Metamath Proof Explorer


Theorem conncn

Description: A continuous function from a connected topology with one point in a clopen set must lie entirely within the set. (Contributed by Mario Carneiro, 16-Feb-2015)

Ref Expression
Hypotheses conncn.x ⊢ X = ⋃ J
conncn.j ⊢ φ → J ∈ Conn
conncn.f ⊢ φ → F ∈ J Cn K
conncn.u ⊢ φ → U ∈ K
conncn.c ⊢ φ → U ∈ Clsd ⁡ K
conncn.a ⊢ φ → A ∈ X
conncn.1 ⊢ φ → F ⁡ A ∈ U
Assertion conncn ⊢ φ → F : X ⟶ U

Proof

Step Hyp Ref Expression
1 conncn.x ⊢ X = ⋃ J
2 conncn.j ⊢ φ → J ∈ Conn
3 conncn.f ⊢ φ → F ∈ J Cn K
4 conncn.u ⊢ φ → U ∈ K
5 conncn.c ⊢ φ → U ∈ Clsd ⁡ K
6 conncn.a ⊢ φ → A ∈ X
7 conncn.1 ⊢ φ → F ⁡ A ∈ U
8 eqid ⊢ ⋃ K = ⋃ K
9 1 8 cnf ⊢ F ∈ J Cn K → F : X ⟶ ⋃ K
10 3 9 syl ⊢ φ → F : X ⟶ ⋃ K
11 10 ffnd ⊢ φ → F Fn X
12 10 frnd ⊢ φ → ran ⁡ F ⊆ ⋃ K
13 dffn4 ⊢ F Fn X ↔ F : X ⟶ onto ran ⁡ F
14 11 13 sylib ⊢ φ → F : X ⟶ onto ran ⁡ F
15 cntop2 ⊢ F ∈ J Cn K → K ∈ Top
16 3 15 syl ⊢ φ → K ∈ Top
17 8 restuni ⊢ K ∈ Top ∧ ran ⁡ F ⊆ ⋃ K → ran ⁡ F = ⋃ K ↾ 𝑡 ran ⁡ F
18 16 12 17 syl2anc ⊢ φ → ran ⁡ F = ⋃ K ↾ 𝑡 ran ⁡ F
19 foeq3 ⊢ ran ⁡ F = ⋃ K ↾ 𝑡 ran ⁡ F → F : X ⟶ onto ran ⁡ F ↔ F : X ⟶ onto ⋃ K ↾ 𝑡 ran ⁡ F
20 18 19 syl ⊢ φ → F : X ⟶ onto ran ⁡ F ↔ F : X ⟶ onto ⋃ K ↾ 𝑡 ran ⁡ F
21 14 20 mpbid ⊢ φ → F : X ⟶ onto ⋃ K ↾ 𝑡 ran ⁡ F
22 toptopon2 ⊢ K ∈ Top ↔ K ∈ TopOn ⁡ ⋃ K
23 16 22 sylib ⊢ φ → K ∈ TopOn ⁡ ⋃ K
24 ssidd ⊢ φ → ran ⁡ F ⊆ ran ⁡ F
25 cnrest2 ⊢ K ∈ TopOn ⁡ ⋃ K ∧ ran ⁡ F ⊆ ran ⁡ F ∧ ran ⁡ F ⊆ ⋃ K → F ∈ J Cn K ↔ F ∈ J Cn K ↾ 𝑡 ran ⁡ F
26 23 24 12 25 syl3anc ⊢ φ → F ∈ J Cn K ↔ F ∈ J Cn K ↾ 𝑡 ran ⁡ F
27 3 26 mpbid ⊢ φ → F ∈ J Cn K ↾ 𝑡 ran ⁡ F
28 eqid ⊢ ⋃ K ↾ 𝑡 ran ⁡ F = ⋃ K ↾ 𝑡 ran ⁡ F
29 28 cnconn ⊢ J ∈ Conn ∧ F : X ⟶ onto ⋃ K ↾ 𝑡 ran ⁡ F ∧ F ∈ J Cn K ↾ 𝑡 ran ⁡ F → K ↾ 𝑡 ran ⁡ F ∈ Conn
30 2 21 27 29 syl3anc ⊢ φ → K ↾ 𝑡 ran ⁡ F ∈ Conn
31 fnfvelrn ⊢ F Fn X ∧ A ∈ X → F ⁡ A ∈ ran ⁡ F
32 11 6 31 syl2anc ⊢ φ → F ⁡ A ∈ ran ⁡ F
33 inelcm ⊢ F ⁡ A ∈ U ∧ F ⁡ A ∈ ran ⁡ F → U ∩ ran ⁡ F ≠ ∅
34 7 32 33 syl2anc ⊢ φ → U ∩ ran ⁡ F ≠ ∅
35 8 12 30 4 34 5 connsubclo ⊢ φ → ran ⁡ F ⊆ U
36 df-f ⊢ F : X ⟶ U ↔ F Fn X ∧ ran ⁡ F ⊆ U
37 11 35 36 sylanbrc ⊢ φ → F : X ⟶ U