Metamath Proof Explorer


Theorem aspsubrg

Description: The algebraic span of a set of vectors is a subring of the algebra. (Contributed by Mario Carneiro, 7-Jan-2015)

Ref Expression
Hypotheses aspval.a ⊢ A = AlgSpan ⁡ W
aspval.v ⊢ V = Base W
Assertion aspsubrg ⊢ W ∈ AssAlg ∧ S ⊆ V → A ⁡ S ∈ SubRing ⁡ W

Proof

Step Hyp Ref Expression
1 aspval.a ⊢ A = AlgSpan ⁡ W
2 aspval.v ⊢ V = Base W
3 eqid ⊢ LSubSp ⁡ W = LSubSp ⁡ W
4 1 2 3 aspval ⊢ W ∈ AssAlg ∧ S ⊆ V → A ⁡ S = ⋂ t ∈ SubRing ⁡ W ∩ LSubSp ⁡ W | S ⊆ t
5 ssrab2 ⊢ t ∈ SubRing ⁡ W ∩ LSubSp ⁡ W | S ⊆ t ⊆ SubRing ⁡ W ∩ LSubSp ⁡ W
6 inss1 ⊢ SubRing ⁡ W ∩ LSubSp ⁡ W ⊆ SubRing ⁡ W
7 5 6 sstri ⊢ t ∈ SubRing ⁡ W ∩ LSubSp ⁡ W | S ⊆ t ⊆ SubRing ⁡ W
8 fvex ⊢ A ⁡ S ∈ V
9 4 8 eqeltrrdi ⊢ W ∈ AssAlg ∧ S ⊆ V → ⋂ t ∈ SubRing ⁡ W ∩ LSubSp ⁡ W | S ⊆ t ∈ V
10 intex ⊢ t ∈ SubRing ⁡ W ∩ LSubSp ⁡ W | S ⊆ t ≠ ∅ ↔ ⋂ t ∈ SubRing ⁡ W ∩ LSubSp ⁡ W | S ⊆ t ∈ V
11 9 10 sylibr ⊢ W ∈ AssAlg ∧ S ⊆ V → t ∈ SubRing ⁡ W ∩ LSubSp ⁡ W | S ⊆ t ≠ ∅
12 subrgint ⊢ t ∈ SubRing ⁡ W ∩ LSubSp ⁡ W | S ⊆ t ⊆ SubRing ⁡ W ∧ t ∈ SubRing ⁡ W ∩ LSubSp ⁡ W | S ⊆ t ≠ ∅ → ⋂ t ∈ SubRing ⁡ W ∩ LSubSp ⁡ W | S ⊆ t ∈ SubRing ⁡ W
13 7 11 12 sylancr ⊢ W ∈ AssAlg ∧ S ⊆ V → ⋂ t ∈ SubRing ⁡ W ∩ LSubSp ⁡ W | S ⊆ t ∈ SubRing ⁡ W
14 4 13 eqeltrd ⊢ W ∈ AssAlg ∧ S ⊆ V → A ⁡ S ∈ SubRing ⁡ W