ 1 ∈ ℚ → 3 3 ⁢ A 3 − 1 ∈ ℚ
17 12 15 16 sylancl ⊢ A ∈ ℚ → 3 3 ⁢ A 3 − 1 ∈ ℚ
18 qsqcl ⊢ A ∈ ℚ → A 2 ∈ ℚ
19 qmulcl ⊢ 3 3 ∈ ℚ ∧ A 2 ∈ ℚ → 3 3 ⁢ A 2 ∈ ℚ
20 8 18 19 syl2anc ⊢ A ∈ ℚ → 3 3 ⁢ A 2 ∈ ℚ
21 nnq ⊢ 3 ∈ ℕ → 3 ∈ ℚ
22 1 21 ax-mp ⊢ 3 ∈ ℚ
23 qsqcl ⊢ 3 ∈ ℚ → 3 2 ∈ ℚ
24 22 23 mp1i ⊢ A ∈ ℚ → 3 2 ∈ ℚ
25 qmulcl ⊢ 3 2 ∈ ℚ ∧ A ∈ ℚ → 3 2 ⁢ A ∈ ℚ
26 24 25 mpancom ⊢ A ∈ ℚ → 3 2 ⁢ A ∈ ℚ
27 qaddcl ⊢ 3 3 ⁢ A 2 ∈ ℚ ∧ 3 2 ⁢ A ∈ ℚ → 3 3 ⁢ A 2 + 3 2 ⁢ A ∈ ℚ
28 20 26 27 syl2anc ⊢ A ∈ ℚ → 3 3 ⁢ A 2 + 3 2 ⁢ A ∈ ℚ
29 qaddcl ⊢ 3 3 ⁢ A 2 + 3 2 ⁢ A ∈ ℚ ∧ 3 ∈ ℚ → 3 3 ⁢ A 2 + 3 2 ⁢ A + 3 ∈ ℚ
30 28 22 29 sylancl ⊢ A ∈ ℚ → 3 3 ⁢ A 2 + 3 2 ⁢ A + 3 ∈ ℚ
31 id ⊢ A ∈ ℚ → A ∈ ℚ
32 31 3cubeslem2 ⊢ A ∈ ℚ → ¬ 3 3 ⁢ A 2 + 3 2 ⁢ A + 3 = 0
33 32 neqned ⊢ A ∈ ℚ → 3 3 ⁢ A 2 + 3 2 ⁢ A + 3 ≠ 0
34 qdivcl ⊢ 3 3 ⁢ A 3 − 1 ∈ ℚ ∧ 3 3 ⁢ A 2 + 3 2 ⁢ A + 3 ∈ ℚ ∧ 3 3 ⁢ A 2 + 3 2 ⁢ A + 3 ≠ 0 → 3 3 ⁢ A 3 − 1 3 3 ⁢ A 2 + 3 2 ⁢ A + 3 ∈ ℚ
35 17 30 33 34 syl3anc ⊢ A ∈ ℚ → 3 3 ⁢ A 3 − 1 3 3 ⁢ A 2 + 3 2 ⁢ A + 3 ∈ ℚ
36 qnegcl ⊢ 3 3 ⁢ A 3 ∈ ℚ → − 3 3 ⁢ A 3 ∈ ℚ
37 12 36 syl ⊢ A ∈ ℚ → − 3 3 ⁢ A 3 ∈ ℚ
38 qaddcl ⊢ − 3 3 ⁢ A 3 ∈ ℚ ∧ 3 2 ⁢ A ∈ ℚ → - 3 3 ⁢ A 3 + 3 2 ⁢ A ∈ ℚ
39 37 26 38 syl2anc ⊢ A ∈ ℚ → - 3 3 ⁢ A 3 + 3 2 ⁢ A ∈ ℚ
40 qaddcl ⊢ - 3 3 ⁢ A 3 + 3 2 ⁢ A ∈ ℚ ∧ 1 ∈ ℚ → − 3 3 ⁢ A 3 + 3 2 ⁢ A + 1 ∈ ℚ
41 39 15 40 sylancl ⊢ A ∈ ℚ → − 3 3 ⁢ A 3 + 3 2 ⁢ A + 1 ∈ ℚ
42 qdivcl ⊢ − 3 3 ⁢ A 3 + 3 2 ⁢ A + 1 ∈ ℚ ∧ 3 3 ⁢ A 2 + 3 2 ⁢ A + 3 ∈ ℚ ∧ 3 3 ⁢ A 2 + 3 2 ⁢ A + 3 ≠ 0 → − 3 3 ⁢ A 3 + 3 2 ⁢ A + 1 3 3 ⁢ A 2 + 3 2 ⁢ A + 3 ∈ ℚ
43 41 30 33 42 syl3anc ⊢ A ∈ ℚ → − 3 3 ⁢ A 3 + 3 2 ⁢ A + 1 3 3 ⁢ A 2 + 3 2 ⁢ A + 3 ∈ ℚ
44 qdivcl ⊢ 3 3 ⁢ A 2 + 3 2 ⁢ A ∈ ℚ ∧ 3 3 ⁢ A 2 + 3 2 ⁢ A + 3 ∈ ℚ ∧ 3 3 ⁢ A 2 + 3 2 ⁢ A + 3 ≠ 0 → 3 3 ⁢ A 2 + 3 2 ⁢ A 3 3 ⁢ A 2 + 3 2 ⁢ A + 3 ∈ ℚ
45 28 30 33 44 syl3anc ⊢ A ∈ ℚ → 3 3 ⁢ A 2 + 3 2 ⁢ A 3 3 ⁢ A 2 + 3 2 ⁢ A + 3 ∈ ℚ
46 31 3cubeslem4 ⊢ A ∈ ℚ → A = 3 3 ⁢ A 3 − 1 3 3 ⁢ A 2 + 3 2 ⁢ A + 3 3 + − 3 3 ⁢ A 3 + 3 2 ⁢ A + 1 3 3 ⁢ A 2 + 3 2 ⁢ A + 3 3 + 3 3 ⁢ A 2 + 3 2 ⁢ A 3 3 ⁢ A 2 + 3 2 ⁢ A + 3 3
47 oveq1 ⊢ a = 3 3 ⁢ A 3 − 1 3 3 ⁢ A 2 + 3 2 ⁢ A + 3 → a 3 = 3 3 ⁢ A 3 − 1 3 3 ⁢ A 2 + 3 2 ⁢ A + 3 3
48 47 oveq1d ⊢ a = 3 3 ⁢ A 3 − 1 3 3 ⁢ A 2 + 3 2 ⁢ A + 3 → a 3 + b 3 = 3 3 ⁢ A 3 − 1 3 3 ⁢ A 2 + 3 2 ⁢ A + 3 3 + b 3
49 48 oveq1d ⊢ a = 3 3 ⁢ A 3 − 1 3 3 ⁢ A 2 + 3 2 ⁢ A + 3 → a 3 + b 3 + c 3 = 3 3 ⁢ A 3 − 1 3 3 ⁢ A 2 + 3 2 ⁢ A + 3 3 + b 3 + c 3
50 49 eqeq2d ⊢ a = 3 3 ⁢ A 3 − 1 3 3 ⁢ A 2 + 3 2 ⁢ A + 3 → A = a 3 + b 3 + c 3 ↔ A = 3 3 ⁢ A 3 − 1 3 3 ⁢ A 2 + 3 2 ⁢ A + 3 3 + b 3 + c 3
51 oveq1 ⊢ b = − 3 3 ⁢ A 3 + 3 2 ⁢ A + 1 3 3 ⁢ A 2 + 3 2 ⁢ A + 3 → b 3 = − 3 3 ⁢ A 3 + 3 2 ⁢ A + 1 3 3 ⁢ A 2 + 3 2 ⁢ A + 3 3
52 51 oveq2d ⊢ b = − 3 3 ⁢ A 3 + 3 2 ⁢ A + 1 3 3 ⁢ A 2 + 3 2 ⁢ A + 3 → 3 3 ⁢ A 3 − 1 3 3 ⁢ A 2 + 3 2 ⁢ A + 3 3 + b 3 = 3 3 ⁢ A 3 − 1 3 3 ⁢ A 2 + 3 2 ⁢ A + 3 3 + − 3 3 ⁢ A 3 + 3 2 ⁢ A + 1 3 3 ⁢ A 2 + 3 2 ⁢ A + 3 3
53 52 oveq1d ⊢ b = − 3 3 ⁢ A 3 + 3 2 ⁢ A + 1 3 3 ⁢ A 2 + 3 2 ⁢ A + 3 → 3 3 ⁢ A 3 − 1 3 3 ⁢ A 2 + 3 2 ⁢ A + 3 3 + b 3 + c 3 = 3 3 ⁢ A 3 − 1 3 3 ⁢ A 2 + 3 2 ⁢ A + 3 3 + − 3 3 ⁢ A 3 + 3 2 ⁢ A + 1 3 3 ⁢ A 2 + 3 2 ⁢ A + 3 3 + c 3
54 53 eqeq2d ⊢ b = − 3 3 ⁢ A 3 + 3 2 ⁢ A + 1 3 3 ⁢ A 2 + 3 2 ⁢ A + 3 → A = 3 3 ⁢ A 3 − 1 3 3 ⁢ A 2 + 3 2 ⁢ A + 3 3 + b 3 + c 3 ↔ A = 3 3 ⁢ A 3 − 1 3 3 ⁢ A 2 + 3 2 ⁢ A + 3 3 + − 3 3 ⁢ A 3 + 3 2 ⁢ A + 1 3 3 ⁢ A 2 + 3 2 ⁢ A + 3 3 + c 3
55 oveq1 ⊢ c = 3 3 ⁢ A 2 + 3 2 ⁢ A 3 3 ⁢ A 2 + 3 2 ⁢ A + 3 → c 3 = 3 3 ⁢ A 2 + 3 2 ⁢ A 3 3 ⁢ A 2 + 3 2 ⁢ A + 3 3
56 55 oveq2d ⊢ c = 3 3 ⁢ A 2 + 3 2 ⁢ A 3 3 ⁢ A 2 + 3 2 ⁢ A + 3 → 3 3 ⁢ A 3 − 1 3 3 ⁢ A 2 + 3 2 ⁢ A + 3 3 + − 3 3 ⁢ A 3 + 3 2 ⁢ A + 1 3 3 ⁢ A 2 + 3 2 ⁢ A + 3 3 + c 3 = 3 3 ⁢ A 3 − 1 3 3 ⁢ A 2 + 3 2 ⁢ A + 3 3 + − 3 3 ⁢ A 3 + 3 2 ⁢ A + 1 3 3 ⁢ A 2 + 3 2 ⁢ A + 3 3 + 3 3 ⁢ A 2 + 3 2 ⁢ A 3 3 ⁢ A 2 + 3 2 ⁢ A + 3 3
57 56 eqeq2d ⊢ c = 3 3 ⁢ A 2 + 3 2 ⁢ A 3 3 ⁢ A 2 + 3 2 ⁢ A + 3 → A = 3 3 ⁢ A 3 − 1 3 3 ⁢ A 2 + 3 2 ⁢ A + 3 3 + − 3 3 ⁢ A 3 + 3 2 ⁢ A + 1 3 3 ⁢ A 2 + 3 2 ⁢ A + 3 3 + c 3 ↔ A = 3 3 ⁢ A 3 − 1 3 3 ⁢ A 2 + 3 2 ⁢ A + 3 3 + − 3 3 ⁢ A 3 + 3 2 ⁢ A + 1 3 3 ⁢ A 2 + 3 2 ⁢ A + 3 3 + 3 3 ⁢ A 2 + 3 2 ⁢ A 3 3 ⁢ A 2 + 3 2 ⁢ A + 3 3
58 50 54 57 rspc3ev ⊢ 3 3 ⁢ A 3 − 1 3 3 ⁢ A 2 + 3 2 ⁢ A + 3 ∈ ℚ ∧ − 3 3 ⁢ A 3 + 3 2 ⁢ A + 1 3 3 ⁢ A 2 + 3 2 ⁢ A + 3 ∈ ℚ ∧ 3 3 ⁢ A 2 + 3 2 ⁢ A 3 3 ⁢ A 2 + 3 2 ⁢ A + 3 ∈ ℚ ∧ A = 3 3 ⁢ A 3 − 1 3 3 ⁢ A 2 + 3 2 ⁢ A + 3 3 + − 3 3 ⁢ A 3 + 3 2 ⁢ A + 1 3 3 ⁢ A 2 + 3 2 ⁢ A + 3 3 + 3 3 ⁢ A 2 + 3 2 ⁢ A 3 3 ⁢ A 2 + 3 2 ⁢ A + 3 3 → ∃ a ∈ ℚ ∃ b ∈ ℚ ∃ c ∈ ℚ A = a 3 + b 3 + c 3
59 35 43 45 46 58 syl31anc ⊢ A ∈ ℚ → ∃ a ∈ ℚ ∃ b ∈ ℚ ∃ c ∈ ℚ A = a 3 + b 3 + c 3
60 3anass ⊢ a ∈ ℚ ∧ b ∈ ℚ ∧ c ∈ ℚ ↔ a ∈ ℚ ∧ b ∈ ℚ ∧ c ∈ ℚ
61 qexpcl ⊢ a ∈ ℚ ∧ 3 ∈ ℕ 0 → a 3 ∈ ℚ
62 3 61 mpan2 ⊢ a ∈ ℚ → a 3 ∈ ℚ
63 simprl ⊢ a ∈ ℚ ∧ b ∈ ℚ ∧ c ∈ ℚ → b ∈ ℚ
64 qexpcl ⊢ b ∈ ℚ ∧ 3 ∈ ℕ 0 → b 3 ∈ ℚ
65 63 3 64 sylancl ⊢ a ∈ ℚ ∧ b ∈ ℚ ∧ c ∈ ℚ → b 3 ∈ ℚ
66 qaddcl ⊢ a 3 ∈ ℚ ∧ b 3 ∈ ℚ → a 3 + b 3 ∈ ℚ
67 62 65 66 syl2an2r ⊢ a ∈ ℚ ∧ b ∈ ℚ ∧ c ∈ ℚ → a 3 + b 3 ∈ ℚ
68 simprr ⊢ a ∈ ℚ ∧ b ∈ ℚ ∧ c ∈ ℚ → c ∈ ℚ
69 qexpcl ⊢ c ∈ ℚ ∧ 3 ∈ ℕ 0 → c 3 ∈ ℚ
70 68 3 69 sylancl ⊢ a ∈ ℚ ∧ b ∈ ℚ ∧ c ∈ ℚ → c 3 ∈ ℚ
71 qaddcl ⊢ a 3 + b 3 ∈ ℚ ∧ c 3 ∈ ℚ → a 3 + b 3 + c 3 ∈ ℚ
72 67 70 71 syl2anc ⊢ a ∈ ℚ ∧ b ∈ ℚ ∧ c ∈ ℚ → a 3 + b 3 + c 3 ∈ ℚ
73 eleq1a ⊢ a 3 + b 3 + c 3 ∈ ℚ → A = a 3 + b 3 + c 3 → A ∈ ℚ
74 72 73 syl ⊢ a ∈ ℚ ∧ b ∈ ℚ ∧ c ∈ ℚ → A = a 3 + b 3 + c 3 → A ∈ ℚ
75 74 a1i ⊢ ⊤ → a ∈ ℚ ∧ b ∈ ℚ ∧ c ∈ ℚ → A = a 3 + b 3 + c 3 → A ∈ ℚ
76 60 75 biimtrid ⊢ ⊤ → a ∈ ℚ ∧ b ∈ ℚ ∧ c ∈ ℚ → A = a 3 + b 3 + c 3 → A ∈ ℚ
77 76 rexlimdv3d ⊢ ⊤ → ∃ a ∈ ℚ ∃ b ∈ ℚ ∃ c ∈ ℚ A = a 3 + b 3 + c 3 → A ∈ ℚ
78 77 mptru ⊢ ∃ a ∈ ℚ ∃ b ∈ ℚ ∃ c ∈ ℚ A = a 3 + b 3 + c 3 → A ∈ ℚ
79 59 78 impbii ⊢ A ∈ ℚ ↔ ∃ a ∈ ℚ ∃ b ∈ ℚ ∃ c ∈ ℚ A = a 3 + b 3 + c 3