Metamath Proof Explorer


Theorem asclmul2

Description: Right multiplication by a lifted scalar is the same as the scalar operation. (Contributed by Mario Carneiro, 9-Mar-2015)

Ref Expression
Hypotheses asclmul1.a ⊢ A = algSc ⁡ W
asclmul1.f ⊢ F = Scalar ⁡ W
asclmul1.k ⊢ K = Base F
asclmul1.v ⊢ V = Base W
asclmul1.t ⊢ × ˙ = ⋅ W
asclmul1.s ⊢ · ˙ = ⋅ W
Assertion asclmul2 ⊢ W ∈ AssAlg ∧ R ∈ K ∧ X ∈ V → X × ˙ A ⁡ R = R · ˙ X

Proof

Step Hyp Ref Expression
1 asclmul1.a ⊢ A = algSc ⁡ W
2 asclmul1.f ⊢ F = Scalar ⁡ W
3 asclmul1.k ⊢ K = Base F
4 asclmul1.v ⊢ V = Base W
5 asclmul1.t ⊢ × ˙ = ⋅ W
6 asclmul1.s ⊢ · ˙ = ⋅ W
7 eqid ⊢ 1 W = 1 W
8 1 2 3 6 7 asclval ⊢ R ∈ K → A ⁡ R = R · ˙ 1 W
9 8 3ad2ant2 ⊢ W ∈ AssAlg ∧ R ∈ K ∧ X ∈ V → A ⁡ R = R · ˙ 1 W
10 9 oveq2d ⊢ W ∈ AssAlg ∧ R ∈ K ∧ X ∈ V → X × ˙ A ⁡ R = X × ˙ R · ˙ 1 W
11 simp1 ⊢ W ∈ AssAlg ∧ R ∈ K ∧ X ∈ V → W ∈ AssAlg
12 simp2 ⊢ W ∈ AssAlg ∧ R ∈ K ∧ X ∈ V → R ∈ K
13 simp3 ⊢ W ∈ AssAlg ∧ R ∈ K ∧ X ∈ V → X ∈ V
14 assaring ⊢ W ∈ AssAlg → W ∈ Ring
15 14 3ad2ant1 ⊢ W ∈ AssAlg ∧ R ∈ K ∧ X ∈ V → W ∈ Ring
16 4 7 ringidcl ⊢ W ∈ Ring → 1 W ∈ V
17 15 16 syl ⊢ W ∈ AssAlg ∧ R ∈ K ∧ X ∈ V → 1 W ∈ V
18 4 2 3 6 5 assaassr ⊢ W ∈ AssAlg ∧ R ∈ K ∧ X ∈ V ∧ 1 W ∈ V → X × ˙ R · ˙ 1 W = R · ˙ X × ˙ 1 W
19 11 12 13 17 18 syl13anc ⊢ W ∈ AssAlg ∧ R ∈ K ∧ X ∈ V → X × ˙ R · ˙ 1 W = R · ˙ X × ˙ 1 W
20 4 5 7 ringridm ⊢ W ∈ Ring ∧ X ∈ V → X × ˙ 1 W = X
21 15 13 20 syl2anc ⊢ W ∈ AssAlg ∧ R ∈ K ∧ X ∈ V → X × ˙ 1 W = X
22 21 oveq2d ⊢ W ∈ AssAlg ∧ R ∈ K ∧ X ∈ V → R · ˙ X × ˙ 1 W = R · ˙ X
23 10 19 22 3eqtrd ⊢ W ∈ AssAlg ∧ R ∈ K ∧ X ∈ V → X × ˙ A ⁡ R = R · ˙ X